leetcode-problemset/leetcode-cn/originData/pOCWxh.json

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        "question": {
            "questionId": "1000301",
            "questionFrontendId": "LCR 047",
            "categoryTitle": "Algorithms",
            "boundTopicId": 910295,
            "title": "二叉树剪枝",
            "titleSlug": "pOCWxh",
            "content": "<p>English description is not available for the problem. Please switch to Chinese.</p>\n",
            "translatedTitle": "二叉树剪枝",
            "translatedContent": "<p>给定一个二叉树 <strong>根节点</strong>&nbsp;<code>root</code>&nbsp;，树的每个节点的值要么是 <code>0</code>，要么是 <code>1</code>。请剪除该二叉树中所有节点的值为 <code>0</code> 的子树。</p>\n\n<p>节点 <code>node</code> 的子树为&nbsp;<code>node</code> 本身，以及所有 <code>node</code>&nbsp;的后代。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入:</strong> [1,null,0,0,1]\n<strong>输出: </strong>[1,null,0,null,1] \n<strong>解释:</strong> \n只有红色节点满足条件&ldquo;所有不包含 1 的子树&rdquo;。\n右图为返回的答案。\n\n<img alt=\"\" src=\"https://s3-lc-upload.s3.amazonaws.com/uploads/2018/04/06/1028_2.png\" style=\"width:450px\" />\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入:</strong> [1,0,1,0,0,0,1]\n<strong>输出: </strong>[1,null,1,null,1]\n<strong>解释:</strong> \n\n<img alt=\"\" src=\"https://s3-lc-upload.s3.amazonaws.com/uploads/2018/04/06/1028_1.png\" style=\"width:450px\" />\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入:</strong> [1,1,0,1,1,0,1,0]\n<strong>输出: </strong>[1,1,0,1,1,null,1]\n<strong>解释:</strong> \n\n<img alt=\"\" src=\"https://s3-lc-upload.s3.amazonaws.com/uploads/2018/04/05/1028.png\" style=\"width:450px\" />\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li>二叉树的节点个数的范围是 <code>[1,200]</code></li>\n\t<li>二叉树节点的值只会是 <code>0</code> 或 <code>1</code></li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><meta charset=\"UTF-8\" />注意：本题与主站 814&nbsp;题相同：<a href=\"https://leetcode-cn.com/problems/binary-tree-pruning/\">https://leetcode-cn.com/problems/binary-tree-pruning/</a></p>\n",
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                    "code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n *     int val;\n *     TreeNode *left;\n *     TreeNode *right;\n *     TreeNode() : val(0), left(nullptr), right(nullptr) {}\n *     TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}\n *     TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}\n * };\n */\nclass Solution {\npublic:\n    TreeNode* pruneTree(TreeNode* root) {\n\n    }\n};",
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                    "code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n *     int val;\n *     struct TreeNode *left;\n *     struct TreeNode *right;\n * };\n */\n\n\nstruct TreeNode* pruneTree(struct TreeNode* root){\n\n}",
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                    "code": "/**\n * Definition for a binary tree node.\n * function TreeNode(val, left, right) {\n *     this.val = (val===undefined ? 0 : val)\n *     this.left = (left===undefined ? null : left)\n *     this.right = (right===undefined ? null : right)\n * }\n */\n/**\n * @param {TreeNode} root\n * @return {TreeNode}\n */\nvar pruneTree = function(root) {\n\n};",
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                    "code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n *     val: number\n *     left: TreeNode | null\n *     right: TreeNode | null\n *     constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {\n *         this.val = (val===undefined ? 0 : val)\n *         this.left = (left===undefined ? null : left)\n *         this.right = (right===undefined ? null : right)\n *     }\n * }\n */\n\nfunction pruneTree(root: TreeNode | null): TreeNode | null {\n\n};",
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                    "code": "/**\n * Definition for a binary tree node.\n * type TreeNode struct {\n *     Val int\n *     Left *TreeNode\n *     Right *TreeNode\n * }\n */\nfunc pruneTree(root *TreeNode) *TreeNode {\n\n}",
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