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"question": {
"questionId": "1434",
"questionFrontendId": "1309",
"categoryTitle": "Algorithms",
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"title": "Decrypt String from Alphabet to Integer Mapping",
"titleSlug": "decrypt-string-from-alphabet-to-integer-mapping",
"content": "<p>You are given a string <code>s</code> formed by digits and <code>&#39;#&#39;</code>. We want to map <code>s</code> to English lowercase characters as follows:</p>\n\n<ul>\n\t<li>Characters (<code>&#39;a&#39;</code> to <code>&#39;i&#39;</code>) are represented by (<code>&#39;1&#39;</code> to <code>&#39;9&#39;</code>) respectively.</li>\n\t<li>Characters (<code>&#39;j&#39;</code> to <code>&#39;z&#39;</code>) are represented by (<code>&#39;10#&#39;</code> to <code>&#39;26#&#39;</code>) respectively.</li>\n</ul>\n\n<p>Return <em>the string formed after mapping</em>.</p>\n\n<p>The test cases are generated so that a unique mapping will always exist.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;10#11#12&quot;\n<strong>Output:</strong> &quot;jkab&quot;\n<strong>Explanation:</strong> &quot;j&quot; -&gt; &quot;10#&quot; , &quot;k&quot; -&gt; &quot;11#&quot; , &quot;a&quot; -&gt; &quot;1&quot; , &quot;b&quot; -&gt; &quot;2&quot;.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;1326#&quot;\n<strong>Output:</strong> &quot;acz&quot;\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 1000</code></li>\n\t<li><code>s</code> consists of digits and the <code>&#39;#&#39;</code> letter.</li>\n\t<li><code>s</code> will be a valid string such that mapping is always possible.</li>\n</ul>\n",
"translatedTitle": "解码字母到整数映射",
"translatedContent": "<p>给你一个字符串&nbsp;<code>s</code>,它由数字(<code>'0'</code> - <code>'9'</code>)和&nbsp;<code>'#'</code>&nbsp;组成。我们希望按下述规则将&nbsp;<code>s</code>&nbsp;映射为一些小写英文字符:</p>\n\n<ul>\n\t<li>字符(<code>'a'</code> - <code>'i'</code>)分别用(<code>'1'</code> -&nbsp;<code>'9'</code>)表示。</li>\n\t<li>字符(<code>'j'</code> - <code>'z'</code>)分别用(<code>'10#'</code>&nbsp;-&nbsp;<code>'26#'</code>)表示。&nbsp;</li>\n</ul>\n\n<p>返回映射之后形成的新字符串。</p>\n\n<p>题目数据保证映射始终唯一。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>s = \"10#11#12\"\n<strong>输出:</strong>\"jkab\"\n<strong>解释:</strong>\"j\" -&gt; \"10#\" , \"k\" -&gt; \"11#\" , \"a\" -&gt; \"1\" , \"b\" -&gt; \"2\".\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>s = \"1326#\"\n<strong>输出:</strong>\"acz\"\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 1000</code></li>\n\t<li><code>s[i]</code> 只包含数字(<code>'0'</code>-<code>'9'</code>)和&nbsp;<code>'#'</code>&nbsp;字符。</li>\n\t<li><code>s</code>&nbsp;是映射始终存在的有效字符串。</li>\n</ul>\n",
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