mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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199 lines
22 KiB
JSON
199 lines
22 KiB
JSON
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"questionFrontendId": "面试题 16.18",
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"categoryTitle": "LCCI",
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"boundTopicId": 91351,
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"title": "Pattern Matching LCCI",
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"content": "<p>You are given two strings, pattern and value. The pattern string consists of just the letters a and b, describing a pattern within a string. For example, the string catcatgocatgo matches the pattern aabab (where cat is a and go is b). It also matches patterns like a, ab, and b. Write a method to determine if value matches pattern. a and b cannot be the same string.</p>\r\n\r\n<p><strong>Example 1: </strong></p>\r\n\r\n<pre>\r\n<strong>Input: </strong> pattern = "abba", value = "dogcatcatdog"\r\n<strong>Output: </strong> true\r\n</pre>\r\n\r\n<p><strong>Example 2: </strong></p>\r\n\r\n<pre>\r\n<strong>Input: </strong> pattern = "abba", value = "dogcatcatfish"\r\n<strong>Output: </strong> false\r\n</pre>\r\n\r\n<p><strong>Example 3: </strong></p>\r\n\r\n<pre>\r\n<strong>Input: </strong> pattern = "aaaa", value = "dogcatcatdog"\r\n<strong>Output: </strong> false\r\n</pre>\r\n\r\n<p><strong>Example 4: </strong></p>\r\n\r\n<pre>\r\n<strong>Input: </strong> pattern = "abba", value = "dogdogdogdog"\r\n<strong>Output: </strong> true\r\n<strong>Explanation: </strong> "a"="dogdog",b="",vice versa.\r\n</pre>\r\n\r\n<p><strong>Note: </strong></p>\r\n\r\n<ul>\r\n\t<li><code>0 <= len(pattern) <= 1000</code></li>\r\n\t<li><code>0 <= len(value) <= 1000</code></li>\r\n\t<li><code>pattern</code> only contains <code>"a"</code> and <code>"b"</code>, <code>value</code> only contains lowercase letters.</li>\r\n</ul>\r\n",
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"translatedTitle": "模式匹配",
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"translatedContent": "<p>你有两个字符串,即<code>pattern</code>和<code>value</code>。 <code>pattern</code>字符串由字母<code>"a"</code>和<code>"b"</code>组成,用于描述字符串中的模式。例如,字符串<code>"catcatgocatgo"</code>匹配模式<code>"aabab"</code>(其中<code>"cat"</code>是<code>"a"</code>,<code>"go"</code>是<code>"b"</code>),该字符串也匹配像<code>"a"</code>、<code>"ab"</code>和<code>"b"</code>这样的模式。但需注意<code>"a"</code>和<code>"b"</code>不能同时表示相同的字符串。编写一个方法判断<code>value</code>字符串是否匹配<code>pattern</code>字符串。</p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre><strong>输入:</strong> pattern = "abba", value = "dogcatcatdog"\n<strong>输出:</strong> true\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre><strong>输入:</strong> pattern = "abba", value = "dogcatcatfish"\n<strong>输出:</strong> false\n</pre>\n\n<p><strong>示例 3:</strong></p>\n\n<pre><strong>输入:</strong> pattern = "aaaa", value = "dogcatcatdog"\n<strong>输出:</strong> false\n</pre>\n\n<p><strong>示例 4:</strong></p>\n\n<pre><strong>输入:</strong> pattern = "abba", value = "dogdogdogdog"\n<strong>输出:</strong> true\n<strong>解释:</strong> "a"="dogdog",b="",反之也符合规则\n</pre>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 <= len(pattern) <= 1000</code></li>\n\t<li><code>0 <= len(value) <= 1000</code></li>\n\t<li>你可以假设<code>pattern</code>只包含字母<code>"a"</code>和<code>"b"</code>,<code>value</code>仅包含小写字母。</li>\n</ul>\n",
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"hints": [
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"从蛮力解法开始。你能试一下a和b的所有可能性吗?",
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"观察其中一个子字符串,a或b都可以,必须从字符串的开头开始。这减少了可能性的种类。",
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"不要忘记处理pattern中的第一个字符是b的可能性。",
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"谨慎地选择分析时间复杂度的方式。如果遍历O(n2)个子字符串,每个子字符串都进行O(n)次的字符串比较,那么总体运行时间为O(n3)。",
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"假设你确定了一个模式中“a”部分的值。b有多少种可能性?",
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"由于a的值决定b的值(反之亦然),并且a或b必须出现于值的起始处,所以你应该只有O(n)种可能来分解模式串。",
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"你应该能够有一个O(n2)的算法。"
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