leetcode-problemset/leetcode-cn/originData/k-concatenation-maximum-sum.json

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        "question": {
            "questionId": "1299",
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            "categoryTitle": "Algorithms",
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            "title": "K-Concatenation Maximum Sum",
            "titleSlug": "k-concatenation-maximum-sum",
            "content": "<p>Given an integer array <code>arr</code> and an integer <code>k</code>, modify the array by repeating it <code>k</code> times.</p>\n\n<p>For example, if <code>arr = [1, 2]</code> and <code>k = 3 </code>then the modified array will be <code>[1, 2, 1, 2, 1, 2]</code>.</p>\n\n<p>Return the maximum sub-array sum in the modified array. Note that the length of the sub-array can be <code>0</code> and its sum in that case is <code>0</code>.</p>\n\n<p>As the answer can be very large, return the answer <strong>modulo</strong> <code>10<sup>9</sup> + 7</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> arr = [1,2], k = 3\n<strong>Output:</strong> 9\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> arr = [1,-2,1], k = 5\n<strong>Output:</strong> 2\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> arr = [-1,-2], k = 7\n<strong>Output:</strong> 0\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= arr.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= k &lt;= 10<sup>5</sup></code></li>\n\t<li><code>-10<sup>4</sup> &lt;= arr[i] &lt;= 10<sup>4</sup></code></li>\n</ul>\n",
            "translatedTitle": "K 次串联后最大子数组之和",
            "translatedContent": "<p>给定一个整数数组&nbsp;<code>arr</code>&nbsp;和一个整数&nbsp;<code>k</code>&nbsp;，通过重复&nbsp;<code>k</code>&nbsp;次来修改数组。</p>\n\n<p>例如，如果&nbsp;<code>arr = [1, 2]</code>&nbsp;，<meta charset=\"UTF-8\" />&nbsp;<code>k = 3</code>&nbsp;，那么修改后的数组将是 <code>[1, 2, 1, 2, 1, 2]</code> 。</p>\n\n<p>返回修改后的数组中的最大的子数组之和。注意，子数组长度可以是 <code>0</code>，在这种情况下它的总和也是 <code>0</code>。</p>\n\n<p>由于&nbsp;<strong>结果可能会很大</strong>，需要返回的<meta charset=\"UTF-8\" />&nbsp;<code>10<sup>9</sup>&nbsp;+ 7</code>&nbsp;的&nbsp;<strong>模</strong>&nbsp;。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>arr = [1,2], k = 3\n<strong>输出：</strong>9\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>arr = [1,-2,1], k = 5\n<strong>输出：</strong>2\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>arr = [-1,-2], k = 7\n<strong>输出：</strong>0\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n<meta charset=\"UTF-8\" />\n\n<ul>\n\t<li><code>1 &lt;= arr.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= k &lt;= 10<sup>5</sup></code></li>\n\t<li><code>-10<sup>4</sup>&nbsp;&lt;= arr[i] &lt;= 10<sup>4</sup></code></li>\n</ul>\n",
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                "How to solve the problem for k=1 ?",
                "Use Kadane's algorithm for k=1.",
                "What are the possible cases for the answer ?",
                "The answer is the maximum between, the answer for k=1, the sum of the whole array multiplied by k, or the maximum suffix sum plus the maximum prefix sum plus (k-2) multiplied by the whole array sum for k > 1."
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