mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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168 lines
25 KiB
JSON
168 lines
25 KiB
JSON
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"questionId": "893",
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"questionFrontendId": "863",
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"categoryTitle": "Algorithms",
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"boundTopicId": 1912,
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"title": "All Nodes Distance K in Binary Tree",
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"titleSlug": "all-nodes-distance-k-in-binary-tree",
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"content": "<p>Given the <code>root</code> of a binary tree, the value of a target node <code>target</code>, and an integer <code>k</code>, return <em>an array of the values of all nodes that have a distance </em><code>k</code><em> from the target node.</em></p>\n\n<p>You can return the answer in <strong>any order</strong>.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://s3-lc-upload.s3.amazonaws.com/uploads/2018/06/28/sketch0.png\" style=\"width: 500px; height: 429px;\" />\n<pre>\n<strong>Input:</strong> root = [3,5,1,6,2,0,8,null,null,7,4], target = 5, k = 2\n<strong>Output:</strong> [7,4,1]\nExplanation: The nodes that are a distance 2 from the target node (with value 5) have values 7, 4, and 1.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> root = [1], target = 1, k = 3\n<strong>Output:</strong> []\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li>The number of nodes in the tree is in the range <code>[1, 500]</code>.</li>\n\t<li><code>0 <= Node.val <= 500</code></li>\n\t<li>All the values <code>Node.val</code> are <strong>unique</strong>.</li>\n\t<li><code>target</code> is the value of one of the nodes in the tree.</li>\n\t<li><code>0 <= k <= 1000</code></li>\n</ul>\n",
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"translatedTitle": "二叉树中所有距离为 K 的结点",
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"translatedContent": "<p>给定一个二叉树(具有根结点 <code>root</code>), 一个目标结点 <code>target</code> ,和一个整数值 <code>k</code> ,返回到目标结点 <code>target</code> 距离为 <code>k</code> 的所有结点的值的数组。</p>\n\n<p>答案可以以 <strong>任何顺序</strong> 返回。</p>\n\n<p> </p>\n\n<ol>\n</ol>\n\n<p><strong>示例 1:</strong></p>\n\n<p><img src=\"https://s3-lc-upload.s3.amazonaws.com/uploads/2018/06/28/sketch0.png\" style=\"height: 429px; width: 500px;\" /></p>\n\n<pre>\n<strong>输入:</strong>root = [3,5,1,6,2,0,8,null,null,7,4], target = 5, k = 2\n<strong>输出:</strong>[7,4,1]\n<strong>解释:</strong>所求结点为与目标结点(值为 5)距离为 2 的结点,值分别为 7,4,以及 1\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre>\n<strong>输入:</strong> root = [1], target = 1, k = 3\n<strong>输出:</strong> []\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li>节点数在 <code>[1, 500]</code> 范围内</li>\n\t<li><code>0 <= Node.val <= 500</code></li>\n\t<li><code>Node.val</code> 中所有值 <strong>不同</strong></li>\n\t<li>目标结点 <code>target</code> 是树上的结点。</li>\n\t<li><code>0 <= k <= 1000</code></li>\n</ul>\n\n<p> </p>\n",
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"code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n * int val;\n * TreeNode *left;\n * TreeNode *right;\n * TreeNode(int x) : val(x), left(NULL), right(NULL) {}\n * };\n */\nclass Solution {\npublic:\n vector<int> distanceK(TreeNode* root, TreeNode* target, int k) {\n \n }\n};",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * int val;\n * TreeNode left;\n * TreeNode right;\n * TreeNode(int x) { val = x; }\n * }\n */\nclass Solution {\n public List<Integer> distanceK(TreeNode root, TreeNode target, int k) {\n \n }\n}",
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"code": "# Definition for a binary tree node.\n# class TreeNode(object):\n# def __init__(self, x):\n# self.val = x\n# self.left = None\n# self.right = None\n\nclass Solution(object):\n def distanceK(self, root, target, k):\n \"\"\"\n :type root: TreeNode\n :type target: TreeNode\n :type k: int\n :rtype: List[int]\n \"\"\"\n ",
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"code": "# Definition for a binary tree node.\n# class TreeNode:\n# def __init__(self, x):\n# self.val = x\n# self.left = None\n# self.right = None\n\nclass Solution:\n def distanceK(self, root: TreeNode, target: TreeNode, k: int) -> List[int]:\n ",
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"code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n * int val;\n * struct TreeNode *left;\n * struct TreeNode *right;\n * };\n */\n\n\n/**\n * Note: The returned array must be malloced, assume caller calls free().\n */\nint* distanceK(struct TreeNode* root, struct TreeNode* target, int k, int* returnSize) {\n \n}",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public int val;\n * public TreeNode left;\n * public TreeNode right;\n * public TreeNode(int x) { val = x; }\n * }\n */\npublic class Solution {\n public IList<int> DistanceK(TreeNode root, TreeNode target, int k) {\n \n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * function TreeNode(val) {\n * this.val = val;\n * this.left = this.right = null;\n * }\n */\n/**\n * @param {TreeNode} root\n * @param {TreeNode} target\n * @param {number} k\n * @return {number[]}\n */\nvar distanceK = function(root, target, k) {\n \n};",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * val: number\n * left: TreeNode | null\n * right: TreeNode | null\n * constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n * }\n */\n\nfunction distanceK(root: TreeNode | null, target: TreeNode | null, k: number): number[] {\n \n};",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * public $val = null;\n * public $left = null;\n * public $right = null;\n * function __construct($value) { $this->val = $value; }\n * }\n */\nclass Solution {\n /**\n * @param TreeNode $root\n * @param TreeNode $target\n * @param Integer $k\n * @return Integer[]\n */\n function distanceK($root, $target, $k) {\n \n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public var val: Int\n * public var left: TreeNode?\n * public var right: TreeNode?\n * public init(_ val: Int) {\n * self.val = val\n * self.left = nil\n * self.right = nil\n * }\n * }\n */\nclass Solution {\n func distanceK(_ root: TreeNode?, _ target: TreeNode?, _ k: Int) -> [Int] {\n \n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode(var `val`: Int = 0) {\n * var left: TreeNode? = null\n * var right: TreeNode? = null\n * }\n */\nclass Solution {\n fun distanceK(root: TreeNode?, target: TreeNode?, k: Int): List<Int> {\n \n }\n}",
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"code": "# Definition for a binary tree node.\n# class TreeNode\n# attr_accessor :val, :left, :right\n# def initialize(val)\n# @val = val\n# @left, @right = nil, nil\n# end\n# end\n# @param {TreeNode} root\n# @param {TreeNode} target\n# @param {Integer} k\n# @return {Integer[]}\ndef distance_k(root, target, k)\n \nend",
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