leetcode-problemset/leetcode-cn/originData/find-the-duplicate-number.json

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            "title": "Find the Duplicate Number",
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            "content": "<p>Given an array of integers <code>nums</code> containing&nbsp;<code>n + 1</code> integers where each integer is in the range <code>[1, n]</code> inclusive.</p>\n\n<p>There is only <strong>one repeated number</strong> in <code>nums</code>, return <em>this&nbsp;repeated&nbsp;number</em>.</p>\n\n<p>You must solve the problem <strong>without</strong> modifying the array <code>nums</code>&nbsp;and uses only constant extra space.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,3,4,2,2]\n<strong>Output:</strong> 2\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [3,1,3,4,2]\n<strong>Output:</strong> 3\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>nums.length == n + 1</code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= n</code></li>\n\t<li>All the integers in <code>nums</code> appear only <strong>once</strong> except for <strong>precisely one integer</strong> which appears <strong>two or more</strong> times.</li>\n</ul>\n\n<p>&nbsp;</p>\n<p><b>Follow up:</b></p>\n\n<ul>\n\t<li>How can we prove that at least one duplicate number must exist in <code>nums</code>?</li>\n\t<li>Can you solve the problem in linear runtime complexity?</li>\n</ul>\n",
            "translatedTitle": "寻找重复数",
            "translatedContent": "<p>给定一个包含&nbsp;<code>n + 1</code> 个整数的数组&nbsp;<code>nums</code> ，其数字都在&nbsp;<code>[1, n]</code>&nbsp;范围内（包括 <code>1</code> 和 <code>n</code>），可知至少存在一个重复的整数。</p>\n\n<p>假设 <code>nums</code> 只有 <strong>一个重复的整数</strong> ，返回&nbsp;<strong>这个重复的数</strong> 。</p>\n\n<p>你设计的解决方案必须 <strong>不修改</strong> 数组 <code>nums</code> 且只用常量级 <code>O(1)</code> 的额外空间。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [1,3,4,2,2]\n<strong>输出：</strong>2\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [3,1,3,4,2]\n<strong>输出：</strong>3\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>nums.length == n + 1</code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= n</code></li>\n\t<li><code>nums</code> 中 <strong>只有一个整数</strong> 出现 <strong>两次或多次</strong> ，其余整数均只出现 <strong>一次</strong></li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><b>进阶：</b></p>\n\n<ul>\n\t<li>如何证明 <code>nums</code> 中至少存在一个重复的数字?</li>\n\t<li>你可以设计一个线性级时间复杂度 <code>O(n)</code> 的解决方案吗？</li>\n</ul>\n",
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