mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-10 18:48:13 +08:00
53 lines
2.8 KiB
HTML
53 lines
2.8 KiB
HTML
<p>Given an <code>m x n</code> grid. Each cell of the grid has a sign pointing to the next cell you should visit if you are currently in this cell. The sign of <code>grid[i][j]</code> can be:</p>
|
|
|
|
<ul>
|
|
<li><code>1</code> which means go to the cell to the right. (i.e go from <code>grid[i][j]</code> to <code>grid[i][j + 1]</code>)</li>
|
|
<li><code>2</code> which means go to the cell to the left. (i.e go from <code>grid[i][j]</code> to <code>grid[i][j - 1]</code>)</li>
|
|
<li><code>3</code> which means go to the lower cell. (i.e go from <code>grid[i][j]</code> to <code>grid[i + 1][j]</code>)</li>
|
|
<li><code>4</code> which means go to the upper cell. (i.e go from <code>grid[i][j]</code> to <code>grid[i - 1][j]</code>)</li>
|
|
</ul>
|
|
|
|
<p>Notice that there could be some signs on the cells of the grid that point outside the grid.</p>
|
|
|
|
<p>You will initially start at the upper left cell <code>(0, 0)</code>. A valid path in the grid is a path that starts from the upper left cell <code>(0, 0)</code> and ends at the bottom-right cell <code>(m - 1, n - 1)</code> following the signs on the grid. The valid path does not have to be the shortest.</p>
|
|
|
|
<p>You can modify the sign on a cell with <code>cost = 1</code>. You can modify the sign on a cell <strong>one time only</strong>.</p>
|
|
|
|
<p>Return <em>the minimum cost to make the grid have at least one valid path</em>.</p>
|
|
|
|
<p> </p>
|
|
<p><strong>Example 1:</strong></p>
|
|
<img alt="" src="https://assets.leetcode.com/uploads/2020/02/13/grid1.png" style="width: 400px; height: 390px;" />
|
|
<pre>
|
|
<strong>Input:</strong> grid = [[1,1,1,1],[2,2,2,2],[1,1,1,1],[2,2,2,2]]
|
|
<strong>Output:</strong> 3
|
|
<strong>Explanation:</strong> You will start at point (0, 0).
|
|
The path to (3, 3) is as follows. (0, 0) --> (0, 1) --> (0, 2) --> (0, 3) change the arrow to down with cost = 1 --> (1, 3) --> (1, 2) --> (1, 1) --> (1, 0) change the arrow to down with cost = 1 --> (2, 0) --> (2, 1) --> (2, 2) --> (2, 3) change the arrow to down with cost = 1 --> (3, 3)
|
|
The total cost = 3.
|
|
</pre>
|
|
|
|
<p><strong>Example 2:</strong></p>
|
|
<img alt="" src="https://assets.leetcode.com/uploads/2020/02/13/grid2.png" style="width: 350px; height: 341px;" />
|
|
<pre>
|
|
<strong>Input:</strong> grid = [[1,1,3],[3,2,2],[1,1,4]]
|
|
<strong>Output:</strong> 0
|
|
<strong>Explanation:</strong> You can follow the path from (0, 0) to (2, 2).
|
|
</pre>
|
|
|
|
<p><strong>Example 3:</strong></p>
|
|
<img alt="" src="https://assets.leetcode.com/uploads/2020/02/13/grid3.png" style="width: 200px; height: 192px;" />
|
|
<pre>
|
|
<strong>Input:</strong> grid = [[1,2],[4,3]]
|
|
<strong>Output:</strong> 1
|
|
</pre>
|
|
|
|
<p> </p>
|
|
<p><strong>Constraints:</strong></p>
|
|
|
|
<ul>
|
|
<li><code>m == grid.length</code></li>
|
|
<li><code>n == grid[i].length</code></li>
|
|
<li><code>1 <= m, n <= 100</code></li>
|
|
<li><code>1 <= grid[i][j] <= 4</code></li>
|
|
</ul>
|