leetcode-problemset/leetcode-cn/originData/maximum-number-of-removable-characters.json

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        "question": {
            "questionId": "2027",
            "questionFrontendId": "1898",
            "categoryTitle": "Algorithms",
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            "title": "Maximum Number of Removable Characters",
            "titleSlug": "maximum-number-of-removable-characters",
            "content": "<p>You are given two strings <code>s</code> and <code>p</code> where <code>p</code> is a <strong>subsequence </strong>of <code>s</code>. You are also given a <strong>distinct 0-indexed </strong>integer array <code>removable</code> containing a subset of indices of <code>s</code> (<code>s</code> is also <strong>0-indexed</strong>).</p>\n\n<p>You want to choose an integer <code>k</code> (<code>0 &lt;= k &lt;= removable.length</code>) such that, after removing <code>k</code> characters from <code>s</code> using the <strong>first</strong> <code>k</code> indices in <code>removable</code>, <code>p</code> is still a <strong>subsequence</strong> of <code>s</code>. More formally, you will mark the character at <code>s[removable[i]]</code> for each <code>0 &lt;= i &lt; k</code>, then remove all marked characters and check if <code>p</code> is still a subsequence.</p>\n\n<p>Return <em>the <strong>maximum</strong> </em><code>k</code><em> you can choose such that </em><code>p</code><em> is still a <strong>subsequence</strong> of </em><code>s</code><em> after the removals</em>.</p>\n\n<p>A <strong>subsequence</strong> of a string is a new string generated from the original string with some characters (can be none) deleted without changing the relative order of the remaining characters.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;abcacb&quot;, p = &quot;ab&quot;, removable = [3,1,0]\n<strong>Output:</strong> 2\n<strong>Explanation</strong>: After removing the characters at indices 3 and 1, &quot;a<s><strong>b</strong></s>c<s><strong>a</strong></s>cb&quot; becomes &quot;accb&quot;.\n&quot;ab&quot; is a subsequence of &quot;<strong><u>a</u></strong>cc<strong><u>b</u></strong>&quot;.\nIf we remove the characters at indices 3, 1, and 0, &quot;<s><strong>ab</strong></s>c<s><strong>a</strong></s>cb&quot; becomes &quot;ccb&quot;, and &quot;ab&quot; is no longer a subsequence.\nHence, the maximum k is 2.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;abcbddddd&quot;, p = &quot;abcd&quot;, removable = [3,2,1,4,5,6]\n<strong>Output:</strong> 1\n<strong>Explanation</strong>: After removing the character at index 3, &quot;abc<s><strong>b</strong></s>ddddd&quot; becomes &quot;abcddddd&quot;.\n&quot;abcd&quot; is a subsequence of &quot;<u><strong>abcd</strong></u>dddd&quot;.\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;abcab&quot;, p = &quot;abc&quot;, removable = [0,1,2,3,4]\n<strong>Output:</strong> 0\n<strong>Explanation</strong>: If you remove the first index in the array removable, &quot;abc&quot; is no longer a subsequence.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= p.length &lt;= s.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>0 &lt;= removable.length &lt; s.length</code></li>\n\t<li><code>0 &lt;= removable[i] &lt; s.length</code></li>\n\t<li><code>p</code> is a <strong>subsequence</strong> of <code>s</code>.</li>\n\t<li><code>s</code> and <code>p</code> both consist of lowercase English letters.</li>\n\t<li>The elements in <code>removable</code> are <strong>distinct</strong>.</li>\n</ul>\n",
            "translatedTitle": "可移除字符的最大数目",
            "translatedContent": "<p>给你两个字符串 <code>s</code> 和 <code>p</code> ，其中 <code>p</code> 是 <code>s</code> 的一个 <strong>子序列</strong> 。同时，给你一个元素 <strong>互不相同</strong> 且下标 <strong>从 0 开始</strong> 计数的整数数组 <code>removable</code> ，该数组是 <code>s</code> 中下标的一个子集（<code>s</code> 的下标也 <strong>从 0 开始</strong> 计数）。</p>\n\n<p>请你找出一个整数 <code>k</code>（<code>0 <= k <= removable.length</code>），选出 <code>removable</code> 中的 <strong>前</strong> <code>k</code> 个下标，然后从 <code>s</code> 中移除这些下标对应的 <code>k</code> 个字符。整数 <code>k</code> 需满足：在执行完上述步骤后， <code>p</code> 仍然是 <code>s</code> 的一个 <strong>子序列</strong> 。更正式的解释是，对于每个 <code>0 <= i < k</code> ，先标记出位于 <code>s[removable[i]]</code> 的字符，接着移除所有标记过的字符，然后检查 <code>p</code> 是否仍然是 <code>s</code> 的一个子序列。</p>\n\n<p>返回你可以找出的 <strong>最大</strong><em> </em><code>k</code><em> </em>，满足在移除字符后<em> </em><code>p</code><em> </em>仍然是 <code>s</code> 的一个子序列。</p>\n\n<p>字符串的一个 <strong>子序列</strong> 是一个由原字符串生成的新字符串，生成过程中可能会移除原字符串中的一些字符（也可能不移除）但不改变剩余字符之间的相对顺序。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"abcacb\", p = \"ab\", removable = [3,1,0]\n<strong>输出：</strong>2\n<strong>解释：</strong>在移除下标 3 和 1 对应的字符后，\"a<strong>b</strong>c<strong>a</strong>cb\" 变成 \"accb\" 。\n\"ab\" 是 \"<strong>a</strong>cc<strong>b</strong>\" 的一个子序列。\n如果移除下标 3、1 和 0 对应的字符后，\"<strong>ab</strong>c<strong>a</strong>cb\" 变成 \"ccb\" ，那么 \"ab\" 就不再是 s 的一个子序列。\n因此，最大的 k 是 2 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"abcbddddd\", p = \"abcd\", removable = [3,2,1,4,5,6]\n<strong>输出：</strong>1\n<strong>解释：</strong>在移除下标 3 对应的字符后，\"abc<strong>b</strong>ddddd\" 变成 \"abcddddd\" 。\n\"abcd\" 是 \"<strong>abcd</strong>dddd\" 的一个子序列。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"abcab\", p = \"abc\", removable = [0,1,2,3,4]\n<strong>输出：</strong>0\n<strong>解释：</strong>如果移除数组 removable 的第一个下标，\"abc\" 就不再是 s 的一个子序列。\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= p.length <= s.length <= 10<sup>5</sup></code></li>\n\t<li><code>0 <= removable.length < s.length</code></li>\n\t<li><code>0 <= removable[i] < s.length</code></li>\n\t<li><code>p</code> 是 <code>s</code> 的一个 <strong>子字符串</strong></li>\n\t<li><code>s</code> 和 <code>p</code> 都由小写英文字母组成</li>\n\t<li><code>removable</code> 中的元素 <strong>互不相同</strong></li>\n</ul>\n",
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                "First, we need to think about solving an easier problem, If we remove a set of indices from the string does P exist in S as a subsequence",
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href=\\\"https:\\/\\/github.com\\/datastructures-js\\/queue\\\" target=\\\"_blank\\\"> datastructures-js\\/queue<\\/a>\\u3002<\\/p>\"],\"ruby\":[\"Ruby\",\"<p>\\u4f7f\\u7528<code>Ruby 3.1<\\/code>\\u6267\\u884c<\\/p>\\r\\n\\r\\n<p>\\u4e00\\u4e9b\\u5e38\\u7528\\u7684\\u6570\\u636e\\u7ed3\\u6784\\u5df2\\u5728 Algorithms \\u6a21\\u5757\\u4e2d\\u63d0\\u4f9b\\uff1ahttps:\\/\\/www.rubydoc.info\\/github\\/kanwei\\/algorithms\\/Algorithms<\\/p>\"],\"swift\":[\"Swift\",\"<p>\\u7248\\u672c\\uff1a<code>Swift 5.5.2<\\/code><\\/p>\\r\\n\\r\\n<p>\\u6211\\u4eec\\u901a\\u5e38\\u4fdd\\u8bc1\\u66f4\\u65b0\\u5230 <a href=\\\"https:\\/\\/swift.org\\/download\\/\\\" target=\\\"_blank\\\">Apple\\u653e\\u51fa\\u7684\\u6700\\u65b0\\u7248Swift<\\/a>\\u3002\\u5982\\u679c\\u60a8\\u53d1\\u73b0Swift\\u4e0d\\u662f\\u6700\\u65b0\\u7248\\u7684\\uff0c\\u8bf7\\u8054\\u7cfb\\u6211\\u4eec\\uff01\\u6211\\u4eec\\u5c06\\u5c3d\\u5feb\\u66f4\\u65b0\\u3002<\\/p>\"],\"golang\":[\"Go\",\"<p>\\u7248\\u672c\\uff1a<code>Go 1.17<\\/code><\\/p>\\r\\n\\r\\n<p>\\u652f\\u6301 <a href=\\\"https:\\/\\/godoc.org\\/github.com\\/emirpasic\\/gods\\\" target=\\\"_blank\\\">https:\\/\\/godoc.org\\/github.com\\/emirpasic\\/gods<\\/a> \\u7b2c\\u4e09\\u65b9\\u5e93\\u3002<\\/p>\"],\"python3\":[\"Python3\",\"<p>\\u7248\\u672c\\uff1a<code>Python 3.10<\\/code><\\/p>\\r\\n\\r\\n<p>\\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u5e38\\u7528\\u5e93\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8 \\u5bfc\\u5165\\uff0c\\u5982<a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/array.html\\\" target=\\\"_blank\\\">array<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/bisect.html\\\" target=\\\"_blank\\\">bisect<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/collections.html\\\" target=\\\"_blank\\\">collections<\\/a>\\u3002 \\u5982\\u679c\\u60a8\\u9700\\u8981\\u4f7f\\u7528\\u5176\\u4ed6\\u5e93\\u51fd\\u6570\\uff0c\\u8bf7\\u81ea\\u884c\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n<p>\\u5982\\u9700\\u4f7f\\u7528 Map\\/TreeMap \\u6570\\u636e\\u7ed3\\u6784\\uff0c\\u60a8\\u53ef\\u4f7f\\u7528 <a href=\\\"http:\\/\\/www.grantjenks.com\\/docs\\/sortedcontainers\\/\\\" target=\\\"_blank\\\">sortedcontainers<\\/a> \\u5e93\\u3002<\\/p>\"],\"scala\":[\"Scala\",\"<p>\\u7248\\u672c\\uff1a<code>Scala 2.13<\\/code><\\/p>\"],\"kotlin\":[\"Kotlin\",\"<p>\\u7248\\u672c\\uff1a<code>Kotlin 1.3.10<\\/code><\\/p>\"],\"rust\":[\"Rust\",\"<p>\\u7248\\u672c\\uff1a<code>rust 1.58.1<\\/code><\\/p>\\r\\n\\r\\n<p>\\u652f\\u6301 crates.io \\u7684 <a href=\\\"https:\\/\\/crates.io\\/crates\\/rand\\\" target=\\\"_blank\\\">rand<\\/a><\\/p>\"],\"php\":[\"PHP\",\"<p><code>PHP 8.1<\\/code>.<\\/p>\\r\\n\\r\\n<p>With bcmath module.<\\/p>\"],\"typescript\":[\"TypeScript\",\"<p>TypeScript 4.5.4<\\/p>\\r\\n\\r\\n<p>Compile Options: --alwaysStrict --strictBindCallApply --strictFunctionTypes --target ES2020<\\/p>\"],\"racket\":[\"Racket\",\"<p><a href=\\\"https:\\/\\/docs.racket-lang.org\\/guide\\/performance.html#%28tech._c%29\\\" target=\\\"_blank\\\">Racket CS<\\/a> v8.3<\\/p>\\r\\n\\r\\n<p>\\u4f7f\\u7528 #lang racket<\\/p>\\r\\n\\r\\n<p>\\u5df2\\u9884\\u5148 (require data\\/gvector data\\/queue data\\/order data\\/heap). \\u82e5\\u9700\\u4f7f\\u7528\\u5176\\u5b83\\u6570\\u636e\\u7ed3\\u6784\\uff0c\\u53ef\\u81ea\\u884c require\\u3002<\\/p>\"],\"erlang\":[\"Erlang\",\"Erlang\\/OTP 24.2\"],\"elixir\":[\"Elixir\",\"Elixir 1.13.0 with Erlang\\/OTP 24.2\"]}",
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