mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-09-05 23:41:41 +08:00
196 lines
23 KiB
JSON
196 lines
23 KiB
JSON
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"questionId": "100348",
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"questionFrontendId": "面试题 08.08",
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"categoryTitle": "LCCI",
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"boundTopicId": 90883,
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"title": "Permutation II LCCI",
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"titleSlug": "permutation-ii-lcci",
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"content": "<p>Write a method to compute all permutations of a string whose characters are not necessarily unique. The list of permutations should not have duplicates.</p>\r\n\r\n<p><strong>Example1:</strong></p>\r\n\r\n<pre>\r\n<strong> Input</strong>: S = "qqe"\r\n<strong> Output</strong>: ["eqq","qeq","qqe"]\r\n</pre>\r\n\r\n<p><strong>Example2:</strong></p>\r\n\r\n<pre>\r\n<strong> Input</strong>: S = "ab"\r\n<strong> Output</strong>: ["ab", "ba"]\r\n</pre>\r\n\r\n<p><strong>Note:</strong></p>\r\n\r\n<ol>\r\n\t<li>All characters are English letters.</li>\r\n\t<li><code>1 <= S.length <= 9</code></li>\r\n</ol>\r\n",
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"translatedTitle": "有重复字符串的排列组合",
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"translatedContent": "<p>有重复字符串的排列组合。编写一种方法,计算某字符串的所有排列组合。</p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre>\n<strong> 输入</strong>:S = \"qqe\"\n<strong> 输出</strong>:[\"eqq\",\"qeq\",\"qqe\"]\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre>\n<strong> 输入</strong>:S = \"ab\"\n<strong> 输出</strong>:[\"ab\", \"ba\"]\n</pre>\n\n<p><strong>提示:</strong></p>\n\n<ol>\n\t<li>字符都是英文字母。</li>\n\t<li>字符串长度在[1, 9]之间。</li>\n</ol>\n",
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"difficulty": "Medium",
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"name": "String",
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"slug": "string",
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"translatedName": "字符串",
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"lang": "C++",
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"langSlug": "cpp",
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"code": "class Solution {\npublic:\n vector<string> permutation(string S) {\n \n }\n};",
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"lang": "Java",
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"langSlug": "java",
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"code": "class Solution {\n public String[] permutation(String S) {\n \n }\n}",
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},
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"lang": "Python",
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"langSlug": "python",
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"code": "class Solution(object):\n def permutation(self, S):\n \"\"\"\n :type S: str\n :rtype: List[str]\n \"\"\"\n ",
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"__typename": "CodeSnippetNode"
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"langSlug": "python3",
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"code": "class Solution:\n def permutation(self, S: str) -> List[str]:\n ",
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"lang": "C",
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"langSlug": "c",
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"code": "/**\n * Note: The returned array must be malloced, assume caller calls free().\n */\nchar** permutation(char* S, int* returnSize) {\n \n}",
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"lang": "C#",
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"langSlug": "csharp",
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"code": "public class Solution {\n public string[] Permutation(string S) {\n \n }\n}",
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"lang": "JavaScript",
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"langSlug": "javascript",
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"code": "/**\n * @param {string} S\n * @return {string[]}\n */\nvar permutation = function(S) {\n \n};",
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"lang": "TypeScript",
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"langSlug": "typescript",
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"code": "function permutation(S: string): string[] {\n \n};",
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"lang": "PHP",
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"langSlug": "php",
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"code": "class Solution {\n\n /**\n * @param String $S\n * @return String[]\n */\n function permutation($S) {\n \n }\n}",
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"lang": "Swift",
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"langSlug": "swift",
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"code": "class Solution {\n func permutation(_ S: String) -> [String] {\n \n }\n}",
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"lang": "Kotlin",
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"langSlug": "kotlin",
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"code": "class Solution {\n fun permutation(S: String): Array<String> {\n \n }\n}",
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"lang": "Dart",
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"langSlug": "dart",
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"code": "class Solution {\n List<String> permutation(String S) {\n \n }\n}",
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"lang": "Go",
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"langSlug": "golang",
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"code": "func permutation(S string) []string {\n \n}",
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"lang": "Ruby",
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"langSlug": "ruby",
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"code": "# @param {String} s\n# @return {String[]}\ndef permutation(s)\n \nend",
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"lang": "Scala",
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"langSlug": "scala",
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"code": "object Solution {\n def permutation(S: String): Array[String] = {\n \n }\n}",
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"lang": "Rust",
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"langSlug": "rust",
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"code": "impl Solution {\n pub fn permutation(s: String) -> Vec<String> {\n \n }\n}",
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"lang": "Racket",
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"langSlug": "racket",
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"code": "(define/contract (permutation S)\n (-> string? (listof string?))\n )",
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"lang": "Erlang",
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"langSlug": "erlang",
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"code": "-spec permutation(S :: unicode:unicode_binary()) -> [unicode:unicode_binary()].\npermutation(S) ->\n .",
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"lang": "Elixir",
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"langSlug": "elixir",
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"code": "defmodule Solution do\n @spec permutation(s :: String.t) :: [String.t]\n def permutation(s) do\n \n end\nend",
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"lang": "Cangjie",
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"langSlug": "cangjie",
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"code": "class Solution {\n func permutation(S: String): Array<String> {\n\n }\n}",
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"stats": "{\"totalAccepted\": \"39K\", \"totalSubmission\": \"56.2K\", \"totalAcceptedRaw\": 39011, \"totalSubmissionRaw\": 56237, \"acRate\": \"69.4%\"}",
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"hints": [
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"你可以通过在打印之前检查是否有重复内容(或将它们添加到列表中)来处理此问题。你可以用散列表来做到这一点。在什么情况下,这样是可以的?在什么情况下,这可能不是一个很好的解法?",
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"如果你还没有解决8.7的问题,就先解决那个。",
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"试着获得每个字符的计数。例如,abcaac有3个a、2个c和1个b。",
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"要得到3个a、2个c和1个b的全排列,你首先需要选择一个起始字符:a、b或c。如果是a,那么你需要2个a、2个c和1个b的全排列。"
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],
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"sampleTestCase": "\"qqe\"",
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