mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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111 lines
20 KiB
JSON
111 lines
20 KiB
JSON
{
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"data": {
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"question": {
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"questionId": "3921",
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"questionFrontendId": "3580",
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"categoryTitle": "Database",
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"boundTopicId": 3696226,
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"title": "Find Consistently Improving Employees",
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"titleSlug": "find-consistently-improving-employees",
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"content": "<p>Table: <code>employees</code></p>\n\n<pre>\n+-------------+---------+\n| Column Name | Type |\n+-------------+---------+\n| employee_id | int |\n| name | varchar |\n+-------------+---------+\nemployee_id is the unique identifier for this table.\nEach row contains information about an employee.\n</pre>\n\n<p>Table: <code>performance_reviews</code></p>\n\n<pre>\n+-------------+------+\n| Column Name | Type |\n+-------------+------+\n| review_id | int |\n| employee_id | int |\n| review_date | date |\n| rating | int |\n+-------------+------+\nreview_id is the unique identifier for this table.\nEach row represents a performance review for an employee. The rating is on a scale of 1-5 where 5 is excellent and 1 is poor.\n</pre>\n\n<p>Write a solution to find employees who have consistently improved their performance over <strong>their last three reviews</strong>.</p>\n\n<ul>\n\t<li>An employee must have <strong>at least </strong><code>3</code><strong> review</strong> to be considered</li>\n\t<li>The employee's <strong>last </strong><code>3</code><strong> reviews</strong> must show <strong>strictly increasing ratings</strong> (each review better than the previous)</li>\n\t<li>Use the most recent <code>3</code> reviews based on <code>review_date</code> for each employee</li>\n\t<li>Calculate the <strong>improvement score</strong> as the difference between the latest rating and the earliest rating among the last <code>3</code> reviews</li>\n</ul>\n\n<p>Return <em>the result table ordered by <strong>improvement score</strong> in <strong>descending</strong> order, then by <strong>name</strong> in <strong>ascending</strong> order</em>.</p>\n\n<p>The result format is in the following example.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong></p>\n\n<p>employees table:</p>\n\n<pre class=\"example-io\">\n+-------------+----------------+\n| employee_id | name |\n+-------------+----------------+\n| 1 | Alice Johnson |\n| 2 | Bob Smith |\n| 3 | Carol Davis |\n| 4 | David Wilson |\n| 5 | Emma Brown |\n+-------------+----------------+\n</pre>\n\n<p>performance_reviews table:</p>\n\n<pre class=\"example-io\">\n+-----------+-------------+-------------+--------+\n| review_id | employee_id | review_date | rating |\n+-----------+-------------+-------------+--------+\n| 1 | 1 | 2023-01-15 | 2 |\n| 2 | 1 | 2023-04-15 | 3 |\n| 3 | 1 | 2023-07-15 | 4 |\n| 4 | 1 | 2023-10-15 | 5 |\n| 5 | 2 | 2023-02-01 | 3 |\n| 6 | 2 | 2023-05-01 | 2 |\n| 7 | 2 | 2023-08-01 | 4 |\n| 8 | 2 | 2023-11-01 | 5 |\n| 9 | 3 | 2023-03-10 | 1 |\n| 10 | 3 | 2023-06-10 | 2 |\n| 11 | 3 | 2023-09-10 | 3 |\n| 12 | 3 | 2023-12-10 | 4 |\n| 13 | 4 | 2023-01-20 | 4 |\n| 14 | 4 | 2023-04-20 | 4 |\n| 15 | 4 | 2023-07-20 | 4 |\n| 16 | 5 | 2023-02-15 | 3 |\n| 17 | 5 | 2023-05-15 | 2 |\n+-----------+-------------+-------------+--------+\n</pre>\n\n<p><strong>Output:</strong></p>\n\n<pre class=\"example-io\">\n+-------------+----------------+-------------------+\n| employee_id | name | improvement_score |\n+-------------+----------------+-------------------+\n| 2 | Bob Smith | 3 |\n| 1 | Alice Johnson | 2 |\n| 3 | Carol Davis | 2 |\n+-------------+----------------+-------------------+\n</pre>\n\n<p><strong>Explanation:</strong></p>\n\n<ul>\n\t<li><strong>Alice Johnson (employee_id = 1):</strong>\n\n\t<ul>\n\t\t<li>Has 4 reviews with ratings: 2, 3, 4, 5</li>\n\t\t<li>Last 3 reviews (by date): 2023-04-15 (3), 2023-07-15 (4), 2023-10-15 (5)</li>\n\t\t<li>Ratings are strictly increasing: 3 → 4 → 5</li>\n\t\t<li>Improvement score: 5 - 3 = 2</li>\n\t</ul>\n\t</li>\n\t<li><strong>Carol Davis (employee_id = 3):</strong>\n\t<ul>\n\t\t<li>Has 4 reviews with ratings: 1, 2, 3, 4</li>\n\t\t<li>Last 3 reviews (by date): 2023-06-10 (2), 2023-09-10 (3), 2023-12-10 (4)</li>\n\t\t<li>Ratings are strictly increasing: 2 → 3 → 4</li>\n\t\t<li>Improvement score: 4 - 2 = 2</li>\n\t</ul>\n\t</li>\n\t<li><strong>Bob Smith (employee_id = 2):</strong>\n\t<ul>\n\t\t<li>Has 4 reviews with ratings: 3, 2, 4, 5</li>\n\t\t<li>Last 3 reviews (by date): 2023-05-01 (2), 2023-08-01 (4), 2023-11-01 (5)</li>\n\t\t<li>Ratings are strictly increasing: 2 → 4 → 5</li>\n\t\t<li>Improvement score: 5 - 2 = 3</li>\n\t</ul>\n\t</li>\n\t<li><strong>Employees not included:</strong>\n\t<ul>\n\t\t<li>David Wilson (employee_id = 4): Last 3 reviews are all 4 (no improvement)</li>\n\t\t<li>Emma Brown (employee_id = 5): Only has 2 reviews (needs at least 3)</li>\n\t</ul>\n\t</li>\n</ul>\n\n<p>The output table is ordered by improvement_score in descending order, then by name in ascending order.</p>\n</div>\n",
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"translatedTitle": "寻找持续进步的员工",
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"translatedContent": "<p>表：<code>employees</code></p>\n\n<pre>\n+-------------+---------+\n| Column Name | Type |\n+-------------+---------+\n| employee_id | int |\n| name | varchar |\n+-------------+---------+\nemployee_id 是这张表的唯一主键。\n每一行包含一名员工的信息。\n</pre>\n\n<p>表：<code>performance_reviews</code></p>\n\n<pre>\n+-------------+------+\n| Column Name | Type |\n+-------------+------+\n| review_id | int |\n| employee_id | int |\n| review_date | date |\n| rating | int |\n+-------------+------+\nreview_id 是这张表的唯一主键。\n每一行表示一名员工的绩效评估。评分在 1-5 的范围内，5分代表优秀，1分代表较差。\n</pre>\n\n<p>编写一个解决方案，以找到在过去三次评估中持续提高绩效的员工。</p>\n\n<ul>\n\t<li>员工 <strong>至少需要</strong> <code>3</code> <strong>次评估 </strong>才能被考虑</li>\n\t<li>员工过去的 <code>3</code> 次评估，评分必须 <strong>严格递增</strong>（每次评价都比上一次好）</li>\n\t<li>根据 <code>review_date</code> 为每位员工分析最近的 <code>3</code> 次评估</li>\n\t<li><strong>进步分数</strong> 为最后 <code>3</code> 次评估中最后一次评分与最早一次评分之间的差值</li>\n</ul>\n\n<p>返回结果表以<em> </em><strong>进步分数 降序</strong> 排序，然后以 <strong>名字</strong> <strong>升序</strong> 排序。</p>\n\n<p>结果格式如下所示。</p>\n\n<p> </p>\n\n<p><strong class=\"example\">示例：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong></p>\n\n<p>employees 表：</p>\n\n<pre class=\"example-io\">\n+-------------+----------------+\n| employee_id | name |\n+-------------+----------------+\n| 1 | Alice Johnson |\n| 2 | Bob Smith |\n| 3 | Carol Davis |\n| 4 | David Wilson |\n| 5 | Emma Brown |\n+-------------+----------------+\n</pre>\n\n<p>performance_reviews 表：</p>\n\n<pre class=\"example-io\">\n+-----------+-------------+-------------+--------+\n| review_id | employee_id | review_date | rating |\n+-----------+-------------+-------------+--------+\n| 1 | 1 | 2023-01-15 | 2 |\n| 2 | 1 | 2023-04-15 | 3 |\n| 3 | 1 | 2023-07-15 | 4 |\n| 4 | 1 | 2023-10-15 | 5 |\n| 5 | 2 | 2023-02-01 | 3 |\n| 6 | 2 | 2023-05-01 | 2 |\n| 7 | 2 | 2023-08-01 | 4 |\n| 8 | 2 | 2023-11-01 | 5 |\n| 9 | 3 | 2023-03-10 | 1 |\n| 10 | 3 | 2023-06-10 | 2 |\n| 11 | 3 | 2023-09-10 | 3 |\n| 12 | 3 | 2023-12-10 | 4 |\n| 13 | 4 | 2023-01-20 | 4 |\n| 14 | 4 | 2023-04-20 | 4 |\n| 15 | 4 | 2023-07-20 | 4 |\n| 16 | 5 | 2023-02-15 | 3 |\n| 17 | 5 | 2023-05-15 | 2 |\n+-----------+-------------+-------------+--------+\n</pre>\n\n<p><strong>输出：</strong></p>\n\n<pre class=\"example-io\">\n+-------------+----------------+-------------------+\n| employee_id | name | improvement_score |\n+-------------+----------------+-------------------+\n| 2 | Bob Smith | 3 |\n| 1 | Alice Johnson | 2 |\n| 3 | Carol Davis | 2 |\n+-------------+----------------+-------------------+\n</pre>\n\n<p><strong>解释：</strong></p>\n\n<ul>\n\t<li><strong>Alice Johnson (employee_id = 1)：</strong>\n\n\t<ul>\n\t\t<li>有 4 次评估，分数：2, 3, 4, 5</li>\n\t\t<li>最后 3 次评估（按日期）：2023-04-15 (3), 2023-07-15 (4), 2023-10-15 (5)</li>\n\t\t<li>评分严格递增：3 → 4 → 5</li>\n\t\t<li>进步分数：5 - 3 = 2</li>\n\t</ul>\n\t</li>\n\t<li><strong>Carol Davis (employee_id = 3)：</strong>\n\t<ul>\n\t\t<li>有 4 次评估，分数：1, 2, 3, 4</li>\n\t\t<li>最后 3 次评估（按日期）：2023-06-10 (2)，2023-09-10 (3)，2023-12-10 (4)</li>\n\t\t<li>评分严格递增：2 → 3 → 4</li>\n\t\t<li>进步分数：4 - 2 = 2</li>\n\t</ul>\n\t</li>\n\t<li><strong>Bob Smith (employee_id = 2)：</strong>\n\t<ul>\n\t\t<li>有 4 次评估，分数：3，2，4，5</li>\n\t\t<li>最后 3 次评估（按日期）：2023-05-01 (2)，2023-08-01 (4)，2023-11-01 (5)</li>\n\t\t<li>评分严格递增：2 → 4 → 5</li>\n\t\t<li>进步分数：5 - 2 = 3</li>\n\t</ul>\n\t</li>\n\t<li><strong>未包含的员工：</strong>\n\t<ul>\n\t\t<li>David Wilson (employee_id = 4)：之前 3 次评估都是 4 分（没有进步）</li>\n\t\t<li>Emma Brown (employee_id = 5)：只有 2 次评估（需要至少 3 次）</li>\n\t</ul>\n\t</li>\n</ul>\n\n<p>输出表以 improvement_score 降序排序，然后以 name 升序排序。</p>\n</div>\n",
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"sampleTestCase": "{\"headers\":{\"employees\":[\"employee_id\",\"name\"],\"performance_reviews\":[\"review_id\",\"employee_id\",\"review_date\",\"rating\"]},\"rows\":{\"employees\":[[1,\"Alice Johnson\"],[2,\"Bob Smith\"],[3,\"Carol Davis\"],[4,\"David Wilson\"],[5,\"Emma Brown\"]],\"performance_reviews\":[[1,1,\"2023-01-15\",2],[2,1,\"2023-04-15\",3],[3,1,\"2023-07-15\",4],[4,1,\"2023-10-15\",5],[5,2,\"2023-02-01\",3],[6,2,\"2023-05-01\",2],[7,2,\"2023-08-01\",4],[8,2,\"2023-11-01\",5],[9,3,\"2023-03-10\",1],[10,3,\"2023-06-10\",2],[11,3,\"2023-09-10\",3],[12,3,\"2023-12-10\",4],[13,4,\"2023-01-20\",4],[14,4,\"2023-04-20\",4],[15,4,\"2023-07-20\",4],[16,5,\"2023-02-15\",3],[17,5,\"2023-05-15\",2]]}}",
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"metaData": "{\"mysql\":[\"CREATE TABLE employees (\\n employee_id INT,\\n name VARCHAR(255)\\n)\",\"CREATE TABLE performance_reviews (\\n review_id INT,\\n employee_id INT,\\n review_date DATE,\\n rating INT\\n)\"],\"mssql\":[\"CREATE TABLE employees (\\n employee_id INT,\\n name VARCHAR(255)\\n)\",\"CREATE TABLE performance_reviews (\\n review_id INT,\\n employee_id INT,\\n review_date DATE,\\n rating INT\\n)\"],\"oraclesql\":[\"CREATE TABLE employees (\\n employee_id NUMBER,\\n name VARCHAR2(255)\\n)\",\"CREATE TABLE performance_reviews (\\n review_id NUMBER,\\n employee_id NUMBER,\\n review_date DATE,\\n rating NUMBER\\n)\",\"ALTER SESSION SET nls_date_format='YYYY-MM-DD'\"],\"database\":true,\"name\":\"find_consistently_improving_employees\",\"postgresql\":[\"CREATE TABLE employees (\\n employee_id INTEGER,\\n name VARCHAR(255)\\n);\\n\",\"CREATE TABLE performance_reviews (\\n review_id INTEGER,\\n employee_id INTEGER,\\n review_date DATE,\\n rating NUMERIC\\n);\\n\"],\"pythondata\":[\"employees = pd.DataFrame({\\n 'employee_id': pd.Series(dtype='int'),\\n 'name': pd.Series(dtype='str')\\n})\",\"performance_reviews = pd.DataFrame({\\n 'review_id': pd.Series(dtype='int'),\\n 'employee_id': pd.Series(dtype='int'),\\n 'review_date': pd.Series(dtype='datetime64[ns]'),\\n 'rating': pd.Series(dtype='float') # Use float to accommodate decimal ratings\\n})\"],\"database_schema\":{\"employees\":{\"employee_id\":\"INT\",\"name\":\"VARCHAR(255)\"},\"performance_reviews\":{\"review_id\":\"INT\",\"employee_id\":\"INT\",\"review_date\":\"DATE\",\"rating\":\"INT\"}}}",
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"CREATE TABLE employees (\n employee_id INT,\n name VARCHAR(255)\n)",
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"CREATE TABLE performance_reviews (\n review_id INT,\n employee_id INT,\n review_date DATE,\n rating INT\n)",
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"Truncate table employees",
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"insert into employees (employee_id, name) values ('1', 'Alice Johnson')",
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"insert into employees (employee_id, name) values ('2', 'Bob Smith')",
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"insert into employees (employee_id, name) values ('3', 'Carol Davis')",
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"insert into employees (employee_id, name) values ('4', 'David Wilson')",
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"insert into employees (employee_id, name) values ('5', 'Emma Brown')",
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"Truncate table performance_reviews",
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"insert into performance_reviews (review_id, employee_id, review_date, rating) values ('1', '1', '2023-01-15', '2')",
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"insert into performance_reviews (review_id, employee_id, review_date, rating) values ('2', '1', '2023-04-15', '3')",
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"insert into performance_reviews (review_id, employee_id, review_date, rating) values ('3', '1', '2023-07-15', '4')",
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"insert into performance_reviews (review_id, employee_id, review_date, rating) values ('4', '1', '2023-10-15', '5')",
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"insert into performance_reviews (review_id, employee_id, review_date, rating) values ('5', '2', '2023-02-01', '3')",
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"insert into performance_reviews (review_id, employee_id, review_date, rating) values ('6', '2', '2023-05-01', '2')",
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"insert into performance_reviews (review_id, employee_id, review_date, rating) values ('7', '2', '2023-08-01', '4')",
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"insert into performance_reviews (review_id, employee_id, review_date, rating) values ('8', '2', '2023-11-01', '5')",
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"insert into performance_reviews (review_id, employee_id, review_date, rating) values ('9', '3', '2023-03-10', '1')",
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"insert into performance_reviews (review_id, employee_id, review_date, rating) values ('10', '3', '2023-06-10', '2')",
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"insert into performance_reviews (review_id, employee_id, review_date, rating) values ('11', '3', '2023-09-10', '3')",
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"insert into performance_reviews (review_id, employee_id, review_date, rating) values ('12', '3', '2023-12-10', '4')",
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"insert into performance_reviews (review_id, employee_id, review_date, rating) values ('13', '4', '2023-01-20', '4')",
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"insert into performance_reviews (review_id, employee_id, review_date, rating) values ('14', '4', '2023-04-20', '4')",
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"insert into performance_reviews (review_id, employee_id, review_date, rating) values ('15', '4', '2023-07-20', '4')",
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"insert into performance_reviews (review_id, employee_id, review_date, rating) values ('16', '5', '2023-02-15', '3')",
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"insert into performance_reviews (review_id, employee_id, review_date, rating) values ('17', '5', '2023-05-15', '2')"
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