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leetcode-problemset/leetcode/problem/maximum-score-from-removing-stones.html
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<p>You are playing a solitaire game with <strong>three piles</strong> of stones of sizes <code>a</code>, <code>b</code>, and <code>c</code> respectively. Each turn you choose two <strong>different non-empty </strong>piles, take one stone from each, and add <code>1</code> point to your score. The game stops when there are <strong>fewer than two non-empty</strong> piles (meaning there are no more available moves).</p>
<p>Given three integers <code>a</code>, <code>b</code>, and <code>c</code>, return <em>the</em> <strong><em>maximum</em> </strong><em><strong>score</strong> you can get.</em></p>
<p>&nbsp;</p>
<p><strong>Example 1:</strong></p>
<pre>
<strong>Input:</strong> a = 2, b = 4, c = 6
<strong>Output:</strong> 6
<strong>Explanation:</strong> The starting state is (2, 4, 6). One optimal set of moves is:
- Take from 1st and 3rd piles, state is now (1, 4, 5)
- Take from 1st and 3rd piles, state is now (0, 4, 4)
- Take from 2nd and 3rd piles, state is now (0, 3, 3)
- Take from 2nd and 3rd piles, state is now (0, 2, 2)
- Take from 2nd and 3rd piles, state is now (0, 1, 1)
- Take from 2nd and 3rd piles, state is now (0, 0, 0)
There are fewer than two non-empty piles, so the game ends. Total: 6 points.
</pre>
<p><strong>Example 2:</strong></p>
<pre>
<strong>Input:</strong> a = 4, b = 4, c = 6
<strong>Output:</strong> 7
<strong>Explanation:</strong> The starting state is (4, 4, 6). One optimal set of moves is:
- Take from 1st and 2nd piles, state is now (3, 3, 6)
- Take from 1st and 3rd piles, state is now (2, 3, 5)
- Take from 1st and 3rd piles, state is now (1, 3, 4)
- Take from 1st and 3rd piles, state is now (0, 3, 3)
- Take from 2nd and 3rd piles, state is now (0, 2, 2)
- Take from 2nd and 3rd piles, state is now (0, 1, 1)
- Take from 2nd and 3rd piles, state is now (0, 0, 0)
There are fewer than two non-empty piles, so the game ends. Total: 7 points.
</pre>
<p><strong>Example 3:</strong></p>
<pre>
<strong>Input:</strong> a = 1, b = 8, c = 8
<strong>Output:</strong> 8
<strong>Explanation:</strong> One optimal set of moves is to take from the 2nd and 3rd piles for 8 turns until they are empty.
After that, there are fewer than two non-empty piles, so the game ends.
</pre>
<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>
<ul>
<li><code>1 &lt;= a, b, c &lt;= 10<sup>5</sup></code></li>
</ul>