leetcode-problemset/leetcode-cn/originData/average-value-of-even-numbers-that-are-divisible-by-three.json

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            "title": "Average Value of Even Numbers That Are Divisible by Three",
            "titleSlug": "average-value-of-even-numbers-that-are-divisible-by-three",
            "content": "<p>Given an integer array <code>nums</code> of <strong>positive</strong> integers, return <em>the average value of all even integers that are divisible by</em> <code>3</code><i>.</i></p>\n\n<p>Note that the <strong>average</strong> of <code>n</code> elements is the <strong>sum</strong> of the <code>n</code> elements divided by <code>n</code> and <strong>rounded down</strong> to the nearest integer.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,3,6,10,12,15]\n<strong>Output:</strong> 9\n<strong>Explanation:</strong> 6 and 12 are even numbers that are divisible by 3. (6 + 12) / 2 = 9.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,2,4,7,10]\n<strong>Output:</strong> 0\n<strong>Explanation:</strong> There is no single number that satisfies the requirement, so return 0.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 1000</code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 1000</code></li>\n</ul>\n",
            "translatedTitle": "可被三整除的偶数的平均值",
            "translatedContent": "<p>给你一个由正整数组成的整数数组 <code>nums</code> ，返回其中可被 <code>3</code> 整除的所有偶数的平均值。</p>\n\n<p>注意：<code>n</code> 个元素的平均值等于 <code>n</code> 个元素 <strong>求和</strong> 再除以 <code>n</code> ，结果 <strong>向下取整</strong> 到最接近的整数。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [1,3,6,10,12,15]\n<strong>输出：</strong>9\n<strong>解释：</strong>6 和 12 是可以被 3 整除的偶数。(6 + 12) / 2 = 9 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [1,2,4,7,10]\n<strong>输出：</strong>0\n<strong>解释：</strong>不存在满足题目要求的整数，所以返回 0 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 1000</code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 1000</code></li>\n</ul>\n",
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