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"questionId": "1305",
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"categoryTitle": "Algorithms",
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"title": "Number of Visible People in a Queue",
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"content": "<p>There are <code>n</code> people standing in a queue, and they numbered from <code>0</code> to <code>n - 1</code> in <strong>left to right</strong> order. You are given an array <code>heights</code> of <strong>distinct</strong> integers where <code>heights[i]</code> represents the height of the <code>i<sup>th</sup></code> person.</p>\n\n<p>A person can <strong>see</strong> another person to their right in the queue if everybody in between is <strong>shorter</strong> than both of them. More formally, the <code>i<sup>th</sup></code> person can see the <code>j<sup>th</sup></code> person if <code>i &lt; j</code> and <code>min(heights[i], heights[j]) &gt; max(heights[i+1], heights[i+2], ..., heights[j-1])</code>.</p>\n\n<p>Return <em>an array </em><code>answer</code><em> of length </em><code>n</code><em> where </em><code>answer[i]</code><em> is the <strong>number of people</strong> the </em><code>i<sup>th</sup></code><em> person can <strong>see</strong> to their right in the queue</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/05/29/queue-plane.jpg\" style=\"width: 600px; height: 247px;\" /></p>\n\n<pre>\n<strong>Input:</strong> heights = [10,6,8,5,11,9]\n<strong>Output:</strong> [3,1,2,1,1,0]\n<strong>Explanation:</strong>\nPerson 0 can see person 1, 2, and 4.\nPerson 1 can see person 2.\nPerson 2 can see person 3 and 4.\nPerson 3 can see person 4.\nPerson 4 can see person 5.\nPerson 5 can see no one since nobody is to the right of them.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> heights = [5,1,2,3,10]\n<strong>Output:</strong> [4,1,1,1,0]\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == heights.length</code></li>\n\t<li><code>1 &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= heights[i] &lt;= 10<sup>5</sup></code></li>\n\t<li>All the values of <code>heights</code> are <strong>unique</strong>.</li>\n</ul>\n",
"translatedTitle": "队列中可以看到的人数",
"translatedContent": "<p>有&nbsp;<code>n</code>&nbsp;个人排成一个队列,<strong>从左到右</strong>&nbsp;编号为&nbsp;<code>0</code>&nbsp;到&nbsp;<code>n - 1</code>&nbsp;。给你以一个整数数组&nbsp;<code>heights</code>&nbsp;,每个整数 <strong>互不相同</strong><code>heights[i]</code>&nbsp;表示第&nbsp;<code>i</code>&nbsp;个人的高度。</p>\n\n<p>一个人能 <strong>看到</strong> 他右边另一个人的条件是这两人之间的所有人都比他们两人 <strong>矮</strong>&nbsp;。更正式的,第&nbsp;<code>i</code>&nbsp;个人能看到第&nbsp;<code>j</code>&nbsp;个人的条件是&nbsp;<code>i &lt; j</code>&nbsp;且&nbsp;<code>min(heights[i], heights[j]) &gt; max(heights[i+1], heights[i+2], ..., heights[j-1])</code>&nbsp;。</p>\n\n<p>请你返回一个长度为 <code>n</code>&nbsp;的数组<em>&nbsp;</em><code>answer</code><em>&nbsp;</em>,其中<em>&nbsp;</em><code>answer[i]</code><em>&nbsp;</em>是第&nbsp;<code>i</code>&nbsp;个人在他右侧队列中能&nbsp;<strong>看到</strong>&nbsp;的&nbsp;<strong>人数</strong>&nbsp;。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/05/29/queue-plane.jpg\" style=\"width: 600px; height: 247px;\" /></p>\n\n<pre>\n<b>输入:</b>heights = [10,6,8,5,11,9]\n<b>输出:</b>[3,1,2,1,1,0]\n<strong>解释:</strong>\n第 0 个人能看到编号为 1 2 和 4 的人。\n第 1 个人能看到编号为 2 的人。\n第 2 个人能看到编号为 3 和 4 的人。\n第 3 个人能看到编号为 4 的人。\n第 4 个人能看到编号为 5 的人。\n第 5 个人谁也看不到因为他右边没人。\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<b>输入:</b>heights = [5,1,2,3,10]\n<b>输出:</b>[4,1,1,1,0]\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>n == heights.length</code></li>\n\t<li><code>1 &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= heights[i] &lt;= 10<sup>5</sup></code></li>\n\t<li><code>heights</code>&nbsp;中所有数 <strong>互不相同</strong>&nbsp;。</li>\n</ul>\n",
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"hints": [
"How to solve this problem in quadratic complexity ?",
"For every subarray start at index i, keep finding new maximum values until a value larger than arr[i] is found.",
"Since the limits are high, you need a linear solution.",
"Use a stack to keep the values of the array sorted as you iterate the array from the end to the start.",
"Keep popping from the stack the elements in sorted order until a value larger than arr[i] is found, these are the ones that person i can see."
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