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leetcode-problemset/leetcode-cn/originData/coin-change-2.json
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"categoryTitle": "Algorithms",
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"title": "Coin Change 2",
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"content": "<p>You are given an integer array <code>coins</code> representing coins of different denominations and an integer <code>amount</code> representing a total amount of money.</p>\n\n<p>Return <em>the number of combinations that make up that amount</em>. If that amount of money cannot be made up by any combination of the coins, return <code>0</code>.</p>\n\n<p>You may assume that you have an infinite number of each kind of coin.</p>\n\n<p>The answer is <strong>guaranteed</strong> to fit into a signed <strong>32-bit</strong> integer.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> amount = 5, coins = [1,2,5]\n<strong>Output:</strong> 4\n<strong>Explanation:</strong> there are four ways to make up the amount:\n5=5\n5=2+2+1\n5=2+1+1+1\n5=1+1+1+1+1\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> amount = 3, coins = [2]\n<strong>Output:</strong> 0\n<strong>Explanation:</strong> the amount of 3 cannot be made up just with coins of 2.\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> amount = 10, coins = [10]\n<strong>Output:</strong> 1\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= coins.length &lt;= 300</code></li>\n\t<li><code>1 &lt;= coins[i] &lt;= 5000</code></li>\n\t<li>All the values of <code>coins</code> are <strong>unique</strong>.</li>\n\t<li><code>0 &lt;= amount &lt;= 5000</code></li>\n</ul>\n",
"translatedTitle": "零钱兑换 II",
"translatedContent": "<p>给你一个整数数组 <code>coins</code> 表示不同面额的硬币,另给一个整数 <code>amount</code> 表示总金额。</p>\n\n<p>请你计算并返回可以凑成总金额的硬币组合数。如果任何硬币组合都无法凑出总金额,返回 <code>0</code> 。</p>\n\n<p>假设每一种面额的硬币有无限个。 </p>\n\n<p>题目数据保证结果符合 32 位带符号整数。</p>\n\n<p> </p>\n\n<ul>\n</ul>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>amount = 5, coins = [1, 2, 5]\n<strong>输出:</strong>4\n<strong>解释:</strong>有四种方式可以凑成总金额:\n5=5\n5=2+2+1\n5=2+1+1+1\n5=1+1+1+1+1\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>amount = 3, coins = [2]\n<strong>输出:</strong>0\n<strong>解释:</strong>只用面额 2 的硬币不能凑成总金额 3 。\n</pre>\n\n<p><strong>示例 3</strong></p>\n\n<pre>\n<strong>输入:</strong>amount = 10, coins = [10] \n<strong>输出:</strong>1\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 <= coins.length <= 300</code></li>\n\t<li><code>1 <= coins[i] <= 5000</code></li>\n\t<li><code>coins</code> 中的所有值 <strong>互不相同</strong></li>\n\t<li><code>0 <= amount <= 5000</code></li>\n</ul>\n",
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