leetcode-problemset/leetcode-cn/originData/swap-adjacent-in-lr-string.json

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        "question": {
            "questionId": "793",
            "questionFrontendId": "777",
            "categoryTitle": "Algorithms",
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            "title": "Swap Adjacent in LR String",
            "titleSlug": "swap-adjacent-in-lr-string",
            "content": "<p>In a string composed of <code>&#39;L&#39;</code>, <code>&#39;R&#39;</code>, and <code>&#39;X&#39;</code> characters, like <code>&quot;RXXLRXRXL&quot;</code>, a move consists of either replacing one occurrence of <code>&quot;XL&quot;</code> with <code>&quot;LX&quot;</code>, or replacing one occurrence of <code>&quot;RX&quot;</code> with <code>&quot;XR&quot;</code>. Given the starting string <code>start</code> and the ending string <code>result</code>, return <code>True</code> if and only if there exists a sequence of moves to transform <code>start</code> to <code>result</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> start = &quot;RXXLRXRXL&quot;, result = &quot;XRLXXRRLX&quot;\n<strong>Output:</strong> true\n<strong>Explanation:</strong> We can transform start to result following these steps:\nRXXLRXRXL -&gt;\nXRXLRXRXL -&gt;\nXRLXRXRXL -&gt;\nXRLXXRRXL -&gt;\nXRLXXRRLX\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> start = &quot;X&quot;, result = &quot;L&quot;\n<strong>Output:</strong> false\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= start.length&nbsp;&lt;= 10<sup>4</sup></code></li>\n\t<li><code>start.length == result.length</code></li>\n\t<li>Both <code>start</code> and <code>result</code> will only consist of characters in <code>&#39;L&#39;</code>, <code>&#39;R&#39;</code>, and&nbsp;<code>&#39;X&#39;</code>.</li>\n</ul>\n",
            "translatedTitle": "在 LR 字符串中交换相邻字符",
            "translatedContent": "<p>在一个由 <code>'L'</code> , <code>'R'</code> 和 <code>'X'</code> 三个字符组成的字符串（例如<code>\"RXXLRXRXL\"</code>）中进行移动操作。一次移动操作指用一个&nbsp;<code>\"LX\"</code>&nbsp;替换一个&nbsp;<code>\"XL\"</code>，或者用一个&nbsp;<code>\"XR\"</code>&nbsp;替换一个&nbsp;<code>\"RX\"</code>。现给定起始字符串&nbsp;<code>start</code>&nbsp;和结束字符串&nbsp;<code>result</code>，请编写代码，当且仅当存在一系列移动操作使得&nbsp;<code>start</code>&nbsp;可以转换成&nbsp;<code>result</code>&nbsp;时， 返回&nbsp;<code>True</code>。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>start = \"RXXLRXRXL\", result = \"XRLXXRRLX\"\n<strong>输出：</strong>true\n<strong>解释：</strong>通过以下步骤我们可以将 start 转化为 result：\nRXXLRXRXL -&gt;\nXRXLRXRXL -&gt;\nXRLXRXRXL -&gt;\nXRLXXRRXL -&gt;\nXRLXXRRLX\n</pre>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>start = \"X\", result = \"L\"\n<strong>输出：</strong>false\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= start.length&nbsp;&lt;= 10<sup>4</sup></code></li>\n\t<li><code>start.length == result.length</code></li>\n\t<li><code>start</code> 和&nbsp;<code>result</code>&nbsp;都只包含&nbsp;<code>'L'</code>, <code>'R'</code>&nbsp;或&nbsp;<code>'X'</code>。</li>\n</ul>\n",
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                "Think of the L and R's as people on a horizontal line, where X is a space.  The people can't cross each other, and also you can't go from XRX to RXX."
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