leetcode-problemset/leetcode-cn/originData/valid-parenthesis-string.json

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        "question": {
            "questionId": "678",
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            "categoryTitle": "Algorithms",
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            "title": "Valid Parenthesis String",
            "titleSlug": "valid-parenthesis-string",
            "content": "<p>Given a string <code>s</code> containing only three types of characters: <code>&#39;(&#39;</code>, <code>&#39;)&#39;</code> and <code>&#39;*&#39;</code>, return <code>true</code> <em>if</em> <code>s</code> <em>is <strong>valid</strong></em>.</p>\n\n<p>The following rules define a <strong>valid</strong> string:</p>\n\n<ul>\n\t<li>Any left parenthesis <code>&#39;(&#39;</code> must have a corresponding right parenthesis <code>&#39;)&#39;</code>.</li>\n\t<li>Any right parenthesis <code>&#39;)&#39;</code> must have a corresponding left parenthesis <code>&#39;(&#39;</code>.</li>\n\t<li>Left parenthesis <code>&#39;(&#39;</code> must go before the corresponding right parenthesis <code>&#39;)&#39;</code>.</li>\n\t<li><code>&#39;*&#39;</code> could be treated as a single right parenthesis <code>&#39;)&#39;</code> or a single left parenthesis <code>&#39;(&#39;</code> or an empty string <code>&quot;&quot;</code>.</li>\n</ul>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<pre><strong>Input:</strong> s = \"()\"\n<strong>Output:</strong> true\n</pre><p><strong class=\"example\">Example 2:</strong></p>\n<pre><strong>Input:</strong> s = \"(*)\"\n<strong>Output:</strong> true\n</pre><p><strong class=\"example\">Example 3:</strong></p>\n<pre><strong>Input:</strong> s = \"(*))\"\n<strong>Output:</strong> true\n</pre>\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 100</code></li>\n\t<li><code>s[i]</code> is <code>&#39;(&#39;</code>, <code>&#39;)&#39;</code> or <code>&#39;*&#39;</code>.</li>\n</ul>\n",
            "translatedTitle": "有效的括号字符串",
            "translatedContent": "<p>给你一个只包含三种字符的字符串，支持的字符类型分别是 <code>'('</code>、<code>')'</code> 和 <code>'*'</code>。请你检验这个字符串是否为有效字符串，如果是 <strong>有效</strong> 字符串返回 <code>true</code> 。</p>\n\n<p><strong>有效</strong> 字符串符合如下规则：</p>\n\n<ul>\n\t<li>任何左括号 <code>'('</code>&nbsp;必须有相应的右括号 <code>')'</code>。</li>\n\t<li>任何右括号 <code>')'</code>&nbsp;必须有相应的左括号 <code>'('</code>&nbsp;。</li>\n\t<li>左括号 <code>'('</code> 必须在对应的右括号之前 <code>')'</code>。</li>\n\t<li><code>'*'</code>&nbsp;可以被视为单个右括号 <code>')'</code>&nbsp;，或单个左括号 <code>'('</code>&nbsp;，或一个空字符串 <code>\"\"</code>。</li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"()\"\n<strong>输出：</strong>true\n</pre>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"(*)\"\n<strong>输出：</strong>true\n</pre>\n\n<p><strong class=\"example\">示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"(*))\"\n<strong>输出：</strong>true\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 100</code></li>\n\t<li><code>s[i]</code> 为 <code>'('</code>、<code>')'</code> 或 <code>'*'</code></li>\n</ul>\n",
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            "hints": [
                "Use backtracking to explore all possible combinations of treating '*' as either '(', ')', or an empty string. If any combination leads to a valid string, return true.",
                "DP[i][j] represents whether the substring s[i:j] is valid.",
                "Keep track of the count of open parentheses encountered so far. If you encounter a close parenthesis, it should balance with an open parenthesis. Utilize a stack to handle this effectively.",
                "How about using 2 stacks instead of 1? Think about it."
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