leetcode-problemset/leetcode-cn/originData/3sum.json

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            "categoryTitle": "Algorithms",
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            "title": "3Sum",
            "titleSlug": "3sum",
            "content": "<p>Given an integer array nums, return all the triplets <code>[nums[i], nums[j], nums[k]]</code> such that <code>i != j</code>, <code>i != k</code>, and <code>j != k</code>, and <code>nums[i] + nums[j] + nums[k] == 0</code>.</p>\n\n<p>Notice that the solution set must not contain duplicate triplets.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n<pre><strong>Input:</strong> nums = [-1,0,1,2,-1,-4]\n<strong>Output:</strong> [[-1,-1,2],[-1,0,1]]\n</pre><p><strong>Example 2:</strong></p>\n<pre><strong>Input:</strong> nums = []\n<strong>Output:</strong> []\n</pre><p><strong>Example 3:</strong></p>\n<pre><strong>Input:</strong> nums = [0]\n<strong>Output:</strong> []\n</pre>\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>0 &lt;= nums.length &lt;= 3000</code></li>\n\t<li><code>-10<sup>5</sup> &lt;= nums[i] &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
            "translatedTitle": "三数之和",
            "translatedContent": "<p>给你一个包含 <code>n</code> 个整数的数组 <code>nums</code>，判断 <code>nums</code> 中是否存在三个元素 <em>a，b，c ，</em>使得 <em>a + b + c = </em>0 ？请你找出所有和为 <code>0</code> 且不重复的三元组。</p>\n\n<p><strong>注意：</strong>答案中不可以包含重复的三元组。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [-1,0,1,2,-1,-4]\n<strong>输出：</strong>[[-1,-1,2],[-1,0,1]]\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = []\n<strong>输出：</strong>[]\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [0]\n<strong>输出：</strong>[]\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>0 <= nums.length <= 3000</code></li>\n\t<li><code>-10<sup>5</sup> <= nums[i] <= 10<sup>5</sup></code></li>\n</ul>\n",
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                    "code": "class Solution {\npublic:\n    vector<vector<int>> threeSum(vector<int>& nums) {\n\n    }\n};",
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            "hints": [
                "So, we essentially need to find three numbers x, y, and z such that they add up to the given value. If we fix one of the numbers say x, we are left with the two-sum problem at hand!",
                "For the two-sum problem, if we fix one of the numbers, say <pre>x</pre>, we have to scan the entire array to find the next number<pre>y</pre> which is <pre>value - x</pre> where value is the input parameter. Can we change our array somehow so that this search becomes faster?",
                "The second train of thought for two-sum is, without changing the array, can we use additional space somehow? Like maybe a hash map to speed up the search?"
            ],
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