mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-11 02:58:13 +08:00
161 lines
20 KiB
JSON
161 lines
20 KiB
JSON
{
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"questionId": "1000561",
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"questionFrontendId": "LCP 73",
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"categoryTitle": "Algorithms",
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"boundTopicId": 2239148,
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"title": "探险营地",
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"translatedTitle": "探险营地",
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"translatedContent": "探险家小扣的行动轨迹,都将保存在记录仪中。`expeditions[i]` 表示小扣第 `i` 次探险记录,用一个字符串数组表示。其中的每个「营地」由大小写字母组成,通过子串 `->` 连接。\n> 例:\"Leet->code->Campsite\",表示到访了 \"Leet\"、\"code\"、\"Campsite\" 三个营地。\n\n`expeditions[0]` 包含了初始小扣已知的所有营地;对于之后的第 `i` 次探险(即 `expeditions[i]` 且 i > 0),如果记录中包含了之前均没出现的营地,则表示小扣 **新发现** 的营地。\n\n请你找出小扣发现新营地最多且索引最小的那次探险,并返回对应的记录索引。如果所有探险记录都没有发现新的营地,返回 `-1`\n\n**注意:**\n- 大小写不同的营地视为不同的营地;\n- 营地的名称长度均大于 `0`。\n\n**示例 1:**\n>输入:`expeditions = [\"leet->code\",\"leet->code->Campsite->Leet\",\"leet->code->leet->courier\"]`\n>\n>输出:`1`\n>\n>解释:\n>初始已知的所有营地为 \"leet\" 和 \"code\"\n>第 1 次,到访了 \"leet\"、\"code\"、\"Campsite\"、\"Leet\",新发现营地 2 处:\"Campsite\"、\"Leet\"\n>第 2 次,到访了 \"leet\"、\"code\"、\"courier\",新发现营地 1 处:\"courier\"\n>第 1 次探险发现的新营地数量最多,因此返回 `1`\n\n**示例 2:**\n>输入:`expeditions = [\"Alice->Dex\",\"\",\"Dex\"]`\n>\n>输出:`-1`\n>\n>解释:\n>初始已知的所有营地为 \"Alice\" 和 \"Dex\"\n>第 1 次,未到访任何营地;\n>第 2 次,到访了 \"Dex\",未新发现营地;\n>因为两次探险均未发现新的营地,返回 `-1`\n\n**示例 3:**\n>输入:`expeditions = [\"\",\"Gryffindor->Slytherin->Gryffindor\",\"Hogwarts->Hufflepuff->Ravenclaw\"]`\n>\n>输出:`2`\n>\n>解释:\n>初始未发现任何营地;\n>第 1 次,到访 \"Gryffindor\"、\"Slytherin\" 营地,其中重复到访 \"Gryffindor\" 两次,\n>因此新发现营地为 2 处:\"Gryffindor\"、\"Slytherin\"\n>第 2 次,到访 \"Hogwarts\"、\"Hufflepuff\"、\"Ravenclaw\" 营地;\n>新发现营地 3 处:\"Hogwarts\"、\"Hufflepuff\"、\"Ravenclaw\";\n>第 2 次探险发现的新营地数量最多,因此返回 `2`\n\n**提示:**\n- `1 <= expeditions.length <= 1000`\n- `0 <= expeditions[i].length <= 1000`\n- 探险记录中只包含大小写字母和子串\"->\"",
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"difficulty": "Medium",
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