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"categoryTitle": "Algorithms",
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"title": "Divide Intervals Into Minimum Number of Groups",
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"content": "<p>You are given a 2D integer array <code>intervals</code> where <code>intervals[i] = [left<sub>i</sub>, right<sub>i</sub>]</code> represents the <strong>inclusive</strong> interval <code>[left<sub>i</sub>, right<sub>i</sub>]</code>.</p>\n\n<p>You have to divide the intervals into one or more <strong>groups</strong> such that each interval is in <strong>exactly</strong> one group, and no two intervals that are in the same group <strong>intersect</strong> each other.</p>\n\n<p>Return <em>the <strong>minimum</strong> number of groups you need to make</em>.</p>\n\n<p>Two intervals <strong>intersect</strong> if there is at least one common number between them. For example, the intervals <code>[1, 5]</code> and <code>[5, 8]</code> intersect.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> intervals = [[5,10],[6,8],[1,5],[2,3],[1,10]]\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> We can divide the intervals into the following groups:\n- Group 1: [1, 5], [6, 8].\n- Group 2: [2, 3], [5, 10].\n- Group 3: [1, 10].\nIt can be proven that it is not possible to divide the intervals into fewer than 3 groups.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> intervals = [[1,3],[5,6],[8,10],[11,13]]\n<strong>Output:</strong> 1\n<strong>Explanation:</strong> None of the intervals overlap, so we can put all of them in one group.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= intervals.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>intervals[i].length == 2</code></li>\n\t<li><code>1 &lt;= left<sub>i</sub> &lt;= right<sub>i</sub> &lt;= 10<sup>6</sup></code></li>\n</ul>\n",
"translatedTitle": "将区间分为最少组数",
"translatedContent": "<p>给你一个二维整数数组&nbsp;<code>intervals</code>&nbsp;,其中&nbsp;<code>intervals[i] = [left<sub>i</sub>, right<sub>i</sub>]</code>&nbsp;表示 <strong>闭</strong>&nbsp;区间&nbsp;<code>[left<sub>i</sub>, right<sub>i</sub>]</code>&nbsp;。</p>\n\n<p>你需要将&nbsp;<code>intervals</code> 划分为一个或者多个区间&nbsp;<strong>组</strong>&nbsp;,每个区间 <b>只</b>&nbsp;属于一个组,且同一个组中任意两个区间 <strong>不相交</strong>&nbsp;。</p>\n\n<p>请你返回 <strong>最少</strong>&nbsp;需要划分成多少个组。</p>\n\n<p>如果两个区间覆盖的范围有重叠(即至少有一个公共数字),那么我们称这两个区间是 <strong>相交</strong>&nbsp;的。比方说区间&nbsp;<code>[1, 5]</code> 和&nbsp;<code>[5, 8]</code>&nbsp;相交。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<b>输入:</b>intervals = [[5,10],[6,8],[1,5],[2,3],[1,10]]\n<b>输出:</b>3\n<b>解释:</b>我们可以将区间划分为如下的区间组:\n- 第 1 组:[1, 5] [6, 8] 。\n- 第 2 组:[2, 3] [5, 10] 。\n- 第 3 组:[1, 10] 。\n可以证明无法将区间划分为少于 3 个组。\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<b>输入:</b>intervals = [[1,3],[5,6],[8,10],[11,13]]\n<b>输出:</b>1\n<b>解释:</b>所有区间互不相交,所以我们可以把它们全部放在一个组内。</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= intervals.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>intervals[i].length == 2</code></li>\n\t<li><code>1 &lt;= left<sub>i</sub> &lt;= right<sub>i</sub> &lt;= 10<sup>6</sup></code></li>\n</ul>\n",
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"The minimum number of groups we need is equivalent to the maximum number of intervals that overlap at some point. How can you find that?"
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