mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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186 lines
28 KiB
JSON
186 lines
28 KiB
JSON
{
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"questionId": "538",
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"questionFrontendId": "538",
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"categoryTitle": "Algorithms",
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"boundTopicId": 1755,
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"title": "Convert BST to Greater Tree",
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"titleSlug": "convert-bst-to-greater-tree",
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"content": "<p>Given the <code>root</code> of a Binary Search Tree (BST), convert it to a Greater Tree such that every key of the original BST is changed to the original key plus the sum of all keys greater than the original key in BST.</p>\n\n<p>As a reminder, a <em>binary search tree</em> is a tree that satisfies these constraints:</p>\n\n<ul>\n\t<li>The left subtree of a node contains only nodes with keys <strong>less than</strong> the node's key.</li>\n\t<li>The right subtree of a node contains only nodes with keys <strong>greater than</strong> the node's key.</li>\n\t<li>Both the left and right subtrees must also be binary search trees.</li>\n</ul>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2019/05/02/tree.png\" style=\"width: 500px; height: 341px;\" />\n<pre>\n<strong>Input:</strong> root = [4,1,6,0,2,5,7,null,null,null,3,null,null,null,8]\n<strong>Output:</strong> [30,36,21,36,35,26,15,null,null,null,33,null,null,null,8]\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> root = [0,null,1]\n<strong>Output:</strong> [1,null,1]\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li>The number of nodes in the tree is in the range <code>[0, 10<sup>4</sup>]</code>.</li>\n\t<li><code>-10<sup>4</sup> <= Node.val <= 10<sup>4</sup></code></li>\n\t<li>All the values in the tree are <strong>unique</strong>.</li>\n\t<li><code>root</code> is guaranteed to be a valid binary search tree.</li>\n</ul>\n\n<p> </p>\n<p><strong>Note:</strong> This question is the same as 1038: <a href=\"https://leetcode.com/problems/binary-search-tree-to-greater-sum-tree/\" target=\"_blank\">https://leetcode.com/problems/binary-search-tree-to-greater-sum-tree/</a></p>\n",
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"translatedTitle": "把二叉搜索树转换为累加树",
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"translatedContent": "<p>给出二叉<strong> 搜索 </strong>树的根节点，该树的节点值各不相同，请你将其转换为累加树（Greater Sum Tree），使每个节点 <code>node</code> 的新值等于原树中大于或等于 <code>node.val</code> 的值之和。</p>\n\n<p>提醒一下，二叉搜索树满足下列约束条件：</p>\n\n<ul>\n\t<li>节点的左子树仅包含键<strong> 小于 </strong>节点键的节点。</li>\n\t<li>节点的右子树仅包含键<strong> 大于</strong> 节点键的节点。</li>\n\t<li>左右子树也必须是二叉搜索树。</li>\n</ul>\n\n<p><strong>注意：</strong>本题和 1038: <a href=\"https://leetcode-cn.com/problems/binary-search-tree-to-greater-sum-tree/\">https://leetcode-cn.com/problems/binary-search-tree-to-greater-sum-tree/</a> 相同</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<p><strong><img alt=\"\" src=\"https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2019/05/03/tree.png\" style=\"height: 364px; width: 534px;\"></strong></p>\n\n<pre><strong>输入：</strong>[4,1,6,0,2,5,7,null,null,null,3,null,null,null,8]\n<strong>输出：</strong>[30,36,21,36,35,26,15,null,null,null,33,null,null,null,8]\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入：</strong>root = [0,null,1]\n<strong>输出：</strong>[1,null,1]\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre><strong>输入：</strong>root = [1,0,2]\n<strong>输出：</strong>[3,3,2]\n</pre>\n\n<p><strong>示例 4：</strong></p>\n\n<pre><strong>输入：</strong>root = [3,2,4,1]\n<strong>输出：</strong>[7,9,4,10]\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li>树中的节点数介于 <code>0</code> 和 <code>10<sup>4</sup></code><sup> </sup>之间。</li>\n\t<li>每个节点的值介于 <code>-10<sup>4</sup></code> 和 <code>10<sup>4</sup></code> 之间。</li>\n\t<li>树中的所有值 <strong>互不相同</strong> 。</li>\n\t<li>给定的树为二叉搜索树。</li>\n</ul>\n",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * val: number\n * left: TreeNode | null\n * right: TreeNode | null\n * constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n * }\n */\n\nfunction convertBST(root: TreeNode | null): TreeNode | null {\n \n};",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * public $val = null;\n * public $left = null;\n * public $right = null;\n * function __construct($val = 0, $left = null, $right = null) {\n * $this->val = $val;\n * $this->left = $left;\n * $this->right = $right;\n * }\n * }\n */\nclass Solution {\n\n /**\n * @param TreeNode $root\n * @return TreeNode\n */\n function convertBST($root) {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public var val: Int\n * public var left: TreeNode?\n * public var right: TreeNode?\n * public init() { self.val = 0; self.left = nil; self.right = nil; }\n * public init(_ val: Int) { self.val = val; self.left = nil; self.right = nil; }\n * public init(_ val: Int, _ left: TreeNode?, _ right: TreeNode?) {\n * self.val = val\n * self.left = left\n * self.right = right\n * }\n * }\n */\nclass Solution {\n func convertBST(_ root: TreeNode?) -> TreeNode? {\n\n }\n}",
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"code": "/**\n * Example:\n * var ti = TreeNode(5)\n * var v = ti.`val`\n * Definition for a binary tree node.\n * class TreeNode(var `val`: Int) {\n * var left: TreeNode? = null\n * var right: TreeNode? = null\n * }\n */\nclass Solution {\n fun convertBST(root: TreeNode?): TreeNode? {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * int val;\n * TreeNode? left;\n * TreeNode? right;\n * TreeNode([this.val = 0, this.left, this.right]);\n * }\n */\nclass Solution {\n TreeNode? convertBST(TreeNode? root) {\n \n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * type TreeNode struct {\n * Val int\n * Left *TreeNode\n * Right *TreeNode\n * }\n */\nfunc convertBST(root *TreeNode) *TreeNode {\n\n}",
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"code": "# Definition for a binary tree node.\n# class TreeNode\n# attr_accessor :val, :left, :right\n# def initialize(val = 0, left = nil, right = nil)\n# @val = val\n# @left = left\n# @right = right\n# end\n# end\n# @param {TreeNode} root\n# @return {TreeNode}\ndef convert_bst(root)\n\nend",
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