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leetcode-problemset/leetcode-cn/originData/sum-of-scores-of-built-strings.json
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"question": {
"questionId": "2326",
"questionFrontendId": "2223",
"categoryTitle": "Algorithms",
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"title": "Sum of Scores of Built Strings",
"titleSlug": "sum-of-scores-of-built-strings",
"content": "<p>You are <strong>building</strong> a string <code>s</code> of length <code>n</code> <strong>one</strong> character at a time, <strong>prepending</strong> each new character to the <strong>front</strong> of the string. The strings are labeled from <code>1</code> to <code>n</code>, where the string with length <code>i</code> is labeled <code>s<sub>i</sub></code>.</p>\n\n<ul>\n\t<li>For example, for <code>s = &quot;abaca&quot;</code>, <code>s<sub>1</sub> == &quot;a&quot;</code>, <code>s<sub>2</sub> == &quot;ca&quot;</code>, <code>s<sub>3</sub> == &quot;aca&quot;</code>, etc.</li>\n</ul>\n\n<p>The <strong>score</strong> of <code>s<sub>i</sub></code> is the length of the <strong>longest common prefix</strong> between <code>s<sub>i</sub></code> and <code>s<sub>n</sub></code> (Note that <code>s == s<sub>n</sub></code>).</p>\n\n<p>Given the final string <code>s</code>, return<em> the <strong>sum</strong> of the <strong>score</strong> of every </em><code>s<sub>i</sub></code>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;babab&quot;\n<strong>Output:</strong> 9\n<strong>Explanation:</strong>\nFor s<sub>1</sub> == &quot;b&quot;, the longest common prefix is &quot;b&quot; which has a score of 1.\nFor s<sub>2</sub> == &quot;ab&quot;, there is no common prefix so the score is 0.\nFor s<sub>3</sub> == &quot;bab&quot;, the longest common prefix is &quot;bab&quot; which has a score of 3.\nFor s<sub>4</sub> == &quot;abab&quot;, there is no common prefix so the score is 0.\nFor s<sub>5</sub> == &quot;babab&quot;, the longest common prefix is &quot;babab&quot; which has a score of 5.\nThe sum of the scores is 1 + 0 + 3 + 0 + 5 = 9, so we return 9.</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;azbazbzaz&quot;\n<strong>Output:</strong> 14\n<strong>Explanation:</strong> \nFor s<sub>2</sub> == &quot;az&quot;, the longest common prefix is &quot;az&quot; which has a score of 2.\nFor s<sub>6</sub> == &quot;azbzaz&quot;, the longest common prefix is &quot;azb&quot; which has a score of 3.\nFor s<sub>9</sub> == &quot;azbazbzaz&quot;, the longest common prefix is &quot;azbazbzaz&quot; which has a score of 9.\nFor all other s<sub>i</sub>, the score is 0.\nThe sum of the scores is 2 + 3 + 9 = 14, so we return 14.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>s</code> consists of lowercase English letters.</li>\n</ul>\n",
"translatedTitle": "构造字符串的总得分和",
"translatedContent": "<p>你需要从空字符串开始&nbsp;<strong>构造</strong> 一个长度为 <code>n</code>&nbsp;的字符串 <code>s</code>&nbsp;,构造的过程为每次给当前字符串 <strong>前面</strong>&nbsp;添加 <strong>一个</strong> 字符。构造过程中得到的所有字符串编号为 <code>1</code>&nbsp;到 <code>n</code>&nbsp;,其中长度为 <code>i</code>&nbsp;的字符串编号为 <code>s<sub>i</sub></code>&nbsp;。</p>\n\n<ul>\n\t<li>比方说,<code>s = \"abaca\"</code>&nbsp;<code>s<sub>1</sub> == \"a\"</code>&nbsp;<code>s<sub>2</sub> == \"ca\"</code>&nbsp;<code>s<sub>3</sub> == \"aca\"</code>&nbsp;依次类推。</li>\n</ul>\n\n<p><code>s<sub>i</sub></code>&nbsp;的 <strong>得分</strong>&nbsp;为&nbsp;<code>s<sub>i</sub></code> 和&nbsp;<code>s<sub>n</sub></code>&nbsp;的 <strong>最长公共前缀</strong> 的长度(注意&nbsp;<code>s == s<sub>n</sub></code>&nbsp;)。</p>\n\n<p>给你最终的字符串&nbsp;<code>s</code>&nbsp;,请你返回每一个<em>&nbsp;</em><code>s<sub>i</sub></code>&nbsp;的&nbsp;<strong>得分之和</strong>&nbsp;。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<b>输入:</b>s = \"babab\"\n<b>输出:</b>9\n<b>解释:</b>\ns<sub>1</sub> == \"b\" ,最长公共前缀是 \"b\" ,得分为 1 。\ns<sub>2</sub> == \"ab\" ,没有公共前缀,得分为 0 。\ns<sub>3</sub> == \"bab\" ,最长公共前缀为 \"bab\" ,得分为 3 。\ns<sub>4</sub> == \"abab\" ,没有公共前缀,得分为 0 。\ns<sub>5</sub> == \"babab\" ,最长公共前缀为 \"babab\" ,得分为 5 。\n得分和为 1 + 0 + 3 + 0 + 5 = 9 ,所以我们返回 9 。</pre>\n\n<p><strong>示例 2 </strong></p>\n\n<pre>\n<b>输入:</b>s = \"azbazbzaz\"\n<b>输出:</b>14\n<b>解释:</b>\ns<sub>2</sub> == \"az\" ,最长公共前缀为 \"az\" ,得分为 2 。\ns<sub>6</sub> == \"azbzaz\" ,最长公共前缀为 \"azb\" ,得分为 3 。\ns<sub>9</sub> == \"azbazbzaz\" ,最长公共前缀为 \"azbazbzaz\" ,得分为 9 。\n其他 s<sub>i</sub> 得分均为 0 。\n得分和为 2 + 3 + 9 = 14 ,所以我们返回 14 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>s</code>&nbsp;只包含小写英文字母。</li>\n</ul>\n",
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"Each s_i is a suffix of the string s, so consider algorithms that can determine the longest prefix that is also a suffix.",
"Could you use the Z array from the Z algorithm to find the score of each s_i?"
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