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leetcode-problemset/leetcode-cn/originData/route-between-nodes-lcci.json
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{
"data": {
"question": {
"questionId": "100171",
"questionFrontendId": "面试题 04.01",
"categoryTitle": "LCCI",
"boundTopicId": 46021,
"title": "Route Between Nodes LCCI",
"titleSlug": "route-between-nodes-lcci",
"content": "<p>Given a directed graph, design an algorithm to find out whether there is a route between two nodes.</p>\r\n\r\n<p><strong>Example1:</strong></p>\r\n\r\n<pre>\r\n<strong> Input</strong>: n = 3, graph = [[0, 1], [0, 2], [1, 2], [1, 2]], start = 0, target = 2\r\n<strong> Output</strong>: true\r\n</pre>\r\n\r\n<p><strong>Example2:</strong></p>\r\n\r\n<pre>\r\n<strong> Input</strong>: n = 5, graph = [[0, 1], [0, 2], [0, 4], [0, 4], [0, 1], [1, 3], [1, 4], [1, 3], [2, 3], [3, 4]], start = 0, target = 4\r\n<strong> Output</strong> true\r\n</pre>\r\n\r\n<p><strong>Note: </strong></p>\r\n\r\n<ol>\r\n\t<li><code>0 &lt;= n &lt;= 100000</code></li>\r\n\t<li>All node numbers are within the range [0, n].</li>\r\n\t<li>There might be self cycles and duplicated edges.</li>\r\n</ol>\r\n",
"translatedTitle": "节点间通路",
"translatedContent": "<p>节点间通路。给定有向图,设计一个算法,找出两个节点之间是否存在一条路径。</p>\n\n<p><strong>示例1:</strong></p>\n\n<pre><strong> 输入</strong>n = 3, graph = [[0, 1], [0, 2], [1, 2], [1, 2]], start = 0, target = 2\n<strong> 输出</strong>true\n</pre>\n\n<p><strong>示例2:</strong></p>\n\n<pre><strong> 输入</strong>n = 5, graph = [[0, 1], [0, 2], [0, 4], [0, 4], [0, 1], [1, 3], [1, 4], [1, 3], [2, 3], [3, 4]], start = 0, target = 4\n<strong> 输出</strong> true\n</pre>\n\n<p><strong>提示:</strong></p>\n\n<ol>\n\t<li>节点数量n在[0, 1e5]范围内。</li>\n\t<li>节点编号大于等于 0 小于 n。</li>\n\t<li>图中可能存在自环和平行边。</li>\n</ol>\n",
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"difficulty": "Medium",
"likes": 57,
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"name": "Depth-First Search",
"slug": "depth-first-search",
"translatedName": "深度优先搜索",
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"code": "class Solution {\npublic:\n bool findWhetherExistsPath(int n, vector<vector<int>>& graph, int start, int target) {\n\n }\n};",
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"code": "class Solution {\n public boolean findWhetherExistsPath(int n, int[][] graph, int start, int target) {\n\n }\n}",
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{
"lang": "Python",
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"code": "class Solution(object):\n def findWhetherExistsPath(self, n, graph, start, target):\n \"\"\"\n :type n: int\n :type graph: List[List[int]]\n :type start: int\n :type target: int\n :rtype: bool\n \"\"\"",
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"code": "class Solution:\n def findWhetherExistsPath(self, n: int, graph: List[List[int]], start: int, target: int) -> bool:",
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"code": "(define/contract (find-whether-exists-path n graph start target)\n (-> exact-integer? (listof (listof exact-integer?)) exact-integer? exact-integer? boolean?)\n\n )",
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"hints": [
"有两个众所周知的算法可以做到这一点。其利弊是什么?"
],
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