leetcode-problemset/leetcode-cn/originData/evaluate-division.json

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        "question": {
            "questionId": "399",
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            "categoryTitle": "Algorithms",
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            "title": "Evaluate Division",
            "titleSlug": "evaluate-division",
            "content": "<p>You are given an array of variable pairs <code>equations</code> and an array of real numbers <code>values</code>, where <code>equations[i] = [A<sub>i</sub>, B<sub>i</sub>]</code> and <code>values[i]</code> represent the equation <code>A<sub>i</sub> / B<sub>i</sub> = values[i]</code>. Each <code>A<sub>i</sub></code> or <code>B<sub>i</sub></code> is a string that represents a single variable.</p>\n\n<p>You are also given some <code>queries</code>, where <code>queries[j] = [C<sub>j</sub>, D<sub>j</sub>]</code> represents the <code>j<sup>th</sup></code> query where you must find the answer for <code>C<sub>j</sub> / D<sub>j</sub> = ?</code>.</p>\n\n<p>Return <em>the answers to all queries</em>. If a single answer cannot be determined, return <code>-1.0</code>.</p>\n\n<p><strong>Note:</strong> The input is always valid. You may assume that evaluating the queries will not result in division by zero and that there is no contradiction.</p>\n\n<p><strong>Note:&nbsp;</strong>The variables that do not occur in the list of equations are undefined, so the answer cannot be determined for them.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> equations = [[&quot;a&quot;,&quot;b&quot;],[&quot;b&quot;,&quot;c&quot;]], values = [2.0,3.0], queries = [[&quot;a&quot;,&quot;c&quot;],[&quot;b&quot;,&quot;a&quot;],[&quot;a&quot;,&quot;e&quot;],[&quot;a&quot;,&quot;a&quot;],[&quot;x&quot;,&quot;x&quot;]]\n<strong>Output:</strong> [6.00000,0.50000,-1.00000,1.00000,-1.00000]\n<strong>Explanation:</strong> \nGiven: <em>a / b = 2.0</em>, <em>b / c = 3.0</em>\nqueries are: <em>a / c = ?</em>, <em>b / a = ?</em>, <em>a / e = ?</em>, <em>a / a = ?</em>, <em>x / x = ? </em>\nreturn: [6.0, 0.5, -1.0, 1.0, -1.0 ]\nnote: x is undefined =&gt; -1.0</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> equations = [[&quot;a&quot;,&quot;b&quot;],[&quot;b&quot;,&quot;c&quot;],[&quot;bc&quot;,&quot;cd&quot;]], values = [1.5,2.5,5.0], queries = [[&quot;a&quot;,&quot;c&quot;],[&quot;c&quot;,&quot;b&quot;],[&quot;bc&quot;,&quot;cd&quot;],[&quot;cd&quot;,&quot;bc&quot;]]\n<strong>Output:</strong> [3.75000,0.40000,5.00000,0.20000]\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> equations = [[&quot;a&quot;,&quot;b&quot;]], values = [0.5], queries = [[&quot;a&quot;,&quot;b&quot;],[&quot;b&quot;,&quot;a&quot;],[&quot;a&quot;,&quot;c&quot;],[&quot;x&quot;,&quot;y&quot;]]\n<strong>Output:</strong> [0.50000,2.00000,-1.00000,-1.00000]\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= equations.length &lt;= 20</code></li>\n\t<li><code>equations[i].length == 2</code></li>\n\t<li><code>1 &lt;= A<sub>i</sub>.length, B<sub>i</sub>.length &lt;= 5</code></li>\n\t<li><code>values.length == equations.length</code></li>\n\t<li><code>0.0 &lt; values[i] &lt;= 20.0</code></li>\n\t<li><code>1 &lt;= queries.length &lt;= 20</code></li>\n\t<li><code>queries[i].length == 2</code></li>\n\t<li><code>1 &lt;= C<sub>j</sub>.length, D<sub>j</sub>.length &lt;= 5</code></li>\n\t<li><code>A<sub>i</sub>, B<sub>i</sub>, C<sub>j</sub>, D<sub>j</sub></code> consist of lower case English letters and digits.</li>\n</ul>\n",
            "translatedTitle": "除法求值",
            "translatedContent": "<p>给你一个变量对数组 <code>equations</code> 和一个实数值数组 <code>values</code> 作为已知条件，其中 <code>equations[i] = [A<sub>i</sub>, B<sub>i</sub>]</code> 和 <code>values[i]</code> 共同表示等式 <code>A<sub>i</sub> / B<sub>i</sub> = values[i]</code> 。每个 <code>A<sub>i</sub></code> 或 <code>B<sub>i</sub></code> 是一个表示单个变量的字符串。</p>\n\n<p>另有一些以数组 <code>queries</code> 表示的问题，其中 <code>queries[j] = [C<sub>j</sub>, D<sub>j</sub>]</code> 表示第 <code>j</code> 个问题，请你根据已知条件找出 <code>C<sub>j</sub> / D<sub>j</sub> = ?</code> 的结果作为答案。</p>\n\n<p>返回 <strong>所有问题的答案</strong> 。如果存在某个无法确定的答案，则用 <code>-1.0</code> 替代这个答案。如果问题中出现了给定的已知条件中没有出现的字符串，也需要用 <code>-1.0</code> 替代这个答案。</p>\n\n<p><strong>注意：</strong>输入总是有效的。你可以假设除法运算中不会出现除数为 0 的情况，且不存在任何矛盾的结果。</p>\n\n<p><strong>注意：</strong>未在等式列表中出现的变量是未定义的，因此无法确定它们的答案。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>equations = [[\"a\",\"b\"],[\"b\",\"c\"]], values = [2.0,3.0], queries = [[\"a\",\"c\"],[\"b\",\"a\"],[\"a\",\"e\"],[\"a\",\"a\"],[\"x\",\"x\"]]\n<strong>输出：</strong>[6.00000,0.50000,-1.00000,1.00000,-1.00000]\n<strong>解释：</strong>\n条件：<em>a / b = 2.0</em>, <em>b / c = 3.0</em>\n问题：<em>a / c = ?</em>, <em>b / a = ?</em>, <em>a / e = ?</em>, <em>a / a = ?</em>, <em>x / x = ?</em>\n结果：[6.0, 0.5, -1.0, 1.0, -1.0 ]\n注意：x 是未定义的 =&gt; -1.0</pre>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>equations = [[\"a\",\"b\"],[\"b\",\"c\"],[\"bc\",\"cd\"]], values = [1.5,2.5,5.0], queries = [[\"a\",\"c\"],[\"c\",\"b\"],[\"bc\",\"cd\"],[\"cd\",\"bc\"]]\n<strong>输出：</strong>[3.75000,0.40000,5.00000,0.20000]\n</pre>\n\n<p><strong class=\"example\">示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>equations = [[\"a\",\"b\"]], values = [0.5], queries = [[\"a\",\"b\"],[\"b\",\"a\"],[\"a\",\"c\"],[\"x\",\"y\"]]\n<strong>输出：</strong>[0.50000,2.00000,-1.00000,-1.00000]\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= equations.length &lt;= 20</code></li>\n\t<li><code>equations[i].length == 2</code></li>\n\t<li><code>1 &lt;= A<sub>i</sub>.length, B<sub>i</sub>.length &lt;= 5</code></li>\n\t<li><code>values.length == equations.length</code></li>\n\t<li><code>0.0 &lt; values[i] &lt;= 20.0</code></li>\n\t<li><code>1 &lt;= queries.length &lt;= 20</code></li>\n\t<li><code>queries[i].length == 2</code></li>\n\t<li><code>1 &lt;= C<sub>j</sub>.length, D<sub>j</sub>.length &lt;= 5</code></li>\n\t<li><code>A<sub>i</sub>, B<sub>i</sub>, C<sub>j</sub>, D<sub>j</sub></code> 由小写英文字母与数字组成</li>\n</ul>\n",
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<code>use-after-free<\\/code> \\u9519\\u8bef\\u3002<\\/p>\\r\\n\\r\\n<p>\\u4e3a\\u4e86\\u4f7f\\u7528\\u65b9\\u4fbf\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n<p>\\u5982\\u60f3\\u4f7f\\u7528\\u54c8\\u5e0c\\u8868\\u8fd0\\u7b97, \\u60a8\\u53ef\\u4ee5\\u4f7f\\u7528 <a href=\\\"https:\\/\\/troydhanson.github.io\\/uthash\\/\\\" target=\\\"_blank\\\">uthash<\\/a>\\u3002 \\\"uthash.h\\\"\\u5df2\\u7ecf\\u9ed8\\u8ba4\\u88ab\\u5bfc\\u5165\\u3002\\u8bf7\\u770b\\u5982\\u4e0b\\u793a\\u4f8b:<\\/p>\\r\\n\\r\\n<p><b>1. \\u5f80\\u54c8\\u5e0c\\u8868\\u4e2d\\u6dfb\\u52a0\\u4e00\\u4e2a\\u5bf9\\u8c61\\uff1a<\\/b>\\r\\n<pre>\\r\\nstruct hash_entry {\\r\\n    int id;            \\/* we'll use this field as the key *\\/\\r\\n    char name[10];\\r\\n    UT_hash_handle hh; \\/* makes this structure hashable *\\/\\r\\n};\\r\\n\\r\\nstruct hash_entry *users = NULL;\\r\\n\\r\\nvoid add_user(struct hash_entry 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