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"question": {
"questionId": "3317",
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"categoryTitle": "Algorithms",
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"title": "Maximum Palindromes After Operations",
"titleSlug": "maximum-palindromes-after-operations",
"content": "<p>You are given a <strong>0-indexed</strong> string array <code>words</code> having length <code>n</code> and containing <strong>0-indexed</strong> strings.</p>\n\n<p>You are allowed to perform the following operation <strong>any</strong> number of times (<strong>including</strong> <strong>zero</strong>):</p>\n\n<ul>\n\t<li>Choose integers <code>i</code>, <code>j</code>, <code>x</code>, and <code>y</code> such that <code>0 &lt;= i, j &lt; n</code>, <code>0 &lt;= x &lt; words[i].length</code>, <code>0 &lt;= y &lt; words[j].length</code>, and <strong>swap</strong> the characters <code>words[i][x]</code> and <code>words[j][y]</code>.</li>\n</ul>\n\n<p>Return <em>an integer denoting the <strong>maximum</strong> number of <span data-keyword=\"palindrome-string\">palindromes</span> </em><code>words</code><em> can contain, after performing some operations.</em></p>\n\n<p><strong>Note:</strong> <code>i</code> and <code>j</code> may be equal during an operation.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> words = [&quot;abbb&quot;,&quot;ba&quot;,&quot;aa&quot;]\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> In this example, one way to get the maximum number of palindromes is:\nChoose i = 0, j = 1, x = 0, y = 0, so we swap words[0][0] and words[1][0]. words becomes [&quot;bbbb&quot;,&quot;aa&quot;,&quot;aa&quot;].\nAll strings in words are now palindromes.\nHence, the maximum number of palindromes achievable is 3.</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> words = [&quot;abc&quot;,&quot;ab&quot;]\n<strong>Output:</strong> 2\n<strong>Explanation: </strong>In this example, one way to get the maximum number of palindromes is: \nChoose i = 0, j = 1, x = 1, y = 0, so we swap words[0][1] and words[1][0]. words becomes [&quot;aac&quot;,&quot;bb&quot;].\nChoose i = 0, j = 0, x = 1, y = 2, so we swap words[0][1] and words[0][2]. words becomes [&quot;aca&quot;,&quot;bb&quot;].\nBoth strings are now palindromes.\nHence, the maximum number of palindromes achievable is 2.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> words = [&quot;cd&quot;,&quot;ef&quot;,&quot;a&quot;]\n<strong>Output:</strong> 1\n<strong>Explanation:</strong> In this example, there is no need to perform any operation.\nThere is one palindrome in words &quot;a&quot;.\nIt can be shown that it is not possible to get more than one palindrome after any number of operations.\nHence, the answer is 1.</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= words.length &lt;= 1000</code></li>\n\t<li><code>1 &lt;= words[i].length &lt;= 100</code></li>\n\t<li><code>words[i]</code> consists only of lowercase English letters.</li>\n</ul>\n",
"translatedTitle": "回文字符串的最大数量",
"translatedContent": "<p>给你一个下标从 <strong>0</strong> 开始的字符串数组 <code>words</code> ,数组的长度为 <code>n</code> ,且包含下标从 <strong>0</strong> 开始的若干字符串。</p>\n\n<p>你可以执行以下操作 <strong>任意 </strong>次数(<strong>包括零次</strong></p>\n\n<ul>\n\t<li>选择整数<code>i</code>、<code>j</code>、<code>x</code>和<code>y</code>,满足<code>0 &lt;= i, j &lt; n</code><code>0 &lt;= x &lt; words[i].length</code><code>0 &lt;= y &lt; words[j].length</code><strong>交换 </strong>字符 <code>words[i][x]</code> 和 <code>words[j][y]</code> 。</li>\n</ul>\n\n<p>返回一个整数,表示在执行一些操作后,<code>words</code> 中可以包含的回文字符串的 <strong>最大 </strong>数量。</p>\n\n<p><strong>注意:</strong>在操作过程中,<code>i</code> 和 <code>j</code> 可以相等。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>words = [\"abbb\",\"ba\",\"aa\"]\n<strong>输出:</strong>3\n<strong>解释:</strong>在这个例子中,获得最多回文字符串的一种方式是:\n选择 i = 0, j = 1, x = 0, y = 0交换 words[0][0] 和 words[1][0] 。words 变成了 [\"bbbb\",\"aa\",\"aa\"] 。\nwords 中的所有字符串都是回文。\n因此可实现的回文字符串的最大数量是 3 。\n</pre>\n\n<p><strong class=\"example\">示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>words = [\"abc\",\"ab\"]\n<strong>输出:</strong>2\n<strong>解释:</strong>在这个例子中,获得最多回文字符串的一种方式是: \n选择 i = 0, j = 1, x = 1, y = 0交换 words[0][1] 和 words[1][0] 。words 变成了 [\"aac\",\"bb\"] 。\n选择 i = 0, j = 0, x = 1, y = 2交换 words[0][1] 和 words[0][2] 。words 变成了 [\"aca\",\"bb\"] 。\n两个字符串都是回文 。\n因此可实现的回文字符串的最大数量是 2。\n</pre>\n\n<p><strong class=\"example\">示例 3</strong></p>\n\n<pre>\n<strong>输入:</strong>words = [\"cd\",\"ef\",\"a\"]\n<strong>输出:</strong>1\n<strong>解释:</strong>在这个例子中,没有必要执行任何操作。\nwords 中有一个回文 \"a\" 。\n可以证明在执行任何次数操作后无法得到更多回文。\n因此答案是 1 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= words.length &lt;= 1000</code></li>\n\t<li><code>1 &lt;= words[i].length &lt;= 100</code></li>\n\t<li><code>words[i]</code> 仅由小写英文字母组成。</li>\n</ul>\n",
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"hints": [
"We can redistribute all the letters freely among the words.",
"Calculate the frequency of each letter and total the number of matching letter pairs that can be formed from the letters, i.e., <code>total = sum(freq[ch] / 2)</code> for all <code>'a' <= ch <= 'z'</code>.",
"We can greedily try making palindromes from <code>words[i]</code> with the smallest length to <code>words[i]</code> with the longest length.",
"For the current index, <code>i</code>, we try to make <code>words[i]</code> a palindrome. We need <code>len(words[i]) / 2</code> matching character pairs, and the letter in the middle (if it exists) can be freely chosen afterward.",
"We can check if we have enough pairs for index <code>i</code>; if we do, we increase the number of palindromes we can make and decrease the number of pairs we have. Otherwise, we end the loop at this index.",
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