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leetcode-problemset/leetcode-cn/originData/maximum-length-of-pair-chain.json
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"categoryTitle": "Algorithms",
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"title": "Maximum Length of Pair Chain",
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"content": "<p>You are given an array of <code>n</code> pairs <code>pairs</code> where <code>pairs[i] = [left<sub>i</sub>, right<sub>i</sub>]</code> and <code>left<sub>i</sub> &lt; right<sub>i</sub></code>.</p>\n\n<p>A pair <code>p2 = [c, d]</code> <strong>follows</strong> a pair <code>p1 = [a, b]</code> if <code>b &lt; c</code>. A <strong>chain</strong> of pairs can be formed in this fashion.</p>\n\n<p>Return <em>the length longest chain which can be formed</em>.</p>\n\n<p>You do not need to use up all the given intervals. You can select pairs in any order.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> pairs = [[1,2],[2,3],[3,4]]\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> The longest chain is [1,2] -&gt; [3,4].\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> pairs = [[1,2],[7,8],[4,5]]\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> The longest chain is [1,2] -&gt; [4,5] -&gt; [7,8].\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == pairs.length</code></li>\n\t<li><code>1 &lt;= n &lt;= 1000</code></li>\n\t<li><code>-1000 &lt;= left<sub>i</sub> &lt; right<sub>i</sub> &lt;= 1000</code></li>\n</ul>\n",
"translatedTitle": "最长数对链",
"translatedContent": "<p>给出 <code>n</code> 个数对。 在每一个数对中,第一个数字总是比第二个数字小。</p>\n\n<p>现在,我们定义一种跟随关系,当且仅当 <code>b < c</code> 时,数对<code>(c, d)</code> 才可以跟在 <code>(a, b)</code> 后面。我们用这种形式来构造一个数对链。</p>\n\n<p>给定一个数对集合,找出能够形成的最长数对链的长度。你不需要用到所有的数对,你可以以任何顺序选择其中的一些数对来构造。</p>\n\n<p> </p>\n\n<p><strong>示例:</strong></p>\n\n<pre>\n<strong>输入:</strong>[[1,2], [2,3], [3,4]]\n<strong>输出:</strong>2\n<strong>解释:</strong>最长的数对链是 [1,2] -> [3,4]\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li>给出数对的个数在 <code>[1, 1000]</code> 范围内。</li>\n</ul>\n",
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