1
0
mirror of https://gitee.com/coder-xiaomo/leetcode-problemset synced 2025-01-10 18:48:13 +08:00
Code Issues Projects Releases Wiki Activity GitHub Gitee
leetcode-problemset/leetcode-cn/problem (English)/N 次操作后的最大分数和(English) [maximize-score-after-n-operations].html

51 lines
1.6 KiB
HTML

<p>You are given <code>nums</code>, an array of positive integers of size <code>2 * n</code>. You must perform <code>n</code> operations on this array.</p>
<p>In the <code>i<sup>th</sup></code> operation <strong>(1-indexed)</strong>, you will:</p>
<ul>
<li>Choose two elements, <code>x</code> and <code>y</code>.</li>
<li>Receive a score of <code>i * gcd(x, y)</code>.</li>
<li>Remove <code>x</code> and <code>y</code> from <code>nums</code>.</li>
</ul>
<p>Return <em>the maximum score you can receive after performing </em><code>n</code><em> operations.</em></p>
<p>The function <code>gcd(x, y)</code> is the greatest common divisor of <code>x</code> and <code>y</code>.</p>
<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<pre>
<strong>Input:</strong> nums = [1,2]
<strong>Output:</strong> 1
<strong>Explanation:</strong>&nbsp;The optimal choice of operations is:
(1 * gcd(1, 2)) = 1
</pre>
<p><strong class="example">Example 2:</strong></p>
<pre>
<strong>Input:</strong> nums = [3,4,6,8]
<strong>Output:</strong> 11
<strong>Explanation:</strong>&nbsp;The optimal choice of operations is:
(1 * gcd(3, 6)) + (2 * gcd(4, 8)) = 3 + 8 = 11
</pre>
<p><strong class="example">Example 3:</strong></p>
<pre>
<strong>Input:</strong> nums = [1,2,3,4,5,6]
<strong>Output:</strong> 14
<strong>Explanation:</strong>&nbsp;The optimal choice of operations is:
(1 * gcd(1, 5)) + (2 * gcd(2, 4)) + (3 * gcd(3, 6)) = 1 + 4 + 9 = 14
</pre>
<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>
<ul>
<li><code>1 &lt;= n &lt;= 7</code></li>
<li><code>nums.length == 2 * n</code></li>
<li><code>1 &lt;= nums[i] &lt;= 10<sup>6</sup></code></li>
</ul>