mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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188 lines
33 KiB
JSON
188 lines
33 KiB
JSON
{
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"data": {
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"question": {
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"questionId": "100170",
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"questionFrontendId": "面试题 03.04",
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"categoryTitle": "LCCI",
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"boundTopicId": 45971,
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"title": "Implement Queue using Stacks LCCI",
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"titleSlug": "implement-queue-using-stacks-lcci",
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"content": "<p>Implement a MyQueue class which implements a queue using two stacks.</p>\r\n \r\n\r\n<p><strong>Example: </strong></p>\r\n\r\n<pre>\r\nMyQueue queue = new MyQueue();\r\n\r\nqueue.push(1);\r\nqueue.push(2);\r\nqueue.peek(); // return 1\r\nqueue.pop(); // return 1\r\nqueue.empty(); // return false</pre>\r\n\r\n<p> </p>\r\n\r\n<p><b>Notes:</b></p>\r\n\r\n<ul>\r\n\t<li>You must use <i>only</i> standard operations of a stack -- which means only <code>push to top</code>, <code>peek/pop from top</code>, <code>size</code>, and <code>is empty</code> operations are valid.</li>\r\n\t<li>Depending on your language, stack may not be supported natively. You may simulate a stack by using a list or deque (double-ended queue), as long as you use only standard operations of a stack.</li>\r\n\t<li>You may assume that all operations are valid (for example, no pop or peek operations will be called on an empty queue).</li>\r\n</ul>\r\n\r\n<p> </p>\r\n",
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"translatedTitle": "化栈为队",
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"translatedContent": "<p>实现一个MyQueue类,该类用两个栈来实现一个队列。</p><br><p><strong>示例:</strong><pre>MyQueue queue = new MyQueue();<br><br>queue.push(1);<br>queue.push(2);<br>queue.peek(); // 返回 1<br>queue.pop(); // 返回 1<br>queue.empty(); // 返回 false</pre></p><br><p><strong>说明:</strong><br><ul><li>你只能使用标准的栈操作 -- 也就是只有 <code>push to top</code>, <code>peek/pop from top</code>, <code>size</code> 和 <code>is empty</code> 操作是合法的。</li><li>你所使用的语言也许不支持栈。你可以使用 list 或者 deque(双端队列)来模拟一个栈,只要是标准的栈操作即可。</li><li>假设所有操作都是有效的 (例如,一个空的队列不会调用 pop 或者 peek 操作)。</li></ul></p>",
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"difficulty": "Easy",
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"likes": 56,
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"topicTags": [
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"name": "Stack",
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"slug": "stack",
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"translatedName": "栈",
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"name": "Queue",
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"code": "class MyQueue {\npublic:\n /** Initialize your data structure here. */\n MyQueue() {\n\n }\n \n /** Push element x to the back of queue. */\n void push(int x) {\n\n }\n \n /** Removes the element from in front of queue and returns that element. */\n int pop() {\n\n }\n \n /** Get the front element. */\n int peek() {\n\n }\n \n /** Returns whether the queue is empty. */\n bool empty() {\n\n }\n};\n\n/**\n * Your MyQueue object will be instantiated and called as such:\n * MyQueue* obj = new MyQueue();\n * obj->push(x);\n * int param_2 = obj->pop();\n * int param_3 = obj->peek();\n * bool param_4 = obj->empty();\n */",
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"code": "class MyQueue {\n\n /** Initialize your data structure here. */\n public MyQueue() {\n\n }\n \n /** Push element x to the back of queue. */\n public void push(int x) {\n\n }\n \n /** Removes the element from in front of queue and returns that element. */\n public int pop() {\n\n }\n \n /** Get the front element. */\n public int peek() {\n\n }\n \n /** Returns whether the queue is empty. */\n public boolean empty() {\n\n }\n}\n\n/**\n * Your MyQueue object will be instantiated and called as such:\n * MyQueue obj = new MyQueue();\n * obj.push(x);\n * int param_2 = obj.pop();\n * int param_3 = obj.peek();\n * boolean param_4 = obj.empty();\n */",
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"code": "class MyQueue(object):\n\n def __init__(self):\n \"\"\"\n Initialize your data structure here.\n \"\"\"\n\n\n def push(self, x):\n \"\"\"\n Push element x to the back of queue.\n :type x: int\n :rtype: None\n \"\"\"\n\n\n def pop(self):\n \"\"\"\n Removes the element from in front of queue and returns that element.\n :rtype: int\n \"\"\"\n\n\n def peek(self):\n \"\"\"\n Get the front element.\n :rtype: int\n \"\"\"\n\n\n def empty(self):\n \"\"\"\n Returns whether the queue is empty.\n :rtype: bool\n \"\"\"\n\n\n\n# Your MyQueue object will be instantiated and called as such:\n# obj = MyQueue()\n# obj.push(x)\n# param_2 = obj.pop()\n# param_3 = obj.peek()\n# param_4 = obj.empty()",
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"code": "class MyQueue:\n\n def __init__(self):\n \"\"\"\n Initialize your data structure here.\n \"\"\"\n\n\n def push(self, x: int) -> None:\n \"\"\"\n Push element x to the back of queue.\n \"\"\"\n\n\n def pop(self) -> int:\n \"\"\"\n Removes the element from in front of queue and returns that element.\n \"\"\"\n\n\n def peek(self) -> int:\n \"\"\"\n Get the front element.\n \"\"\"\n\n\n def empty(self) -> bool:\n \"\"\"\n Returns whether the queue is empty.\n \"\"\"\n\n\n\n# Your MyQueue object will be instantiated and called as such:\n# obj = MyQueue()\n# obj.push(x)\n# param_2 = obj.pop()\n# param_3 = obj.peek()\n# param_4 = obj.empty()",
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"code": "\n\n\ntypedef struct {\n\n} MyQueue;\n\n/** Initialize your data structure here. */\n\nMyQueue* myQueueCreate() {\n\n}\n\n/** Push element x to the back of queue. */\nvoid myQueuePush(MyQueue* obj, int x) {\n\n}\n\n/** Removes the element from in front of queue and returns that element. */\nint myQueuePop(MyQueue* obj) {\n\n}\n\n/** Get the front element. */\nint myQueuePeek(MyQueue* obj) {\n\n}\n\n/** Returns whether the queue is empty. */\nbool myQueueEmpty(MyQueue* obj) {\n\n}\n\nvoid myQueueFree(MyQueue* obj) {\n\n}\n\n/**\n * Your MyQueue struct will be instantiated and called as such:\n * MyQueue* obj = myQueueCreate();\n * myQueuePush(obj, x);\n \n * int param_2 = myQueuePop(obj);\n \n * int param_3 = myQueuePeek(obj);\n \n * bool param_4 = myQueueEmpty(obj);\n \n * myQueueFree(obj);\n*/",
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"code": "public class MyQueue {\n\n /** Initialize your data structure here. */\n public MyQueue() {\n\n }\n \n /** Push element x to the back of queue. */\n public void Push(int x) {\n\n }\n \n /** Removes the element from in front of queue and returns that element. */\n public int Pop() {\n\n }\n \n /** Get the front element. */\n public int Peek() {\n\n }\n \n /** Returns whether the queue is empty. */\n public bool Empty() {\n\n }\n}\n\n/**\n * Your MyQueue object will be instantiated and called as such:\n * MyQueue obj = new MyQueue();\n * obj.Push(x);\n * int param_2 = obj.Pop();\n * int param_3 = obj.Peek();\n * bool param_4 = obj.Empty();\n */",
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"code": "/**\n * Initialize your data structure here.\n */\nvar MyQueue = function() {\n\n};\n\n/**\n * Push element x to the back of queue. \n * @param {number} x\n * @return {void}\n */\nMyQueue.prototype.push = function(x) {\n\n};\n\n/**\n * Removes the element from in front of queue and returns that element.\n * @return {number}\n */\nMyQueue.prototype.pop = function() {\n\n};\n\n/**\n * Get the front element.\n * @return {number}\n */\nMyQueue.prototype.peek = function() {\n\n};\n\n/**\n * Returns whether the queue is empty.\n * @return {boolean}\n */\nMyQueue.prototype.empty = function() {\n\n};\n\n/**\n * Your MyQueue object will be instantiated and called as such:\n * var obj = new MyQueue()\n * obj.push(x)\n * var param_2 = obj.pop()\n * var param_3 = obj.peek()\n * var param_4 = obj.empty()\n */",
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"code": "class MyQueue\n\n=begin\n Initialize your data structure here.\n=end\n def initialize()\n\n end\n\n\n=begin\n Push element x to the back of queue.\n :type x: Integer\n :rtype: Void\n=end\n def push(x)\n\n end\n\n\n=begin\n Removes the element from in front of queue and returns that element.\n :rtype: Integer\n=end\n def pop()\n\n end\n\n\n=begin\n Get the front element.\n :rtype: Integer\n=end\n def peek()\n\n end\n\n\n=begin\n Returns whether the queue is empty.\n :rtype: Boolean\n=end\n def empty()\n\n end\n\n\nend\n\n# Your MyQueue object will be instantiated and called as such:\n# obj = MyQueue.new()\n# obj.push(x)\n# param_2 = obj.pop()\n# param_3 = obj.peek()\n# param_4 = obj.empty()",
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"code": "\nclass MyQueue {\n\n /** Initialize your data structure here. */\n init() {\n\n }\n \n /** Push element x to the back of queue. */\n func push(_ x: Int) {\n\n }\n \n /** Removes the element from in front of queue and returns that element. */\n func pop() -> Int {\n\n }\n \n /** Get the front element. */\n func peek() -> Int {\n\n }\n \n /** Returns whether the queue is empty. */\n func empty() -> Bool {\n\n }\n}\n\n/**\n * Your MyQueue object will be instantiated and called as such:\n * let obj = MyQueue()\n * obj.push(x)\n * let ret_2: Int = obj.pop()\n * let ret_3: Int = obj.peek()\n * let ret_4: Bool = obj.empty()\n */",
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"lang": "Go",
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"code": "type MyQueue struct {\n\n}\n\n\n/** Initialize your data structure here. */\nfunc Constructor() MyQueue {\n\n}\n\n\n/** Push element x to the back of queue. */\nfunc (this *MyQueue) Push(x int) {\n\n}\n\n\n/** Removes the element from in front of queue and returns that element. */\nfunc (this *MyQueue) Pop() int {\n\n}\n\n\n/** Get the front element. */\nfunc (this *MyQueue) Peek() int {\n\n}\n\n\n/** Returns whether the queue is empty. */\nfunc (this *MyQueue) Empty() bool {\n\n}\n\n\n/**\n * Your MyQueue object will be instantiated and called as such:\n * obj := Constructor();\n * obj.Push(x);\n * param_2 := obj.Pop();\n * param_3 := obj.Peek();\n * param_4 := obj.Empty();\n */",
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"langSlug": "scala",
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"code": "class MyQueue() {\n\n /** Initialize your data structure here. */\n\n\n /** Push element x to the back of queue. */\n def push(x: Int) {\n\n }\n\n /** Removes the element from in front of queue and returns that element. */\n def pop(): Int = {\n\n }\n\n /** Get the front element. */\n def peek(): Int = {\n\n }\n\n /** Returns whether the queue is empty. */\n def empty(): Boolean = {\n\n }\n\n}\n\n/**\n * Your MyQueue object will be instantiated and called as such:\n * var obj = new MyQueue()\n * obj.push(x)\n * var param_2 = obj.pop()\n * var param_3 = obj.peek()\n * var param_4 = obj.empty()\n */",
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"code": "class MyQueue() {\n\n /** Initialize your data structure here. */\n\n\n /** Push element x to the back of queue. */\n fun push(x: Int) {\n\n }\n\n /** Removes the element from in front of queue and returns that element. */\n fun pop(): Int {\n\n }\n\n /** Get the front element. */\n fun peek(): Int {\n\n }\n\n /** Returns whether the queue is empty. */\n fun empty(): Boolean {\n\n }\n\n}\n\n/**\n * Your MyQueue object will be instantiated and called as such:\n * var obj = MyQueue()\n * obj.push(x)\n * var param_2 = obj.pop()\n * var param_3 = obj.peek()\n * var param_4 = obj.empty()\n */",
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"lang": "Rust",
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"langSlug": "rust",
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"code": "struct MyQueue {\n\n}\n\n\n/**\n * `&self` means the method takes an immutable reference.\n * If you need a mutable reference, change it to `&mut self` instead.\n */\nimpl MyQueue {\n\n /** Initialize your data structure here. */\n fn new() -> Self {\n\n }\n \n /** Push element x to the back of queue. */\n fn push(&self, x: i32) {\n\n }\n \n /** Removes the element from in front of queue and returns that element. */\n fn pop(&self) -> i32 {\n\n }\n \n /** Get the front element. */\n fn peek(&self) -> i32 {\n\n }\n \n /** Returns whether the queue is empty. */\n fn empty(&self) -> bool {\n\n }\n}\n\n/**\n * Your MyQueue object will be instantiated and called as such:\n * let obj = MyQueue::new();\n * obj.push(x);\n * let ret_2: i32 = obj.pop();\n * let ret_3: i32 = obj.peek();\n * let ret_4: bool = obj.empty();\n */",
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"lang": "PHP",
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"langSlug": "php",
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"code": "class MyQueue {\n /**\n * Initialize your data structure here.\n */\n function __construct() {\n\n }\n\n /**\n * Push element x to the back of queue.\n * @param Integer $x\n * @return NULL\n */\n function push($x) {\n\n }\n\n /**\n * Removes the element from in front of queue and returns that element.\n * @return Integer\n */\n function pop() {\n\n }\n\n /**\n * Get the front element.\n * @return Integer\n */\n function peek() {\n\n }\n\n /**\n * Returns whether the queue is empty.\n * @return Boolean\n */\n function empty() {\n\n }\n}\n\n/**\n * Your MyQueue object will be instantiated and called as such:\n * $obj = MyQueue();\n * $obj->push($x);\n * $ret_2 = $obj->pop();\n * $ret_3 = $obj->peek();\n * $ret_4 = $obj->empty();\n */",
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"lang": "TypeScript",
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"langSlug": "typescript",
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"code": "class MyQueue {\n constructor() {\n\n }\n\n push(x: number): void {\n\n }\n\n pop(): number {\n\n }\n\n peek(): number {\n\n }\n\n empty(): boolean {\n\n }\n}\n\n/**\n * Your MyQueue object will be instantiated and called as such:\n * var obj = new MyQueue()\n * obj.push(x)\n * var param_2 = obj.pop()\n * var param_3 = obj.peek()\n * var param_4 = obj.empty()\n */",
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"lang": "Racket",
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"langSlug": "racket",
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"code": "(define my-queue%\n (class object%\n (super-new)\n (init-field)\n \n ; push : exact-integer? -> void?\n (define/public (push x)\n\n )\n ; pop : -> exact-integer?\n (define/public (pop)\n\n )\n ; peek : -> exact-integer?\n (define/public (peek)\n\n )\n ; empty : -> boolean?\n (define/public (empty)\n\n )))\n\n;; Your my-queue% object will be instantiated and called as such:\n;; (define obj (new my-queue%))\n;; (send obj push x)\n;; (define param_2 (send obj pop))\n;; (define param_3 (send obj peek))\n;; (define param_4 (send obj empty))",
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"lang": "Erlang",
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"langSlug": "erlang",
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"code": "-spec my_queue_init_() -> any().\nmy_queue_init_() ->\n .\n\n-spec my_queue_push(X :: integer()) -> any().\nmy_queue_push(X) ->\n .\n\n-spec my_queue_pop() -> integer().\nmy_queue_pop() ->\n .\n\n-spec my_queue_peek() -> integer().\nmy_queue_peek() ->\n .\n\n-spec my_queue_empty() -> boolean().\nmy_queue_empty() ->\n .\n\n\n%% Your functions will be called as such:\n%% my_queue_init_(),\n%% my_queue_push(X),\n%% Param_2 = my_queue_pop(),\n%% Param_3 = my_queue_peek(),\n%% Param_4 = my_queue_empty(),\n\n%% my_queue_init_ will be called before every test case, in which you can do some necessary initializations.",
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"lang": "Elixir",
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"langSlug": "elixir",
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"code": "defmodule MyQueue do\n @spec init_() :: any\n def init_() do\n\n end\n\n @spec push(x :: integer) :: any\n def push(x) do\n\n end\n\n @spec pop() :: integer\n def pop() do\n\n end\n\n @spec peek() :: integer\n def peek() do\n\n end\n\n @spec empty() :: boolean\n def empty() do\n\n end\nend\n\n# Your functions will be called as such:\n# MyQueue.init_()\n# MyQueue.push(x)\n# param_2 = MyQueue.pop()\n# param_3 = MyQueue.peek()\n# param_4 = MyQueue.empty()\n\n# MyQueue.init_ will be called before every test case, in which you can do some necessary initializations.",
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"队列和栈的主要区别是元素的顺序。队列删除最旧的项,栈删除最新的项。如果你只访问最新的项,那么如何从栈中删除最旧的项?",
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"我们可以通过不断地删除最新的项(将这些项插入临时栈中)来删除栈中最老的项,直到得到一个元素为止。然后,在检索到最新项后,将所有元素返回。与此有关的问题是,每次在一行中做几个弹出操作(pop)将需要O(n)的时间。我们可以优化在一行中连续弹出这一场景吗?"
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