leetcode-problemset/leetcode-cn/originData/richest-customer-wealth.json

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            "categoryTitle": "Algorithms",
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            "title": "Richest Customer Wealth",
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            "content": "<p>You are given an <code>m x n</code> integer grid <code>accounts</code> where <code>accounts[i][j]</code> is the amount of money the <code>i​​​​​<sup>​​​​​​th</sup>​​​​</code> customer has in the <code>j​​​​​<sup>​​​​​​th</sup></code>​​​​ bank. Return<em> the <strong>wealth</strong> that the richest customer has.</em></p>\n\n<p>A customer&#39;s <strong>wealth</strong> is the amount of money they have in all their bank accounts. The richest customer is the customer that has the maximum <strong>wealth</strong>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> accounts = [[1,2,3],[3,2,1]]\n<strong>Output:</strong> 6\n<strong>Explanation</strong><strong>:</strong>\n<code>1st customer has wealth = 1 + 2 + 3 = 6\n</code><code>2nd customer has wealth = 3 + 2 + 1 = 6\n</code>Both customers are considered the richest with a wealth of 6 each, so return 6.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> accounts = [[1,5],[7,3],[3,5]]\n<strong>Output:</strong> 10\n<strong>Explanation</strong>: \n1st customer has wealth = 6\n2nd customer has wealth = 10 \n3rd customer has wealth = 8\nThe 2nd customer is the richest with a wealth of 10.</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> accounts = [[2,8,7],[7,1,3],[1,9,5]]\n<strong>Output:</strong> 17\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>m ==&nbsp;accounts.length</code></li>\n\t<li><code>n ==&nbsp;accounts[i].length</code></li>\n\t<li><code>1 &lt;= m, n &lt;= 50</code></li>\n\t<li><code>1 &lt;= accounts[i][j] &lt;= 100</code></li>\n</ul>\n",
            "translatedTitle": "最富有客户的资产总量",
            "translatedContent": "<p>给你一个 <code>m x n</code> 的整数网格 <code>accounts</code> ，其中 <code>accounts[i][j]</code> 是第 <code>i​​​​​<sup>​​​​​​</sup>​</code> 位客户在第 <code>j</code> 家银行托管的资产数量。返回最富有客户所拥有的 <strong>资产总量</strong> 。</p>\n\n<p>客户的 <strong>资产总量</strong> 就是他们在各家银行托管的资产数量之和。最富有客户就是 <strong>资产总量</strong> 最大的客户。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><strong>输入：</strong>accounts = [[1,2,3],[3,2,1]]\n<strong>输出：</strong>6\n<strong>解释：</strong>\n<code>第 1 位客户的资产总量 = 1 + 2 + 3 = 6\n第 2 位客户的资产总量 = 3 + 2 + 1 = 6\n</code>两位客户都是最富有的，资产总量都是 6 ，所以返回 6 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入：</strong>accounts = [[1,5],[7,3],[3,5]]\n<strong>输出：</strong>10\n<strong>解释：</strong>\n<code>第 1 位客户的资产总量</code> = 6\n<code>第 2 位客户的资产总量</code> = 10 \n<code>第 3 位客户的资产总量</code> = 8\n第 2 位客户是最富有的，资产总量是 10</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre><strong>输入：</strong>accounts = [[2,8,7],[7,1,3],[1,9,5]]\n<strong>输出：</strong>17\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>m == accounts.length</code></li>\n\t<li><code>n == accounts[i].length</code></li>\n\t<li><code>1 &lt;= m, n &lt;= 50</code></li>\n\t<li><code>1 &lt;= accounts[i][j] &lt;= 100</code></li>\n</ul>\n",
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