leetcode-problemset/leetcode-cn/originData/combine-two-tables.json

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        "question": {
            "questionId": "175",
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            "categoryTitle": "Database",
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            "title": "Combine Two Tables",
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            "content": "<p>Table: <code>Person</code></p>\n\n<pre>\n+-------------+---------+\n| Column Name | Type    |\n+-------------+---------+\n| personId    | int     |\n| lastName    | varchar |\n| firstName   | varchar |\n+-------------+---------+\npersonId is the primary key (column with unique values) for this table.\nThis table contains information about the ID of some persons and their first and last names.\n</pre>\n\n<p>&nbsp;</p>\n\n<p>Table: <code>Address</code></p>\n\n<pre>\n+-------------+---------+\n| Column Name | Type    |\n+-------------+---------+\n| addressId   | int     |\n| personId    | int     |\n| city        | varchar |\n| state       | varchar |\n+-------------+---------+\naddressId is the primary key (column with unique values) for this table.\nEach row of this table contains information about the city and state of one person with ID = PersonId.\n</pre>\n\n<p>&nbsp;</p>\n\n<p>Write a solution to report the first name, last name, city, and state of each person in the <code>Person</code> table. If the address of a <code>personId</code> is not present in the <code>Address</code> table, report <code>null</code> instead.</p>\n\n<p>Return the result table in <strong>any order</strong>.</p>\n\n<p>The result format is in the following example.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> \nPerson table:\n+----------+----------+-----------+\n| personId | lastName | firstName |\n+----------+----------+-----------+\n| 1        | Wang     | Allen     |\n| 2        | Alice    | Bob       |\n+----------+----------+-----------+\nAddress table:\n+-----------+----------+---------------+------------+\n| addressId | personId | city          | state      |\n+-----------+----------+---------------+------------+\n| 1         | 2        | New York City | New York   |\n| 2         | 3        | Leetcode      | California |\n+-----------+----------+---------------+------------+\n<strong>Output:</strong> \n+-----------+----------+---------------+----------+\n| firstName | lastName | city          | state    |\n+-----------+----------+---------------+----------+\n| Allen     | Wang     | Null          | Null     |\n| Bob       | Alice    | New York City | New York |\n+-----------+----------+---------------+----------+\n<strong>Explanation:</strong> \nThere is no address in the address table for the personId = 1 so we return null in their city and state.\naddressId = 1 contains information about the address of personId = 2.\n</pre>\n",
            "translatedTitle": "组合两个表",
            "translatedContent": "<p>表: <code>Person</code></p>\n\n<pre>\n+-------------+---------+\n| 列名         | 类型     |\n+-------------+---------+\n| PersonId    | int     |\n| FirstName   | varchar |\n| LastName    | varchar |\n+-------------+---------+\npersonId 是该表的主键（具有唯一值的列）。\n该表包含一些人的 ID 和他们的姓和名的信息。\n</pre>\n\n<p>&nbsp;</p>\n\n<p>表: <code>Address</code></p>\n\n<pre>\n+-------------+---------+\n| 列名         | 类型    |\n+-------------+---------+\n| AddressId   | int     |\n| PersonId    | int     |\n| City        | varchar |\n| State       | varchar |\n+-------------+---------+\naddressId 是该表的主键（具有唯一值的列）。\n该表的每一行都包含一个 ID = PersonId 的人的城市和州的信息。\n</pre>\n\n<p>&nbsp;</p>\n\n<p>编写解决方案，报告 <code>Person</code> 表中每个人的姓、名、城市和州。如果 <code>personId</code> 的地址不在&nbsp;<code>Address</code>&nbsp;表中，则报告为&nbsp;<code>null</code>&nbsp;。</p>\n\n<p>以 <strong>任意顺序</strong> 返回结果表。</p>\n\n<p>结果格式如下所示。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre>\n<strong>输入:</strong> \nPerson表:\n+----------+----------+-----------+\n| personId | lastName | firstName |\n+----------+----------+-----------+\n| 1        | Wang     | Allen     |\n| 2        | Alice    | Bob       |\n+----------+----------+-----------+\nAddress表:\n+-----------+----------+---------------+------------+\n| addressId | personId | city          | state      |\n+-----------+----------+---------------+------------+\n| 1         | 2        | New York City | New York   |\n| 2         | 3        | Leetcode      | California |\n+-----------+----------+---------------+------------+\n<strong>输出:</strong> \n+-----------+----------+---------------+----------+\n| firstName | lastName | city          | state    |\n+-----------+----------+---------------+----------+\n| Allen     | Wang     | Null          | Null     |\n| Bob       | Alice    | New York City | New York |\n+-----------+----------+---------------+----------+\n<strong>解释:</strong> \n地址表中没有 personId = 1 的地址，所以它们的城市和州返回 null。\naddressId = 1 包含了 personId = 2 的地址信息。</pre>\n",
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            "sampleTestCase": "{\"headers\":{\"Person\":[\"personId\",\"lastName\",\"firstName\"],\"Address\":[\"addressId\",\"personId\",\"city\",\"state\"]},\"rows\":{\"Person\":[[1,\"Wang\",\"Allen\"],[2,\"Alice\",\"Bob\"]],\"Address\":[[1,2,\"New York City\",\"New York\"],[2,3,\"Leetcode\",\"California\"]]}}",
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                "Create table If Not Exists Person (personId int, firstName varchar(255), lastName varchar(255))",
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                "Truncate table Person",
                "insert into Person (personId, lastName, firstName) values ('1', 'Wang', 'Allen')",
                "insert into Person (personId, lastName, firstName) values ('2', 'Alice', 'Bob')",
                "Truncate table Address",
                "insert into Address (addressId, personId, city, state) values ('1', '2', 'New York City', 'New York')",
                "insert into Address (addressId, personId, city, state) values ('2', '3', 'Leetcode', 'California')"
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