leetcode-problemset/leetcode-cn/originData/create-components-with-same-value.json

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            "title": "Create Components With Same Value",
            "titleSlug": "create-components-with-same-value",
            "content": "<p>There is an undirected tree with <code>n</code> nodes labeled from <code>0</code> to <code>n - 1</code>.</p>\n\n<p>You are given a <strong>0-indexed</strong> integer array <code><font face=\"monospace\">nums</font></code> of length <code>n</code> where <code>nums[i]</code> represents the value of the <code>i<sup>th</sup></code> node. You are also given a 2D integer array <code>edges</code> of length <code>n - 1</code> where <code>edges[i] = [a<sub>i</sub>, b<sub>i</sub>]</code> indicates that there is an edge between nodes <code>a<sub>i</sub></code> and <code>b<sub>i</sub></code> in the tree.</p>\n\n<p>You are allowed to <strong>delete</strong> some edges, splitting the tree into multiple connected components. Let the <strong>value</strong> of a component be the sum of <strong>all</strong> <code>nums[i]</code> for which node <code>i</code> is in the component.</p>\n\n<p>Return<em> the <strong>maximum</strong> number of edges you can delete, such that every connected component in the tree has the same value.</em></p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2022/08/26/diagramdrawio.png\" style=\"width: 441px; height: 351px;\" />\n<pre>\n<strong>Input:</strong> nums = [6,2,2,2,6], edges = [[0,1],[1,2],[1,3],[3,4]] \n<strong>Output:</strong> 2 \n<strong>Explanation:</strong> The above figure shows how we can delete the edges [0,1] and [3,4]. The created components are nodes [0], [1,2,3] and [4]. The sum of the values in each component equals 6. It can be proven that no better deletion exists, so the answer is 2.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [2], edges = []\n<strong>Output:</strong> 0\n<strong>Explanation:</strong> There are no edges to be deleted.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 2 * 10<sup>4</sup></code></li>\n\t<li><code>nums.length == n</code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 50</code></li>\n\t<li><code>edges.length == n - 1</code></li>\n\t<li><code>edges[i].length == 2</code></li>\n\t<li><code>0 &lt;= edges[i][0], edges[i][1] &lt;= n - 1</code></li>\n\t<li><code>edges</code> represents a valid tree.</li>\n</ul>\n",
            "translatedTitle": "创建价值相同的连通块",
            "translatedContent": "<p>有一棵&nbsp;<code>n</code>&nbsp;个节点的无向树，节点编号为&nbsp;<code>0</code>&nbsp;到&nbsp;<code>n - 1</code>&nbsp;。</p>\n\n<p>给你一个长度为 <code>n</code>&nbsp;下标从 <strong>0</strong>&nbsp;开始的整数数组&nbsp;<code>nums</code>&nbsp;，其中&nbsp;<code>nums[i]</code>&nbsp;表示第&nbsp;<code>i</code>&nbsp;个节点的值。同时给你一个长度为 <code>n - 1</code>&nbsp;的二维整数数组&nbsp;<code>edges</code>&nbsp;，其中&nbsp;<code>edges[i] = [a<sub>i</sub>, b<sub>i</sub>]</code>&nbsp;表示节点&nbsp;<code>a<sub>i</sub></code>&nbsp;与&nbsp;<code>b<sub>i</sub></code>&nbsp;之间有一条边。</p>\n\n<p>你可以 <strong>删除</strong>&nbsp;一些边，将这棵树分成几个连通块。一个连通块的 <strong>价值</strong>&nbsp;定义为这个连通块中 <strong>所有</strong> 节点 <code>i</code>&nbsp;对应的 <code>nums[i]</code>&nbsp;之和。</p>\n\n<p>你需要删除一些边，删除后得到的各个连通块的价值都相等。请返回你可以删除的边数&nbsp;<strong>最多</strong>&nbsp;为多少。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2022/08/26/diagramdrawio.png\" style=\"width: 441px; height: 351px;\"></p>\n\n<pre><b>输入：</b>nums = [6,2,2,2,6], edges = [[0,1],[1,2],[1,3],[3,4]] \n<b>输出：</b>2 \n<b>解释：</b>上图展示了我们可以删除边 [0,1] 和 [3,4] 。得到的连通块为 [0] ，[1,2,3] 和 [4] 。每个连通块的价值都为 6 。可以证明没有别的更好的删除方案存在了，所以答案为 2 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><b>输入：</b>nums = [2], edges = []\n<b>输出：</b>0\n<b>解释：</b>没有任何边可以删除。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 2 * 10<sup>4</sup></code></li>\n\t<li><code>nums.length == n</code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 50</code></li>\n\t<li><code>edges.length == n - 1</code></li>\n\t<li><code>edges[i].length == 2</code></li>\n\t<li><code>0 &lt;= edges[i][0], edges[i][1] &lt;= n - 1</code></li>\n\t<li><code>edges</code>&nbsp;表示一棵合法的树。</li>\n</ul>\n",
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