leetcode-problemset/leetcode-cn/originData/number-of-burgers-with-no-waste-of-ingredients.json

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        "question": {
            "questionId": "1401",
            "questionFrontendId": "1276",
            "categoryTitle": "Algorithms",
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            "title": "Number of Burgers with No Waste of Ingredients",
            "titleSlug": "number-of-burgers-with-no-waste-of-ingredients",
            "content": "<p>Given two integers <code>tomatoSlices</code> and <code>cheeseSlices</code>. The ingredients of different burgers are as follows:</p>\n\n<ul>\n\t<li><strong>Jumbo Burger:</strong> <code>4</code> tomato slices and <code>1</code> cheese slice.</li>\n\t<li><strong>Small Burger:</strong> <code>2</code> Tomato slices and <code>1</code> cheese slice.</li>\n</ul>\n\n<p>Return <code>[total_jumbo, total_small]</code> so that the number of remaining <code>tomatoSlices</code> equal to <code>0</code> and the number of remaining <code>cheeseSlices</code> equal to <code>0</code>. If it is not possible to make the remaining <code>tomatoSlices</code> and <code>cheeseSlices</code> equal to <code>0</code> return <code>[]</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> tomatoSlices = 16, cheeseSlices = 7\n<strong>Output:</strong> [1,6]\n<strong>Explantion:</strong> To make one jumbo burger and 6 small burgers we need 4*1 + 2*6 = 16 tomato and 1 + 6 = 7 cheese.\nThere will be no remaining ingredients.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> tomatoSlices = 17, cheeseSlices = 4\n<strong>Output:</strong> []\n<strong>Explantion:</strong> There will be no way to use all ingredients to make small and jumbo burgers.\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> tomatoSlices = 4, cheeseSlices = 17\n<strong>Output:</strong> []\n<strong>Explantion:</strong> Making 1 jumbo burger there will be 16 cheese remaining and making 2 small burgers there will be 15 cheese remaining.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>0 &lt;= tomatoSlices, cheeseSlices &lt;= 10<sup>7</sup></code></li>\n</ul>\n",
            "translatedTitle": "不浪费原料的汉堡制作方案",
            "translatedContent": "<p>圣诞活动预热开始啦，汉堡店推出了全新的汉堡套餐。为了避免浪费原料，请你帮他们制定合适的制作计划。</p>\n\n<p>给你两个整数&nbsp;<code>tomatoSlices</code>&nbsp;和&nbsp;<code>cheeseSlices</code>，分别表示番茄片和奶酪片的数目。不同汉堡的原料搭配如下：</p>\n\n<ul>\n\t<li><strong>巨无霸汉堡：</strong>4 片番茄和 1 片奶酪</li>\n\t<li><strong>小皇堡：</strong>2 片番茄和&nbsp;1 片奶酪</li>\n</ul>\n\n<p>请你以&nbsp;<code>[total_jumbo, total_small]</code>（[巨无霸汉堡总数，小皇堡总数]）的格式返回恰当的制作方案，使得剩下的番茄片&nbsp;<code>tomatoSlices</code>&nbsp;和奶酪片&nbsp;<code>cheeseSlices</code>&nbsp;的数量都是&nbsp;<code>0</code>。</p>\n\n<p>如果无法使剩下的番茄片&nbsp;<code>tomatoSlices</code>&nbsp;和奶酪片&nbsp;<code>cheeseSlices</code>&nbsp;的数量为&nbsp;<code>0</code>，就请返回&nbsp;<code>[]</code>。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><strong>输入：</strong>tomatoSlices = 16, cheeseSlices = 7\n<strong>输出：</strong>[1,6]\n<strong>解释：</strong>制作 1 个巨无霸汉堡和 6 个小皇堡需要 4*1 + 2*6 = 16 片番茄和 1 + 6 = 7 片奶酪。不会剩下原料。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入：</strong>tomatoSlices = 17, cheeseSlices = 4\n<strong>输出：</strong>[]\n<strong>解释：</strong>只制作小皇堡和巨无霸汉堡无法用光全部原料。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre><strong>输入：</strong>tomatoSlices = 4, cheeseSlices = 17\n<strong>输出：</strong>[]\n<strong>解释：</strong>制作 1 个巨无霸汉堡会剩下 16 片奶酪，制作 2 个小皇堡会剩下 15 片奶酪。\n</pre>\n\n<p><strong>示例 4：</strong></p>\n\n<pre><strong>输入：</strong>tomatoSlices = 0, cheeseSlices = 0\n<strong>输出：</strong>[0,0]\n</pre>\n\n<p><strong>示例 5：</strong></p>\n\n<pre><strong>输入：</strong>tomatoSlices = 2, cheeseSlices = 1\n<strong>输出：</strong>[0,1]\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>0 &lt;= tomatoSlices &lt;= 10^7</code></li>\n\t<li><code>0 &lt;= cheeseSlices &lt;= 10^7</code></li>\n</ul>\n",
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                    "lang": "C++",
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                    "code": "class Solution {\npublic:\n    vector<int> numOfBurgers(int tomatoSlices, int cheeseSlices) {\n\n    }\n};",
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                    "code": "class Solution(object):\n    def numOfBurgers(self, tomatoSlices, cheeseSlices):\n        \"\"\"\n        :type tomatoSlices: int\n        :type cheeseSlices: int\n        :rtype: List[int]\n        \"\"\"",
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            "hints": [
                "Can we have an answer if the number of tomatoes is odd ?",
                "If we have answer will be there multiple answers or just one answer ?",
                "Let us define number of jumbo burgers as X and number of small burgers as Y\r\nWe have to find an x and y in this equation",
                "1. 4X + 2Y = tomato",
                "2. X + Y = cheese"
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