leetcode-problemset/leetcode-cn/originData/cuyjEf.json

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        "question": {
            "questionId": "1000335",
            "questionFrontendId": "LCR 071",
            "categoryTitle": "Algorithms",
            "boundTopicId": 910329,
            "title": "按权重随机选择",
            "titleSlug": "cuyjEf",
            "content": "<p>English description is not available for the problem. Please switch to Chinese.</p>\n",
            "translatedTitle": "按权重随机选择",
            "translatedContent": "<p>给定一个正整数数组&nbsp;<code>w</code> ，其中&nbsp;<code>w[i]</code>&nbsp;代表下标 <code>i</code>&nbsp;的权重（下标从 <code>0</code> 开始），请写一个函数&nbsp;<code>pickIndex</code>&nbsp;，它可以随机地获取下标 <code>i</code>，选取下标 <code>i</code>&nbsp;的概率与&nbsp;<code>w[i]</code>&nbsp;成正比。</p>\n\n<ol>\n</ol>\n\n<p>例如，对于 <code>w = [1, 3]</code>，挑选下标 <code>0</code> 的概率为 <code>1 / (1 + 3)&nbsp;= 0.25</code> （即，25%），而选取下标 <code>1</code> 的概率为 <code>3 / (1 + 3)&nbsp;= 0.75</code>（即，75%）。</p>\n\n<p>也就是说，选取下标 <code>i</code> 的概率为 <code>w[i] / sum(w)</code> 。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>\ninputs = [&quot;Solution&quot;,&quot;pickIndex&quot;]\ninputs = [[[1]],[]]\n<strong>输出：</strong>\n[null,0]\n<strong>解释：</strong>\nSolution solution = new Solution([1]);\nsolution.pickIndex(); // 返回 0，因为数组中只有一个元素，所以唯一的选择是返回下标 0。</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>\ninputs = [&quot;Solution&quot;,&quot;pickIndex&quot;,&quot;pickIndex&quot;,&quot;pickIndex&quot;,&quot;pickIndex&quot;,&quot;pickIndex&quot;]\ninputs = [[[1,3]],[],[],[],[],[]]\n<strong>输出：</strong>\n[null,1,1,1,1,0]\n<strong>解释：</strong>\nSolution solution = new Solution([1, 3]);\nsolution.pickIndex(); // 返回 1，返回下标 1，返回该下标概率为 3/4 。\nsolution.pickIndex(); // 返回 1\nsolution.pickIndex(); // 返回 1\nsolution.pickIndex(); // 返回 1\nsolution.pickIndex(); // 返回 0，返回下标 0，返回该下标概率为 1/4 。\n\n由于这是一个随机问题，允许多个答案，因此下列输出都可以被认为是正确的:\n[null,1,1,1,1,0]\n[null,1,1,1,1,1]\n[null,1,1,1,0,0]\n[null,1,1,1,0,1]\n[null,1,0,1,0,0]\n......\n诸若此类。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= w.length &lt;= 10000</code></li>\n\t<li><code>1 &lt;= w[i] &lt;= 10^5</code></li>\n\t<li><code>pickIndex</code>&nbsp;将被调用不超过&nbsp;<code>10000</code>&nbsp;次</li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><meta charset=\"UTF-8\" />注意：本题与主站 528&nbsp;题相同：&nbsp;<a href=\"https://leetcode-cn.com/problems/random-pick-with-weight/\">https://leetcode-cn.com/problems/random-pick-with-weight/</a></p>\n",
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                    "code": "class Solution {\npublic:\n    Solution(vector<int>& w) {\n\n    }\n    \n    int pickIndex() {\n\n    }\n};\n\n/**\n * Your Solution object will be instantiated and called as such:\n * Solution* obj = new Solution(w);\n * int param_1 = obj->pickIndex();\n */",
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                    "code": "class Solution:\n\n    def __init__(self, w: List[int]):\n\n\n    def pickIndex(self) -> int:\n\n\n\n# Your Solution object will be instantiated and called as such:\n# obj = Solution(w)\n# param_1 = obj.pickIndex()",
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                    "code": "public class Solution {\n\n    public Solution(int[] w) {\n\n    }\n    \n    public int PickIndex() {\n\n    }\n}\n\n/**\n * Your Solution object will be instantiated and called as such:\n * Solution obj = new Solution(w);\n * int param_1 = obj.PickIndex();\n */",
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                    "code": "type Solution struct {\n\n}\n\n\nfunc Constructor(w []int) Solution {\n\n}\n\n\nfunc (this *Solution) PickIndex() int {\n\n}\n\n\n/**\n * Your Solution object will be instantiated and called as such:\n * obj := Constructor(w);\n * param_1 := obj.PickIndex();\n */",
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