leetcode-problemset/leetcode-cn/originData/check-if-all-as-appears-before-all-bs.json

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            "questionId": "2243",
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            "categoryTitle": "Algorithms",
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            "title": "Check if All A's Appears Before All B's",
            "titleSlug": "check-if-all-as-appears-before-all-bs",
            "content": "<p>Given a string <code>s</code> consisting of <strong>only</strong> the characters <code>&#39;a&#39;</code> and <code>&#39;b&#39;</code>, return <code>true</code> <em>if <strong>every</strong> </em><code>&#39;a&#39;</code> <em>appears before <strong>every</strong> </em><code>&#39;b&#39;</code><em> in the string</em>. Otherwise, return <code>false</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;aaabbb&quot;\n<strong>Output:</strong> true\n<strong>Explanation:</strong>\nThe &#39;a&#39;s are at indices 0, 1, and 2, while the &#39;b&#39;s are at indices 3, 4, and 5.\nHence, every &#39;a&#39; appears before every &#39;b&#39; and we return true.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;abab&quot;\n<strong>Output:</strong> false\n<strong>Explanation:</strong>\nThere is an &#39;a&#39; at index 2 and a &#39;b&#39; at index 1.\nHence, not every &#39;a&#39; appears before every &#39;b&#39; and we return false.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;bbb&quot;\n<strong>Output:</strong> true\n<strong>Explanation:</strong>\nThere are no &#39;a&#39;s, hence, every &#39;a&#39; appears before every &#39;b&#39; and we return true.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 100</code></li>\n\t<li><code>s[i]</code> is either <code>&#39;a&#39;</code> or <code>&#39;b&#39;</code>.</li>\n</ul>\n",
            "translatedTitle": "检查是否所有 A 都在 B 之前",
            "translatedContent": "<p>给你一个 <strong>仅</strong> 由字符 <code>'a'</code> 和 <code>'b'</code> 组成的字符串&nbsp; <code>s</code> 。如果字符串中 <strong>每个</strong> <em> </em><code>'a'</code> 都出现在 <strong>每个</strong><em> </em><code>'b'</code><em> </em>之前，返回 <code>true</code> ；否则，返回 <code>false</code> 。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><strong>输入：</strong>s = \"aaabbb\"\n<strong>输出：</strong>true\n<strong>解释：</strong>\n'a' 位于下标 0、1 和 2 ；而 'b' 位于下标 3、4 和 5 。\n因此，每个 'a' 都出现在每个 'b' 之前，所以返回 true 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入：</strong>s = \"abab\"\n<strong>输出：</strong>false\n<strong>解释：</strong>\n存在一个 'a' 位于下标 2 ，而一个 'b' 位于下标 1 。\n因此，不能满足每个 'a' 都出现在每个 'b' 之前，所以返回 false 。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre><strong>输入：</strong>s = \"bbb\"\n<strong>输出：</strong>true\n<strong>解释：</strong>\n不存在 'a' ，因此可以视作每个 'a' 都出现在每个 'b' 之前，所以返回 true 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 100</code></li>\n\t<li><code>s[i]</code> 为 <code>'a'</code> 或 <code>'b'</code></li>\n</ul>\n",
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            "hints": [
                "You can check the opposite: check if there is a ‘b’ before an ‘a’. Then, negate and return that answer.",
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