leetcode-problemset/leetcode-cn/originData/append-characters-to-string-to-make-subsequence.json

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        "question": {
            "questionId": "2572",
            "questionFrontendId": "2486",
            "categoryTitle": "Algorithms",
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            "title": "Append Characters to String to Make Subsequence",
            "titleSlug": "append-characters-to-string-to-make-subsequence",
            "content": "<p>You are given two strings <code>s</code> and <code>t</code> consisting of only lowercase English letters.</p>\n\n<p>Return <em>the minimum number of characters that need to be appended to the end of </em><code>s</code><em> so that </em><code>t</code><em> becomes a <strong>subsequence</strong> of </em><code>s</code>.</p>\n\n<p>A <strong>subsequence</strong> is a string that can be derived from another string by deleting some or no characters without changing the order of the remaining characters.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;coaching&quot;, t = &quot;coding&quot;\n<strong>Output:</strong> 4\n<strong>Explanation:</strong> Append the characters &quot;ding&quot; to the end of s so that s = &quot;coachingding&quot;.\nNow, t is a subsequence of s (&quot;<u><strong>co</strong></u>aching<u><strong>ding</strong></u>&quot;).\nIt can be shown that appending any 3 characters to the end of s will never make t a subsequence.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;abcde&quot;, t = &quot;a&quot;\n<strong>Output:</strong> 0\n<strong>Explanation:</strong> t is already a subsequence of s (&quot;<u><strong>a</strong></u>bcde&quot;).\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;z&quot;, t = &quot;abcde&quot;\n<strong>Output:</strong> 5\n<strong>Explanation:</strong> Append the characters &quot;abcde&quot; to the end of s so that s = &quot;zabcde&quot;.\nNow, t is a subsequence of s (&quot;z<u><strong>abcde</strong></u>&quot;).\nIt can be shown that appending any 4 characters to the end of s will never make t a subsequence.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length, t.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>s</code> and <code>t</code> consist only of lowercase English letters.</li>\n</ul>\n",
            "translatedTitle": "追加字符以获得子序列",
            "translatedContent": "<p>给你两个仅由小写英文字母组成的字符串 <code>s</code> 和 <code>t</code> 。</p>\n\n<p>现在需要通过向 <code>s</code> 末尾追加字符的方式使 <code>t</code> 变成 <code>s</code> 的一个 <strong>子序列</strong> ，返回需要追加的最少字符数。</p>\n\n<p>子序列是一个可以由其他字符串删除部分（或不删除）字符但不改变剩下字符顺序得到的字符串。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"coaching\", t = \"coding\"\n<strong>输出：</strong>4\n<strong>解释：</strong>向 s 末尾追加字符串 \"ding\" ，s = \"coachingding\" 。\n现在，t 是 s (\"<em><strong>co</strong></em>aching<em><strong>ding</strong></em>\") 的一个子序列。\n可以证明向 s 末尾追加任何 3 个字符都无法使 t 成为 s 的一个子序列。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"abcde\", t = \"a\"\n<strong>输出：</strong>0\n<strong>解释：</strong>t 已经是 s (\"<em><strong>a</strong></em>bcde\") 的一个子序列。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"z\", t = \"abcde\"\n<strong>输出：</strong>5\n<strong>解释：</strong>向 s 末尾追加字符串 \"abcde\" ，s = \"zabcde\" 。\n现在，t 是 s (\"z<em><strong>abcde</strong></em>\") 的一个子序列。 \n可以证明向 s 末尾追加任何 4 个字符都无法使 t 成为 s 的一个子序列。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length, t.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>s</code> 和 <code>t</code> 仅由小写英文字母组成</li>\n</ul>\n",
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                "Find the longest prefix of t that is a subsequence of s.",
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