leetcode-problemset/leetcode-cn/originData/double-a-number-represented-as-a-linked-list.json

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        "question": {
            "questionId": "2871",
            "questionFrontendId": "2816",
            "categoryTitle": "Algorithms",
            "boundTopicId": 2383695,
            "title": "Double a Number Represented as a Linked List",
            "titleSlug": "double-a-number-represented-as-a-linked-list",
            "content": "<p>You are given the <code>head</code> of a <strong>non-empty</strong> linked list representing a non-negative integer without leading zeroes.</p>\n\n<p>Return <em>the </em><code>head</code><em> of the linked list after <strong>doubling</strong> it</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2023/05/28/example.png\" style=\"width: 401px; height: 81px;\" />\n<pre>\n<strong>Input:</strong> head = [1,8,9]\n<strong>Output:</strong> [3,7,8]\n<strong>Explanation:</strong> The figure above corresponds to the given linked list which represents the number 189. Hence, the returned linked list represents the number 189 * 2 = 378.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2023/05/28/example2.png\" style=\"width: 401px; height: 81px;\" />\n<pre>\n<strong>Input:</strong> head = [9,9,9]\n<strong>Output:</strong> [1,9,9,8]\n<strong>Explanation:</strong> The figure above corresponds to the given linked list which represents the number 999. Hence, the returned linked list reprersents the number 999 * 2 = 1998. \n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li>The number of nodes in the list is in the range <code>[1, 10<sup>4</sup>]</code></li>\n\t<li><font face=\"monospace\"><code>0 &lt;= Node.val &lt;= 9</code></font></li>\n\t<li>The input is generated such that the list represents a number that does not have leading zeros, except the number <code>0</code> itself.</li>\n</ul>\n",
            "translatedTitle": "翻倍以链表形式表示的数字",
            "translatedContent": "<p>给你一个 <strong>非空</strong> 链表的头节点 <code>head</code> ，表示一个不含前导零的非负数整数。</p>\n\n<p>将链表 <strong>翻倍</strong> 后，返回头节点<em> </em><code>head</code><em> </em>。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2023/05/28/example.png\" style=\"width: 401px; height: 81px;\" />\n<pre>\n<strong>输入：</strong>head = [1,8,9]\n<strong>输出：</strong>[3,7,8]\n<strong>解释：</strong>上图中给出的链表，表示数字 189 。返回的链表表示数字 189 * 2 = 378 。</pre>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2023/05/28/example2.png\" style=\"width: 401px; height: 81px;\" />\n<pre>\n<strong>输入：</strong>head = [9,9,9]\n<strong>输出：</strong>[1,9,9,8]\n<strong>解释：</strong>上图中给出的链表，表示数字 999 。返回的链表表示数字 999 * 2 = 1998 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li>链表中节点的数目在范围 <code>[1, 10<sup>4</sup>]</code> 内</li>\n\t<li><font face=\"monospace\"><code>0 &lt;= Node.val &lt;= 9</code></font></li>\n\t<li>生成的输入满足：链表表示一个不含前导零的数字，除了数字 <code>0</code> 本身。</li>\n</ul>\n",
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                    "code": "/**\n * Definition for singly-linked list.\n * struct ListNode {\n *     int val;\n *     ListNode *next;\n *     ListNode() : val(0), next(nullptr) {}\n *     ListNode(int x) : val(x), next(nullptr) {}\n *     ListNode(int x, ListNode *next) : val(x), next(next) {}\n * };\n */\nclass Solution {\npublic:\n    ListNode* doubleIt(ListNode* head) {\n        \n    }\n};",
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                    "code": "/**\n * Definition for singly-linked list.\n * public class ListNode {\n *     int val;\n *     ListNode next;\n *     ListNode() {}\n *     ListNode(int val) { this.val = val; }\n *     ListNode(int val, ListNode next) { this.val = val; this.next = next; }\n * }\n */\nclass Solution {\n    public ListNode doubleIt(ListNode head) {\n\n    }\n}",
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                    "code": "# Definition for singly-linked list.\n# class ListNode(object):\n#     def __init__(self, val=0, next=None):\n#         self.val = val\n#         self.next = next\nclass Solution(object):\n    def doubleIt(self, head):\n        \"\"\"\n        :type head: Optional[ListNode]\n        :rtype: Optional[ListNode]\n        \"\"\"",
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                    "code": "/**\n * Definition for singly-linked list.\n * public class ListNode {\n *     public int val;\n *     public ListNode next;\n *     public ListNode(int val=0, ListNode next=null) {\n *         this.val = val;\n *         this.next = next;\n *     }\n * }\n */\npublic class Solution {\n    public ListNode DoubleIt(ListNode head) {\n\n    }\n}",
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                    "code": "/**\n * Definition for singly-linked list.\n * function ListNode(val, next) {\n *     this.val = (val===undefined ? 0 : val)\n *     this.next = (next===undefined ? null : next)\n * }\n */\n/**\n * @param {ListNode} head\n * @return {ListNode}\n */\nvar doubleIt = function(head) {\n\n};",
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                    "code": "/**\n * Definition for singly-linked list.\n * class ListNode {\n *     val: number\n *     next: ListNode | null\n *     constructor(val?: number, next?: ListNode | null) {\n *         this.val = (val===undefined ? 0 : val)\n *         this.next = (next===undefined ? null : next)\n *     }\n * }\n */\n\nfunction doubleIt(head: ListNode | null): ListNode | null {\n\n};",
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                    "code": "/**\n * Definition for a singly-linked list.\n * class ListNode {\n *     public $val = 0;\n *     public $next = null;\n *     function __construct($val = 0, $next = null) {\n *         $this->val = $val;\n *         $this->next = $next;\n *     }\n * }\n */\nclass Solution {\n\n    /**\n     * @param ListNode $head\n     * @return ListNode\n     */\n    function doubleIt($head) {\n\n    }\n}",
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                    "code": "/**\n * Definition for singly-linked list.\n * type ListNode struct {\n *     Val int\n *     Next *ListNode\n * }\n */\nfunc doubleIt(head *ListNode) *ListNode {\n\n}",
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                    "code": "# Definition for singly-linked list.\n# class ListNode\n#     attr_accessor :val, :next\n#     def initialize(val = 0, _next = nil)\n#         @val = val\n#         @next = _next\n#     end\n# end\n# @param {ListNode} head\n# @return {ListNode}\ndef double_it(head)\n\nend",
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                    "code": "/**\n * Definition for singly-linked list.\n * class ListNode(_x: Int = 0, _next: ListNode = null) {\n *   var next: ListNode = _next\n *   var x: Int = _x\n * }\n */\nobject Solution {\n    def doubleIt(head: ListNode): ListNode = {\n\n    }\n}",
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                    "code": "// Definition for singly-linked list.\n// #[derive(PartialEq, Eq, Clone, Debug)]\n// pub struct ListNode {\n//   pub val: i32,\n//   pub next: Option<Box<ListNode>>\n// }\n//\n// impl ListNode {\n//   #[inline]\n//   fn new(val: i32) -> Self {\n//     ListNode {\n//       next: None,\n//       val\n//     }\n//   }\n// }\nimpl Solution {\n    pub fn double_it(head: Option<Box<ListNode>>) -> Option<Box<ListNode>> {\n\n    }\n}",
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                    "lang": "Racket",
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                    "code": "; Definition for singly-linked list:\n#|\n\n; val : integer?\n; next : (or/c list-node? #f)\n(struct list-node\n  (val next) #:mutable #:transparent)\n\n; constructor\n(define (make-list-node [val 0])\n  (list-node val #f))\n\n|#\n\n(define/contract (double-it head)\n  (-> (or/c list-node? #f) (or/c list-node? #f))\n\n  )",
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                    "code": "%% Definition for singly-linked list.\n%%\n%% -record(list_node, {val = 0 :: integer(),\n%%                     next = null :: 'null' | #list_node{}}).\n\n-spec double_it(Head :: #list_node{} | null) -> #list_node{} | null.\ndouble_it(Head) ->\n  .",
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                    "code": "# Definition for singly-linked list.\n#\n# defmodule ListNode do\n#   @type t :: %__MODULE__{\n#           val: integer,\n#           next: ListNode.t() | nil\n#         }\n#   defstruct val: 0, next: nil\n# end\n\ndefmodule Solution do\n  @spec double_it(head :: ListNode.t | nil) :: ListNode.t | nil\n  def double_it(head) do\n\n  end\nend",
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            "hints": [
                "Traverse the linked list from the least significant digit to the most significant digit and multiply each node's value by 2",
                "Handle any carry-over digits that may arise during the doubling process.",
                "If there is a carry-over digit on the most significant digit, create a new node with that value and point it to the start of the given linked list and return it."
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