mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-11 02:58:13 +08:00
178 lines
24 KiB
JSON
178 lines
24 KiB
JSON
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"categoryTitle": "Algorithms",
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"boundTopicId": 293089,
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"title": "Making File Names Unique",
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"content": "<p>Given an array of strings <code>names</code> of size <code>n</code>. You will create <code>n</code> folders in your file system <strong>such that</strong>, at the <code>i<sup>th</sup></code> minute, you will create a folder with the name <code>names[i]</code>.</p>\n\n<p>Since two files <strong>cannot</strong> have the same name, if you enter a folder name that was previously used, the system will have a suffix addition to its name in the form of <code>(k)</code>, where, <code>k</code> is the <strong>smallest positive integer</strong> such that the obtained name remains unique.</p>\n\n<p>Return <em>an array of strings of length </em><code>n</code> where <code>ans[i]</code> is the actual name the system will assign to the <code>i<sup>th</sup></code> folder when you create it.</p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> names = ["pes","fifa","gta","pes(2019)"]\n<strong>Output:</strong> ["pes","fifa","gta","pes(2019)"]\n<strong>Explanation:</strong> Let's see how the file system creates folder names:\n"pes" --> not assigned before, remains "pes"\n"fifa" --> not assigned before, remains "fifa"\n"gta" --> not assigned before, remains "gta"\n"pes(2019)" --> not assigned before, remains "pes(2019)"\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> names = ["gta","gta(1)","gta","avalon"]\n<strong>Output:</strong> ["gta","gta(1)","gta(2)","avalon"]\n<strong>Explanation:</strong> Let's see how the file system creates folder names:\n"gta" --> not assigned before, remains "gta"\n"gta(1)" --> not assigned before, remains "gta(1)"\n"gta" --> the name is reserved, system adds (k), since "gta(1)" is also reserved, systems put k = 2. it becomes "gta(2)"\n"avalon" --> not assigned before, remains "avalon"\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> names = ["onepiece","onepiece(1)","onepiece(2)","onepiece(3)","onepiece"]\n<strong>Output:</strong> ["onepiece","onepiece(1)","onepiece(2)","onepiece(3)","onepiece(4)"]\n<strong>Explanation:</strong> When the last folder is created, the smallest positive valid k is 4, and it becomes "onepiece(4)".\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= names.length <= 5 * 10<sup>4</sup></code></li>\n\t<li><code>1 <= names[i].length <= 20</code></li>\n\t<li><code>names[i]</code> consists of lowercase English letters, digits, and/or round brackets.</li>\n</ul>\n",
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"translatedTitle": "保证文件名唯一",
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"translatedContent": "<p>给你一个长度为 <code>n</code> 的字符串数组 <code>names</code> 。你将会在文件系统中创建 <code>n</code> 个文件夹：在第 <code>i</code> 分钟，新建名为 <code>names[i]</code> 的文件夹。</p>\n\n<p>由于两个文件 <strong>不能</strong> 共享相同的文件名，因此如果新建文件夹使用的文件名已经被占用，系统会以 <code>(k)</code> 的形式为新文件夹的文件名添加后缀，其中 <code>k</code> 是能保证文件名唯一的 <strong>最小正整数</strong> 。</p>\n\n<p>返回长度为<em> <code>n</code></em> 的字符串数组，其中 <code>ans[i]</code> 是创建第 <code>i</code> 个文件夹时系统分配给该文件夹的实际名称。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><strong>输入：</strong>names = ["pes","fifa","gta","pes(2019)"]\n<strong>输出：</strong>["pes","fifa","gta","pes(2019)"]\n<strong>解释：</strong>文件系统将会这样创建文件名：\n"pes" --> 之前未分配，仍为 "pes"\n"fifa" --> 之前未分配，仍为 "fifa"\n"gta" --> 之前未分配，仍为 "gta"\n"pes(2019)" --> 之前未分配，仍为 "pes(2019)"\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入：</strong>names = ["gta","gta(1)","gta","avalon"]\n<strong>输出：</strong>["gta","gta(1)","gta(2)","avalon"]\n<strong>解释：</strong>文件系统将会这样创建文件名：\n"gta" --> 之前未分配，仍为 "gta"\n"gta(1)" --> 之前未分配，仍为 "gta(1)"\n"gta" --> 文件名被占用，系统为该名称添加后缀 (k)，由于 "gta(1)" 也被占用，所以 k = 2 。实际创建的文件名为 "gta(2)" 。\n"avalon" --> 之前未分配，仍为 "avalon"\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre><strong>输入：</strong>names = ["onepiece","onepiece(1)","onepiece(2)","onepiece(3)","onepiece"]\n<strong>输出：</strong>["onepiece","onepiece(1)","onepiece(2)","onepiece(3)","onepiece(4)"]\n<strong>解释：</strong>当创建最后一个文件夹时，最小的正有效 k 为 4 ，文件名变为 "onepiece(4)"。\n</pre>\n\n<p><strong>示例 4：</strong></p>\n\n<pre><strong>输入：</strong>names = ["wano","wano","wano","wano"]\n<strong>输出：</strong>["wano","wano(1)","wano(2)","wano(3)"]\n<strong>解释：</strong>每次创建文件夹 "wano" 时，只需增加后缀中 k 的值即可。</pre>\n\n<p><strong>示例 5：</strong></p>\n\n<pre><strong>输入：</strong>names = ["kaido","kaido(1)","kaido","kaido(1)"]\n<strong>输出：</strong>["kaido","kaido(1)","kaido(2)","kaido(1)(1)"]\n<strong>解释：</strong>注意，如果含后缀文件名被占用，那么系统也会按规则在名称后添加新的后缀 (k) 。\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= names.length <= 5 * 10^4</code></li>\n\t<li><code>1 <= names[i].length <= 20</code></li>\n\t<li><code>names[i]</code> 由小写英文字母、数字和/或圆括号组成。</li>\n</ul>\n",
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"Keep a map of each name and the smallest valid integer that can be appended as a suffix to it.",
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1.17<\\/code><\\/p>\\r\\n\\r\\n<p>\\u652f\\u6301 <a href=\\\"https:\\/\\/godoc.org\\/github.com\\/emirpasic\\/gods\\\" target=\\\"_blank\\\">https:\\/\\/godoc.org\\/github.com\\/emirpasic\\/gods<\\/a> \\u7b2c\\u4e09\\u65b9\\u5e93\\u3002<\\/p>\"],\"python3\":[\"Python3\",\"<p>\\u7248\\u672c\\uff1a<code>Python 3.10<\\/code><\\/p>\\r\\n\\r\\n<p>\\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u5e38\\u7528\\u5e93\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8 \\u5bfc\\u5165\\uff0c\\u5982<a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/array.html\\\" target=\\\"_blank\\\">array<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/bisect.html\\\" target=\\\"_blank\\\">bisect<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/collections.html\\\" target=\\\"_blank\\\">collections<\\/a>\\u3002 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