leetcode-problemset/leetcode-cn/originData/find-closest-person.json

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        "question": {
            "questionId": "3830",
            "questionFrontendId": "3516",
            "categoryTitle": "Algorithms",
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            "title": "Find Closest Person",
            "titleSlug": "find-closest-person",
            "content": "<p data-end=\"116\" data-start=\"0\">You are given three integers <code data-end=\"33\" data-start=\"30\">x</code>, <code data-end=\"38\" data-start=\"35\">y</code>, and <code data-end=\"47\" data-start=\"44\">z</code>, representing the positions of three people on a number line:</p>\n\n<ul data-end=\"252\" data-start=\"118\">\n\t<li data-end=\"154\" data-start=\"118\"><code data-end=\"123\" data-start=\"120\">x</code> is the position of Person 1.</li>\n\t<li data-end=\"191\" data-start=\"155\"><code data-end=\"160\" data-start=\"157\">y</code> is the position of Person 2.</li>\n\t<li data-end=\"252\" data-start=\"192\"><code data-end=\"197\" data-start=\"194\">z</code> is the position of Person 3, who does <strong>not</strong> move.</li>\n</ul>\n\n<p data-end=\"322\" data-start=\"254\">Both Person 1 and Person 2 move toward Person 3 at the <strong>same</strong> speed.</p>\n\n<p data-end=\"372\" data-start=\"324\">Determine which person reaches Person 3 <strong>first</strong>:</p>\n\n<ul data-end=\"505\" data-start=\"374\">\n\t<li data-end=\"415\" data-start=\"374\">Return 1 if Person 1 arrives first.</li>\n\t<li data-end=\"457\" data-start=\"416\">Return 2 if Person 2 arrives first.</li>\n\t<li data-end=\"505\" data-start=\"458\">Return 0 if both arrive at the <strong>same</strong> time.</li>\n</ul>\n\n<p data-end=\"537\" data-is-last-node=\"\" data-is-only-node=\"\" data-start=\"507\">Return the result accordingly.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">x = 2, y = 7, z = 4</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">1</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<ul data-end=\"258\" data-start=\"113\">\n\t<li data-end=\"193\" data-start=\"113\">Person 1 is at position 2 and can reach Person 3 (at position 4) in 2 steps.</li>\n\t<li data-end=\"258\" data-start=\"194\">Person 2 is at position 7 and can reach Person 3 in 3 steps.</li>\n</ul>\n\n<p data-end=\"317\" data-is-last-node=\"\" data-is-only-node=\"\" data-start=\"260\">Since Person 1 reaches Person 3 first, the output is 1.</p>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">x = 2, y = 5, z = 6</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">2</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<ul data-end=\"245\" data-start=\"92\">\n\t<li data-end=\"174\" data-start=\"92\">Person 1 is at position 2 and can reach Person 3 (at position 6) in 4 steps.</li>\n\t<li data-end=\"245\" data-start=\"175\">Person 2 is at position 5 and can reach Person 3 in 1 step.</li>\n</ul>\n\n<p data-end=\"304\" data-is-last-node=\"\" data-is-only-node=\"\" data-start=\"247\">Since Person 2 reaches Person 3 first, the output is 2.</p>\n</div>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">x = 1, y = 5, z = 3</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">0</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<ul data-end=\"245\" data-start=\"92\">\n\t<li data-end=\"174\" data-start=\"92\">Person 1 is at position 1 and can reach Person 3 (at position 3) in 2 steps.</li>\n\t<li data-end=\"245\" data-start=\"175\">Person 2 is at position 5 and can reach Person 3 in 2 steps.</li>\n</ul>\n\n<p data-end=\"304\" data-is-last-node=\"\" data-is-only-node=\"\" data-start=\"247\">Since both Person 1 and Person 2 reach Person 3 at the same time, the output is 0.</p>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= x, y, z &lt;= 100</code></li>\n</ul>\n",
            "translatedTitle": "找到最近的人",
            "translatedContent": "<p data-end=\"116\" data-start=\"0\">给你三个整数 <code data-end=\"33\" data-start=\"30\">x</code>、<code data-end=\"38\" data-start=\"35\">y</code> 和 <code data-end=\"47\" data-start=\"44\">z</code>，表示数轴上三个人的位置：</p>\n\n<ul data-end=\"252\" data-start=\"118\">\n\t<li data-end=\"154\" data-start=\"118\"><code data-end=\"123\" data-start=\"120\">x</code> 是第 1 个人的位置。</li>\n\t<li data-end=\"191\" data-start=\"155\"><code data-end=\"160\" data-start=\"157\">y</code> 是第 2 个人的位置。</li>\n\t<li data-end=\"252\" data-start=\"192\"><code data-end=\"197\" data-start=\"194\">z</code> 是第 3 个人的位置，第 3 个人&nbsp;<strong>不会移动&nbsp;</strong>。</li>\n</ul>\n\n<p data-end=\"322\" data-start=\"254\">第 1 个人和第 2 个人以&nbsp;<strong>相同&nbsp;</strong>的速度向第 3 个人移动。</p>\n\n<p data-end=\"372\" data-start=\"324\">判断谁会&nbsp;<strong>先&nbsp;</strong>到达第 3 个人的位置：</p>\n\n<ul data-end=\"505\" data-start=\"374\">\n\t<li data-end=\"415\" data-start=\"374\">如果第 1 个人先到达，返回 1 。</li>\n\t<li data-end=\"457\" data-start=\"416\">如果第 2 个人先到达，返回 2 。</li>\n\t<li data-end=\"505\" data-start=\"458\">如果两个人同时到达，返回 <strong>0&nbsp;</strong>。</li>\n</ul>\n\n<p data-end=\"537\" data-is-last-node=\"\" data-is-only-node=\"\" data-start=\"507\">根据上述规则返回结果。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong> <span class=\"example-io\">x = 2, y = 7, z = 4</span></p>\n\n<p><strong>输出：</strong> <span class=\"example-io\">1</span></p>\n\n<p><strong>解释：</strong></p>\n\n<ul data-end=\"258\" data-start=\"113\">\n\t<li data-end=\"193\" data-start=\"113\">第 1 个人在位置 2，到达第 3 个人（位置 4）需要 2 步。</li>\n\t<li data-end=\"258\" data-start=\"194\">第 2 个人在位置 7，到达第 3 个人需要 3 步。</li>\n</ul>\n\n<p data-end=\"317\" data-is-last-node=\"\" data-is-only-node=\"\" data-start=\"260\">由于第 1 个人先到达，所以输出为 1。</p>\n</div>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong> <span class=\"example-io\">x = 2, y = 5, z = 6</span></p>\n\n<p><strong>输出：</strong> <span class=\"example-io\">2</span></p>\n\n<p><strong>解释：</strong></p>\n\n<ul data-end=\"245\" data-start=\"92\">\n\t<li data-end=\"174\" data-start=\"92\">第 1 个人在位置 2，到达第 3 个人（位置 6）需要 4 步。</li>\n\t<li data-end=\"245\" data-start=\"175\">第 2 个人在位置 5，到达第 3 个人需要 1 步。</li>\n</ul>\n\n<p data-end=\"304\" data-is-last-node=\"\" data-is-only-node=\"\" data-start=\"247\">由于第 2 个人先到达，所以输出为 2。</p>\n</div>\n\n<p><strong class=\"example\">示例 3：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong> <span class=\"example-io\">x = 1, y = 5, z = 3</span></p>\n\n<p><strong>输出：</strong> <span class=\"example-io\">0</span></p>\n\n<p><strong>解释：</strong></p>\n\n<ul data-end=\"245\" data-start=\"92\">\n\t<li data-end=\"174\" data-start=\"92\">第 1 个人在位置 1，到达第 3 个人（位置 3）需要 2 步。</li>\n\t<li data-end=\"245\" data-start=\"175\">第 2 个人在位置 5，到达第 3 个人需要 2 步。</li>\n</ul>\n\n<p data-end=\"304\" data-is-last-node=\"\" data-is-only-node=\"\" data-start=\"247\">由于两个人同时到达，所以输出为 0。</p>\n</div>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= x, y, z &lt;= 100</code></li>\n</ul>\n",
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target=\\\"_blank\\\">sortedcontainers<\\/a> \\u5e93\\u3002<\\/p>\"],\"scala\":[\"Scala\",\"<p>\\u7248\\u672c\\uff1a<code>Scala 3.3.1<\\/code><\\/p>\"],\"kotlin\":[\"Kotlin\",\"<p>\\u7248\\u672c\\uff1a<code>Kotlin 2.1.10<\\/code><\\/p>\"],\"rust\":[\"Rust\",\"<p>\\u7248\\u672c\\uff1a<code>rust 1.85.0<\\/code><\\/p>\\r\\n\\r\\n<p>\\u652f\\u6301 crates.io \\u7684 <a href=\\\"https:\\/\\/crates.io\\/crates\\/rand\\\" target=\\\"_blank\\\">rand<\\/a>\\u3001<a href=\\\"https:\\/\\/crates.io\\/crates\\/regex\\\" target=\\\"_blank\\\">regex<\\/a> \\u548c <a href=\\\"https:\\/\\/crates.io\\/crates\\/itertools\\\" target=\\\"_blank\\\">itertools<\\/a><\\/p>\"],\"php\":[\"PHP\",\"<p><code>PHP 8.2<\\/code>.<\\/p>\\r\\n\\r\\n<p>With bcmath module.<\\/p>\"],\"typescript\":[\"TypeScript\",\"<p>TypeScript 5.7.3<\\/p>\\r\\n\\r\\n<p>Compile Options: --alwaysStrict --strictBindCallApply --strictFunctionTypes --target ES2024<\\/p>\\r\\n\\r\\n<p><a href=\\\"https:\\/\\/lodash.com\\\" target=\\\"_blank\\\">lodash.js<\\/a> \\u5e93\\u5df2\\u7ecf\\u9ed8\\u8ba4\\u88ab\\u5305\\u542b\\u3002<\\/p>\\r\\n\\r\\n<p> \\u5982\\u9700\\u4f7f\\u7528\\u961f\\u5217\\/\\u4f18\\u5148\\u961f\\u5217\\uff0c\\u60a8\\u53ef\\u4f7f\\u7528 <a href=\\\"https:\\/\\/github.com\\/datastructures-js\\/priority-queue\\/tree\\/v6.3.2\\\" target=\\\"_blank\\\"> datastructures-js\\/priority-queue@6.3.2<\\/a>\\uff0c<a href=\\\"https:\\/\\/github.com\\/datastructures-js\\/queue\\/tree\\/v4.2.3\\\" target=\\\"_blank\\\"> datastructures-js\\/queue@4.2.3<\\/a> \\u4ee5\\u53ca <a href=\\\"https:\\/\\/github.com\\/datastructures-js\\/deque\\/tree\\/v1.0.4\\\" target=\\\"_blank\\\"> datastructures-js\\/deque@1.0.4<\\/a>\\u3002<\\/p>\"],\"racket\":[\"Racket\",\"<p><a href=\\\"https:\\/\\/docs.racket-lang.org\\/guide\\/performance.html#%28tech._c%29\\\" target=\\\"_blank\\\">Racket CS<\\/a> v8.15<\\/p>\\r\\n\\r\\n<p>\\u4f7f\\u7528 #lang racket<\\/p>\\r\\n\\r\\n<p>\\u5df2\\u9884\\u5148 (require data\\/gvector 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target=\\\"_blank\\\">\\u300c\\u4ed3\\u9889\\u7f16\\u7a0b\\u8bed\\u8a00\\u5f00\\u53d1\\u6307\\u5357\\u300d<\\/a><\\/p>\"]}",
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