mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-11 02:58:13 +08:00
177 lines
21 KiB
JSON
177 lines
21 KiB
JSON
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"categoryTitle": "Algorithms",
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"title": "Best Team With No Conflicts",
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"content": "<p>You are the manager of a basketball team. For the upcoming tournament, you want to choose the team with the highest overall score. The score of the team is the <strong>sum</strong> of scores of all the players in the team.</p>\n\n<p>However, the basketball team is not allowed to have <strong>conflicts</strong>. A <strong>conflict</strong> exists if a younger player has a <strong>strictly higher</strong> score than an older player. A conflict does <strong>not</strong> occur between players of the same age.</p>\n\n<p>Given two lists, <code>scores</code> and <code>ages</code>, where each <code>scores[i]</code> and <code>ages[i]</code> represents the score and age of the <code>i<sup>th</sup></code> player, respectively, return <em>the highest overall score of all possible basketball teams</em>.</p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> scores = [1,3,5,10,15], ages = [1,2,3,4,5]\n<strong>Output:</strong> 34\n<strong>Explanation:</strong> You can choose all the players.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> scores = [4,5,6,5], ages = [2,1,2,1]\n<strong>Output:</strong> 16\n<strong>Explanation:</strong> It is best to choose the last 3 players. Notice that you are allowed to choose multiple people of the same age.\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> scores = [1,2,3,5], ages = [8,9,10,1]\n<strong>Output:</strong> 6\n<strong>Explanation:</strong> It is best to choose the first 3 players. \n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= scores.length, ages.length <= 1000</code></li>\n\t<li><code>scores.length == ages.length</code></li>\n\t<li><code>1 <= scores[i] <= 10<sup>6</sup></code></li>\n\t<li><code>1 <= ages[i] <= 1000</code></li>\n</ul>\n",
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"translatedTitle": "无矛盾的最佳球队",
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"translatedContent": "<p>假设你是球队的经理。对于即将到来的锦标赛，你想组合一支总体得分最高的球队。球队的得分是球队中所有球员的分数 <strong>总和</strong> 。</p>\n\n<p>然而，球队中的矛盾会限制球员的发挥，所以必须选出一支 <strong>没有矛盾</strong> 的球队。如果一名年龄较小球员的分数 <strong>严格大于</strong> 一名年龄较大的球员，则存在矛盾。同龄球员之间不会发生矛盾。</p>\n\n<p>给你两个列表 <code>scores</code> 和 <code>ages</code>，其中每组 <code>scores[i]</code> 和 <code>ages[i]</code> 表示第 <code>i</code> 名球员的分数和年龄。请你返回 <strong>所有可能的无矛盾球队中得分最高那支的分数</strong> 。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><strong>输入：</strong>scores = [1,3,5,10,15], ages = [1,2,3,4,5]\n<strong>输出：</strong>34\n<strong>解释：</strong>你可以选中所有球员。</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入：</strong>scores = [4,5,6,5], ages = [2,1,2,1]\n<strong>输出：</strong>16\n<strong>解释：</strong>最佳的选择是后 3 名球员。注意，你可以选中多个同龄球员。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre><strong>输入：</strong>scores = [1,2,3,5], ages = [8,9,10,1]\n<strong>输出：</strong>6\n<strong>解释：</strong>最佳的选择是前 3 名球员。\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= scores.length, ages.length <= 1000</code></li>\n\t<li><code>scores.length == ages.length</code></li>\n\t<li><code>1 <= scores[i] <= 10<sup>6</sup></code></li>\n\t<li><code>1 <= ages[i] <= 1000</code></li>\n</ul>\n",
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"First, sort players by age and break ties by their score. You can now consider the players from left to right.",
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