leetcode-problemset/leetcode-cn/originData/find-the-pivot-integer.json

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            "title": "Find the Pivot Integer",
            "titleSlug": "find-the-pivot-integer",
            "content": "<p>Given a positive integer <code>n</code>, find the <strong>pivot integer</strong> <code>x</code> such that:</p>\n\n<ul>\n\t<li>The sum of all elements between <code>1</code> and <code>x</code> inclusively equals the sum of all elements between <code>x</code> and <code>n</code> inclusively.</li>\n</ul>\n\n<p>Return <em>the pivot integer </em><code>x</code>. If no such integer exists, return <code>-1</code>. It is guaranteed that there will be at most one pivot index for the given input.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 8\n<strong>Output:</strong> 6\n<strong>Explanation:</strong> 6 is the pivot integer since: 1 + 2 + 3 + 4 + 5 + 6 = 6 + 7 + 8 = 21.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 1\n<strong>Output:</strong> 1\n<strong>Explanation:</strong> 1 is the pivot integer since: 1 = 1.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 4\n<strong>Output:</strong> -1\n<strong>Explanation:</strong> It can be proved that no such integer exist.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 1000</code></li>\n</ul>\n",
            "translatedTitle": "找出中枢整数",
            "translatedContent": "<p>给你一个正整数 <code>n</code> ，找出满足下述条件的<strong> 中枢整数</strong> <code>x</code> ：</p>\n\n<ul>\n\t<li><code>1</code> 和 <code>x</code> 之间的所有元素之和等于 <code>x</code> 和 <code>n</code> 之间所有元素之和。</li>\n</ul>\n\n<p>返回中枢整数<em> </em><code>x</code> 。如果不存在中枢整数，则返回 <code>-1</code> 。题目保证对于给定的输入，至多存在一个中枢整数。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>n = 8\n<strong>输出：</strong>6\n<strong>解释：</strong>6 是中枢整数，因为 1 + 2 + 3 + 4 + 5 + 6 = 6 + 7 + 8 = 21 。\n</pre>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>n = 1\n<strong>输出：</strong>1\n<strong>解释：</strong>1 是中枢整数，因为 1 = 1 。\n</pre>\n\n<p><strong class=\"example\">示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>n = 4\n<strong>输出：</strong>-1\n<strong>解释：</strong>可以证明不存在满足题目要求的整数。</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 1000</code></li>\n</ul>\n",
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                    "code": "class Solution(object):\n    def pivotInteger(self, n):\n        \"\"\"\n        :type n: int\n        :rtype: int\n        \"\"\"",
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                    "code": "/**\n * @param {number} n\n * @return {number}\n */\nvar pivotInteger = function(n) {\n\n};",
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                    "code": "# @param {Integer} n\n# @return {Integer}\ndef pivot_integer(n)\n\nend",
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            "hints": [
                "Can you use brute force to check every number from 1 to n if any of them is the pivot integer?",
                "If you know the sum of [1: pivot], how can you efficiently calculate the sum of the other parts?"
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