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"question": {
"questionId": "1000301",
"questionFrontendId": "剑指 Offer II 047",
"categoryTitle": "LCOF2",
"boundTopicId": 910295,
"title": "二叉树剪枝",
"titleSlug": "pOCWxh",
"content": "<p>English description is not available for the problem. Please switch to Chinese.</p>\n",
"translatedTitle": "二叉树剪枝",
"translatedContent": "<p>给定一个二叉树 <strong>根节点</strong>&nbsp;<code>root</code>&nbsp;,树的每个节点的值要么是 <code>0</code>,要么是 <code>1</code>。请剪除该二叉树中所有节点的值为 <code>0</code> 的子树。</p>\n\n<p>节点 <code>node</code> 的子树为&nbsp;<code>node</code> 本身,以及所有 <code>node</code>&nbsp;的后代。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre>\n<strong>输入:</strong> [1,null,0,0,1]\n<strong>输出: </strong>[1,null,0,null,1] \n<strong>解释:</strong> \n只有红色节点满足条件&ldquo;所有不包含 1 的子树&rdquo;。\n右图为返回的答案。\n\n<img alt=\"\" src=\"https://s3-lc-upload.s3.amazonaws.com/uploads/2018/04/06/1028_2.png\" style=\"width:450px\" />\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre>\n<strong>输入:</strong> [1,0,1,0,0,0,1]\n<strong>输出: </strong>[1,null,1,null,1]\n<strong>解释:</strong> \n\n<img alt=\"\" src=\"https://s3-lc-upload.s3.amazonaws.com/uploads/2018/04/06/1028_1.png\" style=\"width:450px\" />\n</pre>\n\n<p><strong>示例 3:</strong></p>\n\n<pre>\n<strong>输入:</strong> [1,1,0,1,1,0,1,0]\n<strong>输出: </strong>[1,1,0,1,1,null,1]\n<strong>解释:</strong> \n\n<img alt=\"\" src=\"https://s3-lc-upload.s3.amazonaws.com/uploads/2018/04/05/1028.png\" style=\"width:450px\" />\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li>二叉树的节点个数的范围是 <code>[1,200]</code></li>\n\t<li>二叉树节点的值只会是 <code>0</code> 或 <code>1</code></li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><meta charset=\"UTF-8\" />注意:本题与主站 814&nbsp;题相同:<a href=\"https://leetcode-cn.com/problems/binary-tree-pruning/\">https://leetcode-cn.com/problems/binary-tree-pruning/</a></p>\n",
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"code": "// Definition for a binary tree node.\n// #[derive(Debug, PartialEq, Eq)]\n// pub struct TreeNode {\n// pub val: i32,\n// pub left: Option<Rc<RefCell<TreeNode>>>,\n// pub right: Option<Rc<RefCell<TreeNode>>>,\n// }\n//\n// impl TreeNode {\n// #[inline]\n// pub fn new(val: i32) -> Self {\n// TreeNode {\n// val,\n// left: None,\n// right: None\n// }\n// }\n// }\nuse std::rc::Rc;\nuse std::cell::RefCell;\nimpl Solution {\n pub fn prune_tree(root: Option<Rc<RefCell<TreeNode>>>) -> Option<Rc<RefCell<TreeNode>>> {\n\n }\n}",
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