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"question": {
"questionId": "1777",
"questionFrontendId": "1657",
"categoryTitle": "Algorithms",
"boundTopicId": 482731,
"title": "Determine if Two Strings Are Close",
"titleSlug": "determine-if-two-strings-are-close",
"content": "<p>Two strings are considered <strong>close</strong> if you can attain one from the other using the following operations:</p>\n\n<ul>\n\t<li>Operation 1: Swap any two <strong>existing</strong> characters.\n\n\t<ul>\n\t\t<li>For example, <code>a<u>b</u>cd<u>e</u> -&gt; a<u>e</u>cd<u>b</u></code></li>\n\t</ul>\n\t</li>\n\t<li>Operation 2: Transform <strong>every</strong> occurrence of one <strong>existing</strong> character into another <strong>existing</strong> character, and do the same with the other character.\n\t<ul>\n\t\t<li>For example, <code><u>aa</u>c<u>abb</u> -&gt; <u>bb</u>c<u>baa</u></code> (all <code>a</code>&#39;s turn into <code>b</code>&#39;s, and all <code>b</code>&#39;s turn into <code>a</code>&#39;s)</li>\n\t</ul>\n\t</li>\n</ul>\n\n<p>You can use the operations on either string as many times as necessary.</p>\n\n<p>Given two strings, <code>word1</code> and <code>word2</code>, return <code>true</code><em> if </em><code>word1</code><em> and </em><code>word2</code><em> are <strong>close</strong>, and </em><code>false</code><em> otherwise.</em></p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> word1 = &quot;abc&quot;, word2 = &quot;bca&quot;\n<strong>Output:</strong> true\n<strong>Explanation:</strong> You can attain word2 from word1 in 2 operations.\nApply Operation 1: &quot;a<u>bc</u>&quot; -&gt; &quot;a<u>cb</u>&quot;\nApply Operation 1: &quot;<u>a</u>c<u>b</u>&quot; -&gt; &quot;<u>b</u>c<u>a</u>&quot;\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> word1 = &quot;a&quot;, word2 = &quot;aa&quot;\n<strong>Output:</strong> false\n<strong>Explanation: </strong>It is impossible to attain word2 from word1, or vice versa, in any number of operations.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> word1 = &quot;cabbba&quot;, word2 = &quot;abbccc&quot;\n<strong>Output:</strong> true\n<strong>Explanation:</strong> You can attain word2 from word1 in 3 operations.\nApply Operation 1: &quot;ca<u>b</u>bb<u>a</u>&quot; -&gt; &quot;ca<u>a</u>bb<u>b</u>&quot;\n<code>Apply Operation 2: &quot;</code><u>c</u>aa<u>bbb</u>&quot; -&gt; &quot;<u>b</u>aa<u>ccc</u>&quot;\nApply Operation 2: &quot;<u>baa</u>ccc&quot; -&gt; &quot;<u>abb</u>ccc&quot;\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= word1.length, word2.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>word1</code> and <code>word2</code> contain only lowercase English letters.</li>\n</ul>\n",
"translatedTitle": "确定两个字符串是否接近",
"translatedContent": "<p>如果可以使用以下操作从一个字符串得到另一个字符串,则认为两个字符串 <strong>接近</strong> </p>\n\n<ul>\n\t<li>操作 1交换任意两个 <strong>现有</strong> 字符。\n\n\t<ul>\n\t\t<li>例如,<code>a<strong>b</strong>cd<strong>e</strong> -> a<strong>e</strong>cd<strong>b</strong></code></li>\n\t</ul>\n\t</li>\n\t<li>操作 2将一个 <strong>现有</strong> 字符的每次出现转换为另一个 <strong>现有</strong> 字符,并对另一个字符执行相同的操作。\n\t<ul>\n\t\t<li>例如,<code><strong>aa</strong>c<strong>abb</strong> -> <strong>bb</strong>c<strong>baa</strong></code>(所有 <code>a</code> 转化为 <code>b</code> ,而所有的 <code>b</code> 转换为 <code>a</code> </li>\n\t</ul>\n\t</li>\n</ul>\n\n<p>你可以根据需要对任意一个字符串多次使用这两种操作。</p>\n\n<p>给你两个字符串,<code>word1</code> 和 <code>word2</code> 。如果<em> </em><code>word1</code><em> </em>和<em> </em><code>word2</code><em> </em><strong>接近 </strong>,就返回 <code>true</code> ;否则,返回<em> </em><code>false</code><em> </em>。</p>\n\n<p> </p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>word1 = \"abc\", word2 = \"bca\"\n<strong>输出:</strong>true\n<strong>解释:</strong>2 次操作从 word1 获得 word2 。\n执行操作 1\"a<strong>bc</strong>\" -> \"a<strong>cb</strong>\"\n执行操作 1\"<strong>a</strong>c<strong>b</strong>\" -> \"<strong>b</strong>c<strong>a</strong>\"\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>word1 = \"a\", word2 = \"aa\"\n<strong>输出:</strong>false\n<strong>解释:</strong>不管执行多少次操作,都无法从 word1 得到 word2 ,反之亦然。</pre>\n\n<p><strong>示例 3</strong></p>\n\n<pre>\n<strong>输入:</strong>word1 = \"cabbba\", word2 = \"abbccc\"\n<strong>输出:</strong>true\n<strong>解释:</strong>3 次操作从 word1 获得 word2 。\n执行操作 1\"ca<strong>b</strong>bb<strong>a</strong>\" -> \"ca<strong>a</strong>bb<strong>b</strong>\"\n执行操作 2<code>\"</code><strong>c</strong>aa<strong>bbb</strong>\" -> \"<strong>b</strong>aa<strong>ccc</strong>\"\n执行操作 2\"<strong>baa</strong>ccc\" -> \"<strong>abb</strong>ccc\"\n</pre>\n\n<p><strong>示例 4</strong></p>\n\n<pre>\n<strong>输入:</strong>word1 = \"cabbba\", word2 = \"aabbss\"\n<strong>输出:</strong>false\n<strong>解释:</strong>不管执行多少次操作,都无法从 word1 得到 word2 ,反之亦然。</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 <= word1.length, word2.length <= 10<sup>5</sup></code></li>\n\t<li><code>word1</code> 和 <code>word2</code> 仅包含小写英文字母</li>\n</ul>\n",
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