mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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186 lines
26 KiB
JSON
186 lines
26 KiB
JSON
{
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"data": {
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"question": {
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"questionId": "106",
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"questionFrontendId": "106",
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"categoryTitle": "Algorithms",
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"boundTopicId": 1486,
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"title": "Construct Binary Tree from Inorder and Postorder Traversal",
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"titleSlug": "construct-binary-tree-from-inorder-and-postorder-traversal",
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"content": "<p>Given two integer arrays <code>inorder</code> and <code>postorder</code> where <code>inorder</code> is the inorder traversal of a binary tree and <code>postorder</code> is the postorder traversal of the same tree, construct and return <em>the binary tree</em>.</p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/02/19/tree.jpg\" style=\"width: 277px; height: 302px;\" />\n<pre>\n<strong>Input:</strong> inorder = [9,3,15,20,7], postorder = [9,15,7,20,3]\n<strong>Output:</strong> [3,9,20,null,null,15,7]\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> inorder = [-1], postorder = [-1]\n<strong>Output:</strong> [-1]\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= inorder.length <= 3000</code></li>\n\t<li><code>postorder.length == inorder.length</code></li>\n\t<li><code>-3000 <= inorder[i], postorder[i] <= 3000</code></li>\n\t<li><code>inorder</code> and <code>postorder</code> consist of <strong>unique</strong> values.</li>\n\t<li>Each value of <code>postorder</code> also appears in <code>inorder</code>.</li>\n\t<li><code>inorder</code> is <strong>guaranteed</strong> to be the inorder traversal of the tree.</li>\n\t<li><code>postorder</code> is <strong>guaranteed</strong> to be the postorder traversal of the tree.</li>\n</ul>\n",
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"translatedTitle": "从中序与后序遍历序列构造二叉树",
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"translatedContent": "<p>给定两个整数数组 <code>inorder</code> 和 <code>postorder</code> ，其中 <code>inorder</code> 是二叉树的中序遍历， <code>postorder</code> 是同一棵树的后序遍历，请你构造并返回这颗 <em>二叉树</em> 。</p>\n\n<p> </p>\n\n<p><strong>示例 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/02/19/tree.jpg\" />\n<pre>\n<b>输入：</b>inorder = [9,3,15,20,7], postorder = [9,15,7,20,3]\n<b>输出：</b>[3,9,20,null,null,15,7]\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre>\n<b>输入：</b>inorder = [-1], postorder = [-1]\n<b>输出：</b>[-1]\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 <= inorder.length <= 3000</code></li>\n\t<li><code>postorder.length == inorder.length</code></li>\n\t<li><code>-3000 <= inorder[i], postorder[i] <= 3000</code></li>\n\t<li><code>inorder</code> 和 <code>postorder</code> 都由 <strong>不同</strong> 的值组成</li>\n\t<li><code>postorder</code> 中每一个值都在 <code>inorder</code> 中</li>\n\t<li><code>inorder</code> <strong>保证</strong>是树的中序遍历</li>\n\t<li><code>postorder</code> <strong>保证</strong>是树的后序遍历</li>\n</ul>\n",
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"difficulty": "Medium",
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"name": "Binary Tree",
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"lang": "C++",
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"code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n * int val;\n * TreeNode *left;\n * TreeNode *right;\n * TreeNode() : val(0), left(nullptr), right(nullptr) {}\n * TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}\n * TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}\n * };\n */\nclass Solution {\npublic:\n TreeNode* buildTree(vector<int>& inorder, vector<int>& postorder) {\n\n }\n};",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * int val;\n * TreeNode left;\n * TreeNode right;\n * TreeNode() {}\n * TreeNode(int val) { this.val = val; }\n * TreeNode(int val, TreeNode left, TreeNode right) {\n * this.val = val;\n * this.left = left;\n * this.right = right;\n * }\n * }\n */\nclass Solution {\n public TreeNode buildTree(int[] inorder, int[] postorder) {\n\n }\n}",
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"code": "# Definition for a binary tree node.\n# class TreeNode(object):\n# def __init__(self, val=0, left=None, right=None):\n# self.val = val\n# self.left = left\n# self.right = right\nclass Solution(object):\n def buildTree(self, inorder, postorder):\n \"\"\"\n :type inorder: List[int]\n :type postorder: List[int]\n :rtype: TreeNode\n \"\"\"",
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"code": "# Definition for a binary tree node.\n# class TreeNode:\n# def __init__(self, val=0, left=None, right=None):\n# self.val = val\n# self.left = left\n# self.right = right\nclass Solution:\n def buildTree(self, inorder: List[int], postorder: List[int]) -> TreeNode:",
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"code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n * int val;\n * struct TreeNode *left;\n * struct TreeNode *right;\n * };\n */\n\n\nstruct TreeNode* buildTree(int* inorder, int inorderSize, int* postorder, int postorderSize){\n\n}",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public int val;\n * public TreeNode left;\n * public TreeNode right;\n * public TreeNode(int val=0, TreeNode left=null, TreeNode right=null) {\n * this.val = val;\n * this.left = left;\n * this.right = right;\n * }\n * }\n */\npublic class Solution {\n public TreeNode BuildTree(int[] inorder, int[] postorder) {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * function TreeNode(val, left, right) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n */\n/**\n * @param {number[]} inorder\n * @param {number[]} postorder\n * @return {TreeNode}\n */\nvar buildTree = function(inorder, postorder) {\n\n};",
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"lang": "Ruby",
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"code": "# Definition for a binary tree node.\n# class TreeNode\n# attr_accessor :val, :left, :right\n# def initialize(val = 0, left = nil, right = nil)\n# @val = val\n# @left = left\n# @right = right\n# end\n# end\n# @param {Integer[]} inorder\n# @param {Integer[]} postorder\n# @return {TreeNode}\ndef build_tree(inorder, postorder)\n\nend",
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"lang": "Swift",
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"langSlug": "swift",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public var val: Int\n * public var left: TreeNode?\n * public var right: TreeNode?\n * public init() { self.val = 0; self.left = nil; self.right = nil; }\n * public init(_ val: Int) { self.val = val; self.left = nil; self.right = nil; }\n * public init(_ val: Int, _ left: TreeNode?, _ right: TreeNode?) {\n * self.val = val\n * self.left = left\n * self.right = right\n * }\n * }\n */\nclass Solution {\n func buildTree(_ inorder: [Int], _ postorder: [Int]) -> TreeNode? {\n\n }\n}",
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"lang": "Go",
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"code": "/**\n * Definition for a binary tree node.\n * type TreeNode struct {\n * Val int\n * Left *TreeNode\n * Right *TreeNode\n * }\n */\nfunc buildTree(inorder []int, postorder []int) *TreeNode {\n\n}",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode(_value: Int = 0, _left: TreeNode = null, _right: TreeNode = null) {\n * var value: Int = _value\n * var left: TreeNode = _left\n * var right: TreeNode = _right\n * }\n */\nobject Solution {\n def buildTree(inorder: Array[Int], postorder: Array[Int]): TreeNode = {\n\n }\n}",
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"code": "/**\n * Example:\n * var ti = TreeNode(5)\n * var v = ti.`val`\n * Definition for a binary tree node.\n * class TreeNode(var `val`: Int) {\n * var left: TreeNode? = null\n * var right: TreeNode? = null\n * }\n */\nclass Solution {\n fun buildTree(inorder: IntArray, postorder: IntArray): TreeNode? {\n\n }\n}",
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"code": "// Definition for a binary tree node.\n// #[derive(Debug, PartialEq, Eq)]\n// pub struct TreeNode {\n// pub val: i32,\n// pub left: Option<Rc<RefCell<TreeNode>>>,\n// pub right: Option<Rc<RefCell<TreeNode>>>,\n// }\n//\n// impl TreeNode {\n// #[inline]\n// pub fn new(val: i32) -> Self {\n// TreeNode {\n// val,\n// left: None,\n// right: None\n// }\n// }\n// }\nuse std::rc::Rc;\nuse std::cell::RefCell;\nimpl Solution {\n pub fn build_tree(inorder: Vec<i32>, postorder: Vec<i32>) -> Option<Rc<RefCell<TreeNode>>> {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * public $val = null;\n * public $left = null;\n * public $right = null;\n * function __construct($val = 0, $left = null, $right = null) {\n * $this->val = $val;\n * $this->left = $left;\n * $this->right = $right;\n * }\n * }\n */\nclass Solution {\n\n /**\n * @param Integer[] $inorder\n * @param Integer[] $postorder\n * @return TreeNode\n */\n function buildTree($inorder, $postorder) {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * val: number\n * left: TreeNode | null\n * right: TreeNode | null\n * constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n * }\n */\n\nfunction buildTree(inorder: number[], postorder: number[]): TreeNode | null {\n\n};",
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