leetcode-problemset/leetcode-cn/originData/array-with-elements-not-equal-to-average-of-neighbors.json

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            "categoryTitle": "Algorithms",
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            "title": "Array With Elements Not Equal to Average of Neighbors",
            "titleSlug": "array-with-elements-not-equal-to-average-of-neighbors",
            "content": "<p>You are given a <strong>0-indexed</strong> array <code>nums</code> of <strong>distinct</strong> integers. You want to rearrange the elements in the array such that every element in the rearranged array is <strong>not</strong> equal to the <strong>average</strong> of its neighbors.</p>\n\n<p>More formally, the rearranged array should have the property such that for every <code>i</code> in the range <code>1 &lt;= i &lt; nums.length - 1</code>, <code>(nums[i-1] + nums[i+1]) / 2</code> is <strong>not</strong> equal to <code>nums[i]</code>.</p>\n\n<p>Return <em><strong>any</strong> rearrangement of </em><code>nums</code><em> that meets the requirements</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,2,3,4,5]\n<strong>Output:</strong> [1,2,4,5,3]\n<strong>Explanation:</strong>\nWhen i=1, nums[i] = 2, and the average of its neighbors is (1+4) / 2 = 2.5.\nWhen i=2, nums[i] = 4, and the average of its neighbors is (2+5) / 2 = 3.5.\nWhen i=3, nums[i] = 5, and the average of its neighbors is (4+3) / 2 = 3.5.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [6,2,0,9,7]\n<strong>Output:</strong> [9,7,6,2,0]\n<strong>Explanation:</strong>\nWhen i=1, nums[i] = 7, and the average of its neighbors is (9+6) / 2 = 7.5.\nWhen i=2, nums[i] = 6, and the average of its neighbors is (7+2) / 2 = 4.5.\nWhen i=3, nums[i] = 2, and the average of its neighbors is (6+0) / 2 = 3.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>3 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>0 &lt;= nums[i] &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
            "translatedTitle": "构造元素不等于两相邻元素平均值的数组",
            "translatedContent": "<p>给你一个 <strong>下标从 0 开始</strong> 的数组 <code>nums</code> ，数组由若干 <strong>互不相同的</strong> 整数组成。你打算重新排列数组中的元素以满足：重排后，数组中的每个元素都 <strong>不等于</strong> 其两侧相邻元素的 <strong>平均值</strong> 。</p>\n\n<p>更公式化的说法是，重新排列的数组应当满足这一属性：对于范围&nbsp;<code>1 &lt;= i &lt; nums.length - 1</code> 中的每个 <code>i</code> ，<code>(nums[i-1] + nums[i+1]) / 2</code> <strong>不等于</strong> <code>nums[i]</code> 均成立 。</p>\n\n<p>返回满足题意的任一重排结果。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><strong>输入：</strong>nums = [1,2,3,4,5]\n<strong>输出：</strong>[1,2,4,5,3]\n<strong>解释：</strong>\ni=1, nums[i] = 2, 两相邻元素平均值为 (1+4) / 2 = 2.5\ni=2, nums[i] = 4, 两相邻元素平均值为 (2+5) / 2 = 3.5\ni=3, nums[i] = 5, 两相邻元素平均值为 (4+3) / 2 = 3.5\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入：</strong>nums = [6,2,0,9,7]\n<strong>输出：</strong>[9,7,6,2,0]\n<strong>解释：</strong>\ni=1, nums[i] = 7, 两相邻元素平均值为 (9+6) / 2 = 7.5\ni=2, nums[i] = 6, 两相邻元素平均值为 (7+2) / 2 = 4.5\ni=3, nums[i] = 2, 两相邻元素平均值为 (6+0) / 2 = 3\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>3 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>0 &lt;= nums[i] &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
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