mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-11 02:58:13 +08:00
177 lines
20 KiB
JSON
177 lines
20 KiB
JSON
{
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"questionId": "1428",
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"questionFrontendId": "1306",
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"categoryTitle": "Algorithms",
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"boundTopicId": 62635,
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"title": "Jump Game III",
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"titleSlug": "jump-game-iii",
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"content": "<p>Given an array of non-negative integers <code>arr</code>, you are initially positioned at <code>start</code> index of the array. When you are at index <code>i</code>, you can jump to <code>i + arr[i]</code> or <code>i - arr[i]</code>, check if you can reach to <strong>any</strong> index with value 0.</p>\n\n<p>Notice that you can not jump outside of the array at any time.</p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> arr = [4,2,3,0,3,1,2], start = 5\n<strong>Output:</strong> true\n<strong>Explanation:</strong> \nAll possible ways to reach at index 3 with value 0 are: \nindex 5 -> index 4 -> index 1 -> index 3 \nindex 5 -> index 6 -> index 4 -> index 1 -> index 3 \n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> arr = [4,2,3,0,3,1,2], start = 0\n<strong>Output:</strong> true \n<strong>Explanation: \n</strong>One possible way to reach at index 3 with value 0 is: \nindex 0 -> index 4 -> index 1 -> index 3\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> arr = [3,0,2,1,2], start = 2\n<strong>Output:</strong> false\n<strong>Explanation: </strong>There is no way to reach at index 1 with value 0.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= arr.length <= 5 * 10<sup>4</sup></code></li>\n\t<li><code>0 <= arr[i] < arr.length</code></li>\n\t<li><code>0 <= start < arr.length</code></li>\n</ul>\n",
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"translatedTitle": "跳跃游戏 III",
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"translatedContent": "<p>这里有一个非负整数数组 <code>arr</code>,你最开始位于该数组的起始下标 <code>start</code> 处。当你位于下标 <code>i</code> 处时,你可以跳到 <code>i + arr[i]</code> 或者 <code>i - arr[i]</code>。</p>\n\n<p>请你判断自己是否能够跳到对应元素值为 0 的 <strong>任一</strong> 下标处。</p>\n\n<p>注意,不管是什么情况下,你都无法跳到数组之外。</p>\n\n<p> </p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre><strong>输入:</strong>arr = [4,2,3,0,3,1,2], start = 5\n<strong>输出:</strong>true\n<strong>解释:</strong>\n到达值为 0 的下标 3 有以下可能方案: \n下标 5 -> 下标 4 -> 下标 1 -> 下标 3 \n下标 5 -> 下标 6 -> 下标 4 -> 下标 1 -> 下标 3 \n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre><strong>输入:</strong>arr = [4,2,3,0,3,1,2], start = 0\n<strong>输出:</strong>true \n<strong>解释:\n</strong>到达值为 0 的下标 3 有以下可能方案: \n下标 0 -> 下标 4 -> 下标 1 -> 下标 3\n</pre>\n\n<p><strong>示例 3:</strong></p>\n\n<pre><strong>输入:</strong>arr = [3,0,2,1,2], start = 2\n<strong>输出:</strong>false\n<strong>解释:</strong>无法到达值为 0 的下标 1 处。 \n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 <= arr.length <= 5 * 10^4</code></li>\n\t<li><code>0 <= arr[i] < arr.length</code></li>\n\t<li><code>0 <= start < arr.length</code></li>\n</ul>\n",
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"difficulty": "Medium",
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"Think of BFS to solve the problem.",
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"When you reach a position with a value = 0 then return true."
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