leetcode-problemset/leetcode-cn/originData/kth-largest-element-in-a-stream.json

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        "question": {
            "questionId": "789",
            "questionFrontendId": "703",
            "categoryTitle": "Algorithms",
            "boundTopicId": 1094,
            "title": "Kth Largest Element in a Stream",
            "titleSlug": "kth-largest-element-in-a-stream",
            "content": "<p>You are part of a university admissions office and need to keep track of the <code>kth</code> highest test score from applicants in real-time. This helps to determine cut-off marks for interviews and admissions dynamically as new applicants submit their scores.</p>\n\n<p>You are tasked to implement a class which, for a given integer&nbsp;<code>k</code>, maintains a stream of test scores and continuously returns the&nbsp;<code>k</code>th highest test score&nbsp;<strong>after</strong>&nbsp;a new score has been submitted. More specifically, we are looking for the <code>k</code>th highest score in the sorted list of all scores.</p>\n\n<p>Implement the&nbsp;<code>KthLargest</code> class:</p>\n\n<ul>\n\t<li><code>KthLargest(int k, int[] nums)</code> Initializes the object with the integer <code>k</code> and the stream of test scores&nbsp;<code>nums</code>.</li>\n\t<li><code>int add(int val)</code> Adds a new test score&nbsp;<code>val</code> to the stream and returns the element representing the <code>k<sup>th</sup></code> largest element in the pool of test scores so far.</li>\n</ul>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong><br />\n<span class=\"example-io\">[&quot;KthLargest&quot;, &quot;add&quot;, &quot;add&quot;, &quot;add&quot;, &quot;add&quot;, &quot;add&quot;]<br />\n[[3, [4, 5, 8, 2]], [3], [5], [10], [9], [4]]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">[null, 4, 5, 5, 8, 8]</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>KthLargest kthLargest = new KthLargest(3, [4, 5, 8, 2]);<br />\nkthLargest.add(3); // return 4<br />\nkthLargest.add(5); // return 5<br />\nkthLargest.add(10); // return 5<br />\nkthLargest.add(9); // return 8<br />\nkthLargest.add(4); // return 8</p>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong><br />\n<span class=\"example-io\">[&quot;KthLargest&quot;, &quot;add&quot;, &quot;add&quot;, &quot;add&quot;, &quot;add&quot;]<br />\n[[4, [7, 7, 7, 7, 8, 3]], [2], [10], [9], [9]]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">[null, 7, 7, 7, 8]</span></p>\n\n<p><strong>Explanation:</strong></p>\nKthLargest kthLargest = new KthLargest(4, [7, 7, 7, 7, 8, 3]);<br />\nkthLargest.add(2); // return 7<br />\nkthLargest.add(10); // return 7<br />\nkthLargest.add(9); // return 7<br />\nkthLargest.add(9); // return 8</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>0 &lt;= nums.length &lt;= 10<sup>4</sup></code></li>\n\t<li><code>1 &lt;= k &lt;= nums.length + 1</code></li>\n\t<li><code>-10<sup>4</sup> &lt;= nums[i] &lt;= 10<sup>4</sup></code></li>\n\t<li><code>-10<sup>4</sup> &lt;= val &lt;= 10<sup>4</sup></code></li>\n\t<li>At most <code>10<sup>4</sup></code> calls will be made to <code>add</code>.</li>\n</ul>\n",
            "translatedTitle": "数据流中的第 K 大元素",
            "translatedContent": "<p>设计一个找到数据流中第 <code>k</code> 大元素的类（class）。注意是排序后的第 <code>k</code> 大元素，不是第 <code>k</code> 个不同的元素。</p>\n\n<p>请实现 <code>KthLargest</code>&nbsp;类：</p>\n\n<ul>\n\t<li><code>KthLargest(int k, int[] nums)</code> 使用整数 <code>k</code> 和整数流 <code>nums</code> 初始化对象。</li>\n\t<li><code>int add(int val)</code> 将 <code>val</code> 插入数据流 <code>nums</code> 后，返回当前数据流中第 <code>k</code> 大的元素。</li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong><br />\n<span class=\"example-io\">[\"KthLargest\", \"add\", \"add\", \"add\", \"add\", \"add\"]<br />\n[[3, [4, 5, 8, 2]], [3], [5], [10], [9], [4]]</span></p>\n\n<p><strong>输出：</strong><span class=\"example-io\">[null, 4, 5, 5, 8, 8]</span></p>\n\n<p><strong>解释：</strong></p>\n\n<p>KthLargest kthLargest = new KthLargest(3, [4, 5, 8, 2]);<br />\nkthLargest.add(3); // 返回 4<br />\nkthLargest.add(5); // 返回 5<br />\nkthLargest.add(10); // 返回 5<br />\nkthLargest.add(9); // 返回 8<br />\nkthLargest.add(4); // 返回 8</p>\n\n<p>&nbsp;</p>\n</div>\n\n<p><strong class=\"example\">示例&nbsp;2：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong><br />\n<span class=\"example-io\">[\"KthLargest\", \"add\", \"add\", \"add\", \"add\"]<br />\n[[4, [7, 7, 7, 7, 8, 3]], [2], [10], [9], [9]]</span></p>\n\n<p><span class=\"example-io\"><b>输出：</b>[null, 7, 7, 7, 8]</span></p>\n\n<p><strong>解释：</strong></p>\nKthLargest kthLargest = new KthLargest(4, [7, 7, 7, 7, 8, 3]);<br />\nkthLargest.add(2); // 返回 7<br />\nkthLargest.add(10); // 返回 7<br />\nkthLargest.add(9); // 返回 7<br />\nkthLargest.add(9); // 返回 8</div>\n\n<p>&nbsp;</p>\n<strong>提示：</strong>\n\n<ul>\n\t<li><code>0 &lt;= nums.length &lt;= 10<sup>4</sup></code></li>\n\t<li><code>1 &lt;= k &lt;= nums.length + 1</code></li>\n\t<li><code>-10<sup>4</sup> &lt;= nums[i] &lt;= 10<sup>4</sup></code></li>\n\t<li><code>-10<sup>4</sup> &lt;= val &lt;= 10<sup>4</sup></code></li>\n\t<li>最多调用 <code>add</code> 方法 <code>10<sup>4</sup></code> 次</li>\n</ul>\n",
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                    "code": "class KthLargest {\npublic:\n    KthLargest(int k, vector<int>& nums) {\n        \n    }\n    \n    int add(int val) {\n        \n    }\n};\n\n/**\n * Your KthLargest object will be instantiated and called as such:\n * KthLargest* obj = new KthLargest(k, nums);\n * int param_1 = obj->add(val);\n */",
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                    "code": "class KthLargest {\n\n    public KthLargest(int k, int[] nums) {\n        \n    }\n    \n    public int add(int val) {\n        \n    }\n}\n\n/**\n * Your KthLargest object will be instantiated and called as such:\n * KthLargest obj = new KthLargest(k, nums);\n * int param_1 = obj.add(val);\n */",
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                    "code": "class KthLargest(object):\n\n    def __init__(self, k, nums):\n        \"\"\"\n        :type k: int\n        :type nums: List[int]\n        \"\"\"\n        \n\n    def add(self, val):\n        \"\"\"\n        :type val: int\n        :rtype: int\n        \"\"\"\n        \n\n\n# Your KthLargest object will be instantiated and called as such:\n# obj = KthLargest(k, nums)\n# param_1 = obj.add(val)",
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                    "code": "class KthLargest(_k: Int, _nums: Array[Int]) {\n\n    def add(`val`: Int): Int = {\n        \n    }\n\n}\n\n/**\n * Your KthLargest object will be instantiated and called as such:\n * val obj = new KthLargest(k, nums)\n * val param_1 = obj.add(`val`)\n */",
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                    "code": "struct KthLargest {\n\n}\n\n\n/** \n * `&self` means the method takes an immutable reference.\n * If you need a mutable reference, change it to `&mut self` instead.\n */\nimpl KthLargest {\n\n    fn new(k: i32, nums: Vec<i32>) -> Self {\n        \n    }\n    \n    fn add(&self, val: i32) -> i32 {\n        \n    }\n}\n\n/**\n * Your KthLargest object will be instantiated and called as such:\n * let obj = KthLargest::new(k, nums);\n * let ret_1: i32 = obj.add(val);\n */",
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                    "code": "defmodule KthLargest do\n  @spec init_(k :: integer, nums :: [integer]) :: any\n  def init_(k, nums) do\n    \n  end\n\n  @spec add(val :: integer) :: integer\n  def add(val) do\n    \n  end\nend\n\n# Your functions will be called as such:\n# KthLargest.init_(k, nums)\n# param_1 = KthLargest.add(val)\n\n# KthLargest.init_ will be called before every test case, in which you can do some necessary initializations.",
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