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leetcode-problemset/leetcode-cn/originData/check-if-string-is-transformable-with-substring-sort-operations.json
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{
"data": {
"question": {
"questionId": "1707",
"questionFrontendId": "1585",
"categoryTitle": "Algorithms",
"boundTopicId": 407645,
"title": "Check If String Is Transformable With Substring Sort Operations",
"titleSlug": "check-if-string-is-transformable-with-substring-sort-operations",
"content": "<p>Given two strings <code>s</code> and <code>t</code>, transform string <code>s</code> into string <code>t</code> using the following operation any number of times:</p>\n\n<ul>\n\t<li>Choose a <strong>non-empty</strong> substring in <code>s</code> and sort it in place so the characters are in <strong>ascending order</strong>.\n\n\t<ul>\n\t\t<li>For example, applying the operation on the underlined substring in <code>&quot;1<u>4234</u>&quot;</code> results in <code>&quot;1<u>2344</u>&quot;</code>.</li>\n\t</ul>\n\t</li>\n</ul>\n\n<p>Return <code>true</code> if <em>it is possible to transform <code>s</code> into <code>t</code></em>. Otherwise, return <code>false</code>.</p>\n\n<p>A <strong>substring</strong> is a contiguous sequence of characters within a string.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;84532&quot;, t = &quot;34852&quot;\n<strong>Output:</strong> true\n<strong>Explanation:</strong> You can transform s into t using the following sort operations:\n&quot;84<u>53</u>2&quot; (from index 2 to 3) -&gt; &quot;84<u>35</u>2&quot;\n&quot;<u>843</u>52&quot; (from index 0 to 2) -&gt; &quot;<u>348</u>52&quot;\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;34521&quot;, t = &quot;23415&quot;\n<strong>Output:</strong> true\n<strong>Explanation:</strong> You can transform s into t using the following sort operations:\n&quot;<u>3452</u>1&quot; -&gt; &quot;<u>2345</u>1&quot;\n&quot;234<u>51</u>&quot; -&gt; &quot;234<u>15</u>&quot;\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;12345&quot;, t = &quot;12435&quot;\n<strong>Output:</strong> false\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>s.length == t.length</code></li>\n\t<li><code>1 &lt;= s.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>s</code> and <code>t</code> consist of only digits.</li>\n</ul>\n",
"translatedTitle": "检查字符串是否可以通过排序子字符串得到另一个字符串",
"translatedContent": "<p>给你两个字符串&nbsp;<code>s</code> 和&nbsp;<code>t</code>&nbsp;,请你通过若干次以下操作将字符串&nbsp;<code>s</code>&nbsp;转化成字符串&nbsp;<code>t</code>&nbsp;</p>\n\n<ul>\n\t<li>选择 <code>s</code>&nbsp;中一个 <strong>非空</strong>&nbsp;子字符串并将它包含的字符就地 <strong>升序</strong>&nbsp;排序。</li>\n</ul>\n\n<p>比方说,对下划线所示的子字符串进行操作可以由&nbsp;<code>&quot;1<strong>4234</strong>&quot;</code>&nbsp;得到&nbsp;<code>&quot;1<strong>2344</strong>&quot;</code>&nbsp;。</p>\n\n<p>如果可以将字符串 <code>s</code>&nbsp;变成 <code>t</code>&nbsp;,返回 <code>true</code>&nbsp;。否则,返回 <code>false</code>&nbsp;。</p>\n\n<p>一个 <strong>子字符串</strong>&nbsp;定义为一个字符串中连续的若干字符。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>s = &quot;84532&quot;, t = &quot;34852&quot;\n<strong>输出:</strong>true\n<strong>解释:</strong>你可以按以下操作将 s 转变为 t \n&quot;84<strong>53</strong>2&quot; (从下标 2 到下标 3-&gt; &quot;84<strong>35</strong>2&quot;\n&quot;<strong>843</strong>52&quot; (从下标 0 到下标 2 -&gt; &quot;<strong>348</strong>52&quot;\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>s = &quot;34521&quot;, t = &quot;23415&quot;\n<strong>输出:</strong>true\n<strong>解释:</strong>你可以按以下操作将 s 转变为 t \n&quot;<strong>3452</strong>1&quot; -&gt; &quot;<strong>2345</strong>1&quot;\n&quot;234<strong>51</strong>&quot; -&gt; &quot;234<strong>15</strong>&quot;\n</pre>\n\n<p><strong>示例 3</strong></p>\n\n<pre>\n<strong>输入:</strong>s = &quot;12345&quot;, t = &quot;12435&quot;\n<strong>输出:</strong>false\n</pre>\n\n<p><strong>示例 4</strong></p>\n\n<pre>\n<strong>输入:</strong>s = &quot;1&quot;, t = &quot;2&quot;\n<strong>输出:</strong>false\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>s.length == t.length</code></li>\n\t<li><code>1 &lt;= s.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>s</code> 和&nbsp;<code>t</code>&nbsp;都只包含数字字符,即&nbsp;<code>&#39;0&#39;</code>&nbsp;到&nbsp;<code>&#39;9&#39;</code> 。</li>\n</ul>\n",
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"Suppose the first digit you need is 'd'. How can you determine if it's possible to get that digit there?",
"Consider swapping adjacent characters to maintain relative ordering."
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