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leetcode-problemset/leetcode-cn/originData/grumpy-bookstore-owner.json
2022-05-02 23:44:12 +08:00

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"question": {
"questionId": "1138",
"questionFrontendId": "1052",
"categoryTitle": "Algorithms",
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"title": "Grumpy Bookstore Owner",
"titleSlug": "grumpy-bookstore-owner",
"content": "<p>There is a bookstore owner that has a store open for <code>n</code> minutes. Every minute, some number of customers enter the store. You are given an integer array <code>customers</code> of length <code>n</code> where <code>customers[i]</code> is the number of the customer that enters the store at the start of the <code>i<sup>th</sup></code> minute and all those customers leave after the end of that minute.</p>\n\n<p>On some minutes, the bookstore owner is grumpy. You are given a binary array grumpy where <code>grumpy[i]</code> is <code>1</code> if the bookstore owner is grumpy during the <code>i<sup>th</sup></code> minute, and is <code>0</code> otherwise.</p>\n\n<p>When the bookstore owner is grumpy, the customers of that minute are not satisfied, otherwise, they are satisfied.</p>\n\n<p>The bookstore owner knows a secret technique to keep themselves not grumpy for <code>minutes</code> consecutive minutes, but can only use it once.</p>\n\n<p>Return <em>the maximum number of customers that can be satisfied throughout the day</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> customers = [1,0,1,2,1,1,7,5], grumpy = [0,1,0,1,0,1,0,1], minutes = 3\n<strong>Output:</strong> 16\n<strong>Explanation:</strong> The bookstore owner keeps themselves not grumpy for the last 3 minutes. \nThe maximum number of customers that can be satisfied = 1 + 1 + 1 + 1 + 7 + 5 = 16.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> customers = [1], grumpy = [0], minutes = 1\n<strong>Output:</strong> 1\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == customers.length == grumpy.length</code></li>\n\t<li><code>1 &lt;= minutes &lt;= n &lt;= 2 * 10<sup>4</sup></code></li>\n\t<li><code>0 &lt;= customers[i] &lt;= 1000</code></li>\n\t<li><code>grumpy[i]</code> is either <code>0</code> or <code>1</code>.</li>\n</ul>\n",
"translatedTitle": "爱生气的书店老板",
"translatedContent": "<p>有一个书店老板,他的书店开了&nbsp;<code>n</code>&nbsp;分钟。每分钟都有一些顾客进入这家商店。给定一个长度为 <code>n</code> 的整数数组 <code>customers</code> ,其中 <code>customers[i]</code> 是在第 <code>i</code> 分钟开始时进入商店的顾客的编号,所有这些顾客在第 <code>i</code> 分钟结束后离开。</p>\n\n<p>在某些时候,书店老板会生气。 如果书店老板在第 <code>i</code> 分钟生气,那么 <code>grumpy[i] = 1</code>,否则 <code>grumpy[i] = 0</code>。</p>\n\n<p>当书店老板生气时,那一分钟的顾客就会不满意,若老板不生气则顾客是满意的。</p>\n\n<p>书店老板知道一个秘密技巧,能抑制自己的情绪,可以让自己连续&nbsp;<code>minutes</code>&nbsp;分钟不生气,但却只能使用一次。</p>\n\n<p>请你返回 <em>这一天营业下来,最多有多少客户能够感到满意</em> 。<br />\n&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>customers = [1,0,1,2,1,1,7,5], grumpy = [0,1,0,1,0,1,0,1], minutes = 3\n<strong>输出:</strong>16\n<strong>解释:</strong>书店老板在最后 3 分钟保持冷静。\n感到满意的最大客户数量 = 1 + 1 + 1 + 1 + 7 + 5 = 16.\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>customers = [1], grumpy = [0], minutes = 1\n<strong>输出:</strong>1</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>n == customers.length == grumpy.length</code></li>\n\t<li><code>1 &lt;= minutes &lt;= n &lt;= 2 * 10<sup>4</sup></code></li>\n\t<li><code>0 &lt;= customers[i] &lt;= 1000</code></li>\n\t<li><code>grumpy[i] == 0 or 1</code></li>\n</ul>\n",
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"hints": [
"Say the store owner uses their power in minute 1 to X and we have some answer A. If they instead use their power from minute 2 to X+1, we only have to use data from minutes 1, 2, X and X+1 to update our answer A."
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