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"question": {
"questionId": "2015",
"questionFrontendId": "1886",
"categoryTitle": "Algorithms",
"boundTopicId": 811621,
"title": "Determine Whether Matrix Can Be Obtained By Rotation",
"titleSlug": "determine-whether-matrix-can-be-obtained-by-rotation",
"content": "<p>Given two <code>n x n</code> binary matrices <code>mat</code> and <code>target</code>, return <code>true</code><em> if it is possible to make </em><code>mat</code><em> equal to </em><code>target</code><em> by <strong>rotating</strong> </em><code>mat</code><em> in <strong>90-degree increments</strong>, or </em><code>false</code><em> otherwise.</em></p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/05/20/grid3.png\" style=\"width: 301px; height: 121px;\" />\n<pre>\n<strong>Input:</strong> mat = [[0,1],[1,0]], target = [[1,0],[0,1]]\n<strong>Output:</strong> true\n<strong>Explanation: </strong>We can rotate mat 90 degrees clockwise to make mat equal target.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/05/20/grid4.png\" style=\"width: 301px; height: 121px;\" />\n<pre>\n<strong>Input:</strong> mat = [[0,1],[1,1]], target = [[1,0],[0,1]]\n<strong>Output:</strong> false\n<strong>Explanation:</strong> It is impossible to make mat equal to target by rotating mat.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/05/26/grid4.png\" style=\"width: 661px; height: 184px;\" />\n<pre>\n<strong>Input:</strong> mat = [[0,0,0],[0,1,0],[1,1,1]], target = [[1,1,1],[0,1,0],[0,0,0]]\n<strong>Output:</strong> true\n<strong>Explanation: </strong>We can rotate mat 90 degrees clockwise two times to make mat equal target.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == mat.length == target.length</code></li>\n\t<li><code>n == mat[i].length == target[i].length</code></li>\n\t<li><code>1 &lt;= n &lt;= 10</code></li>\n\t<li><code>mat[i][j]</code> and <code>target[i][j]</code> are either <code>0</code> or <code>1</code>.</li>\n</ul>\n",
"translatedTitle": "判断矩阵经轮转后是否一致",
"translatedContent": "<p>给你两个大小为 <code>n x n</code> 的二进制矩阵 <code>mat</code> 和 <code>target</code> 。现<strong> 以 90 度顺时针轮转 </strong>矩阵 <code>mat</code> 中的元素 <strong>若干次</strong> ,如果能够使 <code>mat</code> 与 <code>target</code> 一致,返回 <code>true</code> ;否则,返回<em> </em><code>false</code><em> 。</em></p>\n\n<p> </p>\n\n<p><strong>示例 1</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/05/20/grid3.png\" style=\"width: 301px; height: 121px;\" />\n<pre>\n<strong>输入:</strong>mat = [[0,1],[1,0]], target = [[1,0],[0,1]]\n<strong>输出:</strong>true\n<strong>解释:</strong>顺时针轮转 90 度一次可以使 mat 和 target 一致。\n</pre>\n\n<p><strong>示例 2</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/05/20/grid4.png\" style=\"width: 301px; height: 121px;\" />\n<pre>\n<strong>输入:</strong>mat = [[0,1],[1,1]], target = [[1,0],[0,1]]\n<strong>输出:</strong>false\n<strong>解释:</strong>无法通过轮转矩阵中的元素使 equal 与 target 一致。\n</pre>\n\n<p><strong>示例 3</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/05/26/grid4.png\" style=\"width: 661px; height: 184px;\" />\n<pre>\n<strong>输入:</strong>mat = [[0,0,0],[0,1,0],[1,1,1]], target = [[1,1,1],[0,1,0],[0,0,0]]\n<strong>输出:</strong>true\n<strong>解释:</strong>顺时针轮转 90 度两次可以使 mat 和 target 一致。\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>n == mat.length == target.length</code></li>\n\t<li><code>n == mat[i].length == target[i].length</code></li>\n\t<li><code>1 <= n <= 10</code></li>\n\t<li><code>mat[i][j]</code> 和 <code>target[i][j]</code> 不是 <code>0</code> 就是 <code>1</code></li>\n</ul>\n",
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