mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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180 lines
24 KiB
JSON
180 lines
24 KiB
JSON
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"title": "Brick Wall",
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"content": "<p>There is a rectangular brick wall in front of you with <code>n</code> rows of bricks. The <code>i<sup>th</sup></code> row has some number of bricks each of the same height (i.e., one unit) but they can be of different widths. The total width of each row is the same.</p>\n\n<p>Draw a vertical line from the top to the bottom and cross the least bricks. If your line goes through the edge of a brick, then the brick is not considered as crossed. You cannot draw a line just along one of the two vertical edges of the wall, in which case the line will obviously cross no bricks.</p>\n\n<p>Given the 2D array <code>wall</code> that contains the information about the wall, return <em>the minimum number of crossed bricks after drawing such a vertical line</em>.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/04/24/cutwall-grid.jpg\" style=\"width: 493px; height: 577px;\" />\n<pre>\n<strong>Input:</strong> wall = [[1,2,2,1],[3,1,2],[1,3,2],[2,4],[3,1,2],[1,3,1,1]]\n<strong>Output:</strong> 2\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> wall = [[1],[1],[1]]\n<strong>Output:</strong> 3\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == wall.length</code></li>\n\t<li><code>1 <= n <= 10<sup>4</sup></code></li>\n\t<li><code>1 <= wall[i].length <= 10<sup>4</sup></code></li>\n\t<li><code>1 <= sum(wall[i].length) <= 2 * 10<sup>4</sup></code></li>\n\t<li><code>sum(wall[i])</code> is the same for each row <code>i</code>.</li>\n\t<li><code>1 <= wall[i][j] <= 2<sup>31</sup> - 1</code></li>\n</ul>\n",
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"translatedTitle": "砖墙",
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"translatedContent": "<p>你的面前有一堵矩形的、由 <code>n</code> 行砖块组成的砖墙。这些砖块高度相同（也就是一个单位高）但是宽度不同。每一行砖块的宽度之和相等。</p>\n\n<p>你现在要画一条 <strong>自顶向下 </strong>的、穿过 <strong>最少 </strong>砖块的垂线。如果你画的线只是从砖块的边缘经过，就不算穿过这块砖。<strong>你不能沿着墙的两个垂直边缘之一画线，这样显然是没有穿过一块砖的。</strong></p>\n\n<p>给你一个二维数组 <code>wall</code> ，该数组包含这堵墙的相关信息。其中，<code>wall[i]</code> 是一个代表从左至右每块砖的宽度的数组。你需要找出怎样画才能使这条线 <strong>穿过的砖块数量最少</strong> ，并且返回 <strong>穿过的砖块数量</strong> 。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/04/24/cutwall-grid.jpg\" style=\"width: 493px; height: 577px;\" />\n<pre>\n<strong>输入：</strong>wall = [[1,2,2,1],[3,1,2],[1,3,2],[2,4],[3,1,2],[1,3,1,1]]\n<strong>输出：</strong>2\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>wall = [[1],[1],[1]]\n<strong>输出：</strong>3\n</pre>\n \n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>n == wall.length</code></li>\n\t<li><code>1 <= n <= 10<sup>4</sup></code></li>\n\t<li><code>1 <= wall[i].length <= 10<sup>4</sup></code></li>\n\t<li><code>1 <= sum(wall[i].length) <= 2 * 10<sup>4</sup></code></li>\n\t<li>对于每一行 <code>i</code> ，<code>sum(wall[i])</code> 是相同的</li>\n\t<li><code>1 <= wall[i][j] <= 2<sup>31</sup> - 1</code></li>\n</ul>\n",
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