mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-11 02:58:13 +08:00
48 lines
1.5 KiB
HTML
48 lines
1.5 KiB
HTML
<p>An integer <code>x</code> is <strong>numerically balanced</strong> if for every digit <code>d</code> in the number <code>x</code>, there are <strong>exactly</strong> <code>d</code> occurrences of that digit in <code>x</code>.</p>
|
|
|
|
<p>Given an integer <code>n</code>, return <em>the <strong>smallest numerically balanced</strong> number <strong>strictly greater</strong> than </em><code>n</code><em>.</em></p>
|
|
|
|
<p> </p>
|
|
<p><strong>Example 1:</strong></p>
|
|
|
|
<pre>
|
|
<strong>Input:</strong> n = 1
|
|
<strong>Output:</strong> 22
|
|
<strong>Explanation:</strong>
|
|
22 is numerically balanced since:
|
|
- The digit 2 occurs 2 times.
|
|
It is also the smallest numerically balanced number strictly greater than 1.
|
|
</pre>
|
|
|
|
<p><strong>Example 2:</strong></p>
|
|
|
|
<pre>
|
|
<strong>Input:</strong> n = 1000
|
|
<strong>Output:</strong> 1333
|
|
<strong>Explanation:</strong>
|
|
1333 is numerically balanced since:
|
|
- The digit 1 occurs 1 time.
|
|
- The digit 3 occurs 3 times.
|
|
It is also the smallest numerically balanced number strictly greater than 1000.
|
|
Note that 1022 cannot be the answer because 0 appeared more than 0 times.
|
|
</pre>
|
|
|
|
<p><strong>Example 3:</strong></p>
|
|
|
|
<pre>
|
|
<strong>Input:</strong> n = 3000
|
|
<strong>Output:</strong> 3133
|
|
<strong>Explanation:</strong>
|
|
3133 is numerically balanced since:
|
|
- The digit 1 occurs 1 time.
|
|
- The digit 3 occurs 3 times.
|
|
It is also the smallest numerically balanced number strictly greater than 3000.
|
|
</pre>
|
|
|
|
<p> </p>
|
|
<p><strong>Constraints:</strong></p>
|
|
|
|
<ul>
|
|
<li><code>0 <= n <= 10<sup>6</sup></code></li>
|
|
</ul>
|